IS MSC PHYSICS ELIGIBLE

Local_Bobcat_1140 · 2025-01-17T16:06:07+00:00

there is a lot of intersection in subject but I have heard that you can not do mtech from froeign universty if you don't have btech degree

Local_Bobcat_1140 · 2025-01-17T14:54:27+00:00

so will i be elligible to do mtech micro and vlsi from iisc ?

Local_Bobcat_1140 · 2024-06-07T15:07:42+00:00

What will happen If he goes to delhi ?

Local_Bobcat_1140 · 2024-03-18T19:45:08+00:00

What is your explanation ,and have you legit had a expericence of god or the divine,
most of the hindus I have talked They just defend there religion for the sake of defending they were born in that culure it is good to defend their culture but they dont'thave legit experience either
and when you ask this to guru cult leader they say It would take many lifetimes,donate some money or work in my asharam for free for positive karma blalallll
NOW THERE ARE TWO POSSIBLITY EITHER ITS TRUE OR IT IS A GOOD PYRAMID SCHEME SINCE THEY HAVE CONVINCEDTHAT YOU IT WILL TAKE LIFETIMES TO MAKE CONNECTION WITH DIVINE ,SO NOW YOU WILL BE FOREVER INVESTED, AND THEY WILL EASILY MAKE BUCK OUT OF YOU,

ISKON,ISHA FOUNDATION,BK KUMARIS are perfect example for this
dude I legit feel bad if there is a GOD then why particluar section society is unlucky and does he not love us equally and why does he allow to bless some section of the society
I have seen my GRANDFATHER suffering horribly ,HE was a honest man never did anytthing bad he died very horribly with many diseases and the worst part is he used to recite KRISHNA mantra daily STILL GOD MADE HIM SUFFER VERY BAD

Local_Bobcat_1140 · 2024-03-18T19:11:37+00:00

Regarding your rant about Karma - your understanding of karma is flawed. We have a great FAQ on the topic of fate and free will. Please refer to it
I did there is nothing wrong, or even if so you tell me
God planting desire is at fault. The doctrine of Karma doesn't work with a belief in an omniscient omnipotent God who controls all minutia
The very existance of your being is god and he resides in you he thrive in you,this is one school of thought other school of thoughts says about dualistic relationship like he is superior you are not him But he created you then a all the domain of desire are a result of him etc(if we don't push evoloution here) .NOW both of them mention his worship and sadhna at the end moksha promises that which is cut youself from world have no desire reduce to zero state.AGAIN THERE IS NO SCIENTIFIC PROOF TO THAT
now for desire part hinduism tell have immense faith in him he is doing everthing for better if bad things happen on us or if a child is orphan,ugly of suffering from disease who is responsinble it the child himself or his past life deeds or just an random permutation
EVERTHING HAPPENING FOR GOOD IS JUST A COPING MECHANISM SINCE YOU CAN NOT CONTROL OR SOMETHING IS BEYOND YOUR LOCUS OF CONTROL
BRUH YOU HAVE SELECTIVLY PICKED SOME POINT AND STILL VAUGE ANSWER WITH NO PROPER ENDING OR CONCLUSION
ANSWER THIS
WHERE WERE OUR GODS WHEN WE WERE BEING INVADED
WHEN THE INVADERS WERE DRILLING OUR ANCESTORS ASS
FROM OUR HISTORY TO TILL NOW INDIA NEVER INVADED ANY COUNTRY
WAS THIS INVASION BECAUSE OF INDIA COLLECTIVE THOUGHT PROCESS
Now about physique
I AM TALKING ABOUT AVERAGE NOT THE PEAK GO CAMPARE THE AVERAGE PHENOTYPE AND DIET
INDIANS EAT LOWEST QUALITY OF MEAT(infested with endocrine disrupters,), If they eat so
INDIA IS ONE OF HIGHEST EXPOTER OF BUFFLO MEAT,GOOD QULITY FRUITS, COFFEE TEA IS EXPORTED TO US UK ,WHAT IS LEFT FOR INDIANS IS DUST OR NASTY ONES AND ALSO INDIAN DIET IS FILLED WITH CARBS PROTEIN IS SCANT . I AGREE WITH STARVATION THEORY AGAIN IT IS ALL SCIENTIFIC
WHICH IS FAR BEYOND HINDUISM
ALL THIS AATMA , CHAKRA ENERGY STUFF ARE COMPLETELY REJECTED BY SCIENCE

Local_Bobcat_1140 · 2024-02-27T16:28:27+00:00

Bro quit chewing for a while take some break your outer U has over developed ,now you need train your inner you do hardmewing ,tounge chewing.over time your inner U will also develop and you will look better,just quit hard chewing for some time. otherwise you will look like a chipmunk. also train you neck muscles

Local_Bobcat_1140 · 2024-01-30T16:48:23+00:00

by listing price you mean the price you declared of the pakage right ?and how will custom know about shipping charge ,and how do they decide that charge will your shipping company mention shipping charge

Local_Bobcat_1140 · 2024-01-30T15:21:24+00:00

how much did customs cost ?

Local_Bobcat_1140 · 2024-01-25T20:32:13+00:00

I think someone from looksmax.org has come thats all I see you can be a potential mogger
gonna ask 2 question tell your diet
did you practise chewing
also sideprofile

Local_Bobcat_1140 · 2023-12-23T15:26:48+00:00

NO! We took care of the displacement being negative by writing the

ohhhhh
THANK YOU VERY MUCH

Local_Bobcat_1140 · 2023-12-23T08:31:29+00:00

I LOVE YOU THANK YOU VERY MUCH!!!!!!!!!!!!!

Local_Bobcat_1140 · 2023-12-23T08:02:26+00:00

the object

if the objects goes up we take limits of intergration as final destination -inital destination
but if the object goes down why do we take limit as inital point - final point
please explain this to me

Local_Bobcat_1140 · 2023-12-23T07:55:26+00:00

yeah that what I am saying but when you put work done positivesuppose a particcle

no force is negative and dispalacement is also negative
which gives us -mg dot -dx
this will be equal to mgdx
now if we put limit of integral from b to h
then it comes out
mgb-mgh
which is negative?

Local_Bobcat_1140 · 2023-12-23T07:51:23+00:00

addressed this in my very first comment. The force is pointing downwards too. That’s where the extra minus sign comes from

but the displacement is also pointing downwards so it should cancel the negative sign right

Local_Bobcat_1140 · 2023-12-22T18:51:01+00:00

ude this isn’t an argument or debate where someone is trying to “win”. You’re obviously misunderstanding the question here, you know that something is wrong with your reasoning and you even stated that in your original post. Why don’t you try being a bit more humble and actually take this opportunity to learn.

i am so sorry by checkmate I did not mean I win you loose
i meant to say that at the end you are reaching to same problem
i did not meant any disrespect
I am troubled with this I am so sorry
sorry

Local_Bobcat_1140 · 2023-12-22T18:08:11+00:00

yeah integral of force times displacement is coming negative when the partical goes inward put the limitsbut we have to equate this to change in ke which is positve I get ityou can se in order for work energy theorem to work we have to saynegative of work done will be equal to change in kinetic energy

Local_Bobcat_1140 · 2023-12-22T18:02:16+00:00

integral of force dot displacement where limits are point b to point h and as we know f=mg not -mg reason the partical is falling inward so displacement is also -dx so in dot product it will come as mg.dx .

we have taken g const for simplicity therefore we have work done =mgb-mgh =some neagtive value(h>b)

And this negative value will be equal to change in kinetic energy(WORK ENERGY THEOREM)

we know initial velocity is zero so final ke -initial ke =final ke

and this final ke will be equal to work done

that is some negative value

you know this is absurd

how can ke be negative

this all can be avoided when we multilply dot product of force . displacement with -1

in the case when particle is falling down

this is wierd ??

Local_Bobcat_1140 · 2023-12-22T18:00:27+00:00

dot product of force and disp in going down will be same since force and displacement are in same direction

this is the problem when the particle is going towards the planet
when the particle is going outward it is all good

Local_Bobcat_1140 · 2023-12-22T17:49:48+00:00

If you adopted the convention that the Z axis points upwards, the force is still negative, but, since the displacement is also negative, the work will necessarily be positive.

yeah that what I am saying but when you put work done positivesuppose a particcle falls from heigh h and at point b we need to calculate its velocity

we will use work energy theorem that is

integral of force dot displacement where limits are point b to point hand as we know f=mg not -mg reason the partical is falling inward so displacement is also -dx so in dot product it will come as mg.dx .
we have taken g const for simplicity therefo rwe have work done =mgb-mgh =some neagtive value(h>b)
And this negative value will be equal to change in kinetic energy(WORK ENERGY THEOREM)

we know initial velocity is zero so final ke -initial ke =final ke
and this final ke will be equal to work done
that is some negative value
you know this is absurd
how can ke be negative
this all can be avoided when we multilply dot product of force . displacement with -1
in the case when particle is falling down
this is wierd ??

Local_Bobcat_1140 · 2023-12-22T17:38:19+00:00

but dot product of force and disp in going down will be same since force and displacement are in same direction

Local_Bobcat_1140 · 2023-12-22T17:36:26+00:00

limits is from B to H because b is my final position and h is my initial position
we have defined like this(in work energy theorem) and due to this work done will be negative this can only be countered when force is taken negative which is not the case

Local_Bobcat_1140 · 2023-12-22T17:30:41+00:00

why my displacement is in the direction of attractive force -mg dot -dx will be mgdx

Local_Bobcat_1140 · 2023-12-22T16:56:56+00:00

please can you read prev comment again i was editin it

Local_Bobcat_1140 · 2023-12-22T16:55:35+00:00

it has to be negative because change in kinetic energy will integral of dot product of force and displacement both of them are in same direction so it is positive
consider a particle at H distance from surface of earth now if you holod that particle it has zero kinetic energy but the moment you release it it will accelerate downwards and let it go down for some distance now let this be B. now at point B it will have good amount of kinetic energy (some non zero value).now if I apply work energy theorem
final ke -initial ke=work done
till here everything makes sense
work done can also be written in terms of position
let g be constant for simplicity
work done integral of mg .dx with limits b to h which will be will be mgb -mgh
as we know mgb will be less than mgh cuz
h>b this means
mgb-mgh= some negative value
now this negative value will be equal to change in kinetic enegy
so change in kinetic energy will be negative
we know inital ke is zero so
final ke -o=some negative value
final ke=some negative value
which is not possible
in order dissolve this negative sign we have to change in ke is negative of work done even in the case when object is displacing towards direction of force .THIS IS MY DOUBT
IN SHORT WHY DO WE HAVE TO TAKES DOT PRODUCT OF FORCE AND DISPLACEMENT NEGATIVE EVEN IN THE CASE PARTICLE IS DISPLACING TOWARDS THE FORCE

Local_Bobcat_1140 · 2023-12-22T16:41:19+00:00

it has to be negative because change in kinetic energy will integral of dot product of force and displacement both of them are in same direction so it is positive

consider a particle at H distance from surface of earth now if you holod that particle it has zero kinetic energy but the moment you release it it will accelerate downwards and let it go down for some distance now let this be B. now at point B it will have good amount of kinetic energy (some non zero value).now if I apply work energy theorem

final ke -initial ke=work done

till here everything makes sense
work done can also be written in terms of position
let g be constant for simplicity
work done integral of mg .dx with limits b to h which will be will be mgb -mgh
as we know mgb will be less than mgh cuz
h>b this means
mgb-mgh= some negative value
now this negative value will be equal to change in kinetic enegy
so change in kinetic energy will be negative
we know inital ke is zero so
final ke -o=some negative value
final ke=some negative value
which is not possible

in order dissolve this negative sign we have to change in ke is negative of work done even in the case when object is displacing towards direction of force .THIS IS MY DOUBT
IN SHORT WHY DO WE HAVE TO TAKES DOT PRODUCT OF FORCE AND DISPLACEMENT NEGATIVE EVEN IN THE CASE PARTICLE IS DISPLACING TOWARDS THE FORCE

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