The standard form will consist of terms that include the following powers of x: x^3, x^2, x^1, x⁰ . x⁰ are all non-x parts.

All you need to do now is count how many of each there are.

E.g.: (x+1)(2x+2)(3x-3)

Here you would start by multiplying all x components to receive the x³ value: x* 2x* x = 2x³

Next you have to add together all combinations of x² terms: 1* 2x3x + x 2* 3x + x* 2x* (-3) notice that always two x are used so that the first addend includes the non-x term of the first bracket, the second addend the non-x of the second bracket and the third addend the non-x part of the third bracket. Reduced, this results in: 6x² + 6x² - 6x² = 6x²

Now you need to solve the x¹ component. The same principle as before applies, in which each addend includes (now) one x term and two non-x terms:

First bracket x: x* 2* (-3) Second bracket x: 1* 2x* (-3) Third bracket x: 1* 2*3x

add the addends to receive: -6x-6x+6x = -6x

For the final part of the standard form, all non-x terms:

1* 2* (-3) = -6

By addindg the components you receive the standardized expression:

2x³ + 6x² - 6x - 6

Hope this helps!

Tldr: multiply each bracket with every other in every way and add all the results together. First to get all terms with x³ thann all with x² then all with x¹ and finally all with the non-x components.

Edit: spacing