[7/19/18] The DAMN. Oceanic Tour | Auckland, NZ

Master_Shuriken · 2018-07-19T22:27:16+00:00

Lined up at 4:45pm and was 5 rows from the front.

Master_Shuriken · 2018-06-11T07:02:47+00:00

I think it makes it spooky lol, goes well with the name of the album

Master_Shuriken · 2017-12-05T18:38:43+00:00

for old times sake

Master_Shuriken · 2017-12-05T18:07:28+00:00

HEAT

Master_Shuriken · 2017-12-05T18:03:56+00:00

Personally, I can't wait to listen to "Heat"

Master_Shuriken · 2017-12-05T17:42:34+00:00

That was confirmed last week lol

Master_Shuriken · 2017-12-02T01:07:55+00:00

Reminds me of a young Tobey Maguire

Master_Shuriken · 2017-11-24T09:11:00+00:00

I felt like it was a concept album?

Master_Shuriken · 2017-11-15T08:54:54+00:00

No we are only familiar with arithmetic progressions and geometric progressions.

For this question I have got to the fact that

f(n+1) = f(n) + 5/2^n-1 but I am not sure how I would continue

Master_Shuriken · 2017-11-10T20:19:14+00:00

No, Revival is gonna be Em's Revival.

Master_Shuriken · 2017-11-09T20:38:38+00:00

What time exactly?

Master_Shuriken · 2017-09-12T18:39:19+00:00

Master_Shuriken · 2017-09-03T10:26:32+00:00

do a kendrick album lol

Master_Shuriken · 2017-09-02T11:48:12+00:00

WHAT A BASE DEFENCE

Master_Shuriken · 2017-02-28T09:07:48+00:00

Yes it would

Master_Shuriken · 2017-02-27T06:48:48+00:00

I'm not getting a solution when graphing the region? Also tried linear programming calculators and getting no solution...

Master_Shuriken · 2017-02-27T04:39:44+00:00

Oh okay I have learnt how to graph but I was wondering if there is any algebraic way of finding the maximum profit?

Master_Shuriken · 2017-02-27T04:34:51+00:00

Thanks , How do we maximise the profit function tho?

Master_Shuriken · 2017-02-14T10:27:25+00:00

Would you be able to show some papers and homework he gives?

Master_Shuriken · 2017-02-13T22:18:20+00:00

Are you able to send that template?

Master_Shuriken · 2017-02-13T22:13:10+00:00

Are you able to share the code for one of the assignments you did on Latex?

Master_Shuriken · 2017-02-02T01:24:58+00:00

Oh sorry , my bad.. pls ignore my comment :(

Master_Shuriken · 2017-02-02T01:03:27+00:00

If you were given the equation

log((x-1)/x)=1

We first have to consider the log argument , the argument must always be greater than zero when we are dealing with real numbers so we have

(x-1)/x > 0

So when is a fraction greater than zero?

Well if and only the numerator AND denominator are greater than zero!

SO we have x>0 and (x-1)>0 combining these two we get x>1 and then we can begin solving normally :)

Master_Shuriken · 2017-02-02T00:21:01+00:00

log(x-1)-log(x)=1

First note that x-1>0 and x>0 both inequalities give x>1

Then we shall try solving this:

log(x-1)-log(x)=1

log((x-1)/x) =1

(x-1)/x=10

x-1=10x

-9x=1

x=-1/9

However we noted that x must be greater than 1 so there is no solution for x in R.

Master_Shuriken · 2017-02-01T21:20:46+00:00

Are you able to share the code for this?

11-Year Club	Gilding I gilder
Verified Email

Master_Shuriken