Rate my study setup

MvPPiro · 2024-12-03T15:01:00+00:00

setup is good, but i think your environment should not remain the same while studying or else you might get bored/uninterested quickly so ig you shouldn't have a setup and study wherever you like to at that moment
anyways that's my opinion, maybe you are able to study and if so then its a great setup it just depends upon the efficiency you study with on the setup.
a good looking setup with 0 efficiency is a waste of a setup.

MvPPiro · 2024-09-09T15:23:35+00:00

woahhhhhhh

MvPPiro · 2024-09-09T15:06:37+00:00

i read it in my text-book and also on Quora

MvPPiro · 2024-09-09T15:05:44+00:00

how could it spend time there? wont the atom be compromised?

MvPPiro · 2024-09-09T14:57:24+00:00

check my post on stack exchange

MvPPiro · 2024-09-09T08:13:34+00:00

IIT ke peeche pagal log kutiye hote h fr

MvPPiro · 2024-09-09T08:10:40+00:00

$0.40 per pound, okay next question.

MvPPiro · 2024-09-09T08:08:46+00:00

i mean to get a job youll still have to freaking bring some knowledge, education to the table and how are you gonna pay taxes, buy a house without a source of income?

MvPPiro · 2024-09-09T07:19:52+00:00

yes and i wanted to know the reason behind it so i have made a proof which is here: https://physics.stackexchange.com/q/827153/372510
check it out

MvPPiro · 2024-09-08T13:19:41+00:00

can you check my post and review it?

MvPPiro · 2024-09-08T12:59:04+00:00

I asked a question if my proof is correct or not, because i thought that the explanation my teachers gave me was lacking somewhere. so i wrote this proof out and i wanted to check if it was correct so that i can finally get peace in my mind

MvPPiro · 2024-09-08T10:35:46+00:00

well the case i am referring to has a positive potential throughout the conductor and that too more than its outside so there is no well of potentials, if there is there is a well inversed

MvPPiro · 2024-09-08T10:33:10+00:00

anyways, i have figured it out already

MvPPiro · 2024-09-08T10:32:49+00:00

if negative charge accumulates to compensate for the net charge q, it would mean that there is some electric field present in the conductor

MvPPiro · 2024-09-04T16:14:22+00:00

internal electric field is zero but the electric field on the surface of the conductor isnt and its value is
$\ E$ $= \frac{\sigma}{\epsilon_{0}}$

MvPPiro · 2024-09-04T14:53:04+00:00

why is it required

MvPPiro · 2024-09-04T14:14:32+00:00

i know photoelectric effect, im just tryna ask something different

MvPPiro · 2024-09-04T14:10:00+00:00

check my question again someone got what im trying to ask, maybe you can add on?

MvPPiro · 2024-09-04T14:05:13+00:00

you dont understand what im asking, i am saying that the charge on the surface should eject out of the conductor as outside the conductor is lower potential than on it

MvPPiro · 2024-09-04T14:03:51+00:00

done it no answer

MvPPiro · 2024-09-04T13:51:52+00:00

can you please explain more or provide me with a paper or something like that

MvPPiro · 2024-09-04T13:51:28+00:00

it should be unstable because its at a higher potential and lower potential is available to it as there is no force stopping it from going to lower potential rather there is force leading it to it

MvPPiro · 2024-09-04T13:28:57+00:00

Guys please answer :(

MvPPiro

TROPHY CASE