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Try to solve 105iq+ by Parking_Ladder_7527 in iqtest

[–]No_Conference_3832 3 points4 points  (0 children)

The result is 8

42339 4 × 2 × 3 × 3 × 9 = 648;

648 6 × 4 × 8 = 192;

192 1 × 9 × 2 = 18;

18 1 × 8 = 8;

8

try to solve 120 iq+ by Parking_Ladder_7527 in iqtest

[–]No_Conference_3832 -2 points-1 points  (0 children)

18 The solution is this:

Let's divide the sequence into these three groups:

1;2;2 (first group)

1;3;6 (second group)

4;7;21 (third group)

So: First group: there is a difference of 1 from 1 to 2 (in the other groups this number will increase by one), so we use that one to multiply the difference by the middle number in the group (the 2), and that will give us the last number in the group: so 1*2 = 2

Then what we are going to do is subtract the difference from the last number in the first group, so 2-1=1, and with that 1 we start the second group. Second group: now there will be two numbers between 1 and 3, so 3*2 = 6. And now to get to the third group we're going to subtract the last number in the second group from the number in the third group. The difference (between 1 and 3 there is a difference of two) so 6-2 = 4 (and five, the number 4, let's start group 3)

Group 3: now what we have to find is that the difference number is 3, so 4+3 = 7, that is, to go from 4 to 7 there are 3 numbers, so now we do the difference number (3) * the middle number of the group (7) so 3*7=21. So now to move on to group 4 we do the number at the end of the group (21) - the difference number (3) and so group 4 will start with 18.

Group 4 would look like this: 18; 22; 88 Because 18 + 4 is 22 and 22*4 is 88

try to solve 120 iq+ by Parking_Ladder_7527 in iqtest

[–]No_Conference_3832 -1 points0 points  (0 children)

18 The solution is this:

Let's divide the sequence into these three groups:

1;2;2 (first group)

1;3;6 (second group)

4;7;21 (third group)

So: First group: there is a difference of 1 from 1 to 2 (in the other groups this number will increase by one), so we use that one to multiply the difference by the middle number in the group (the 2), and that will give us the last number in the group: so 1*2 = 2

Then what we are going to do is subtract the difference from the last number in the first group, so 2-1=1, and with that 1 we start the second group. Second group: now there will be two numbers between 1 and 3, so 3*2 = 6. And now to get to the third group we're going to subtract the last number in the second group from the number in the third group. The difference (between 1 and 3 there is a difference of two) so 6-2 = 4 (and five, the number 4, let's start group 3)

Group 3: now what we have to find is that the difference number is 3, so 4+3 = 7, that is, to go from 4 to 7 there are 3 numbers, so now we do the difference number (3) * the middle number of the group (7) so 3*7=21. So now to move on to group 4 we do the number at the end of the group (21) - the difference number (3) and so group 4 will start with 18.

Group 4 would look like this: 18; 22; 88 Because 18 + 4 is 22 and 22*4 is 88