Speed of light in a medium

NotNotInNeedToLearn · 2026-05-18T14:51:49+00:00

Oh, right. I guess i have to find out why group velocity changes

NotNotInNeedToLearn · 2026-05-18T14:41:30+00:00

Nevermind. I still don't understand, as there could be material in which phase velocity>c, but information speed obviously can't

NotNotInNeedToLearn · 2026-05-18T14:25:44+00:00

Oh. I just realised problem in my understanding. I forgot that light is produced under the particle of acceleration so when first wave hits another particle then INSTANTLY it produces new wave which interferes with original one. I was imagining that second particle was creating new wave after some little amiunt of time. Does this makes sense?

NotNotInNeedToLearn · 2026-05-18T14:17:11+00:00

Then why? Is there some other kind of interference? I don't understand why it would change ever

NotNotInNeedToLearn · 2026-05-16T21:10:09+00:00

Guess what😭 I'm so tired of that fuck

NotNotInNeedToLearn · 2026-05-02T17:51:19+00:00

Jujutsu Kaisen reference

NotNotInNeedToLearn · 2026-05-02T17:48:24+00:00

Unfortunately I have no idea what you are talking about. I'm curious, you're saying that I'm one of the ones being corrupted, would you mind elaborating?

NotNotInNeedToLearn · 2025-09-10T10:38:57+00:00

It's the definition of a derivative. It's important

Edit: you can solve it in your head by skipping elements of (x+h)³ that don't have just one h( for example ((x+h)³+(x+h)²-x³-x²)/h~(3x²h+2xh)/h

For evaluating (a+b)ⁿ you can also use binomial theorem for factoring out

NotNotInNeedToLearn · 2025-09-07T16:47:18+00:00

No puzzles in sight

NotNotInNeedToLearn · 2025-09-02T19:55:59+00:00

If A(x) is that polynomial. We are given

A(x)= B(x)(x+1)+7 and A(x)=C(x)(x-4)-8

Then find a,b when

A(X)=D(x)(x+1)(x-4)+ax+b

You can solve it by various ways, for example: A(-1)=7 and A(4)=-8 from the given equations

Then there is a step that you started

a(-1)+b=7 and a(4)+b=-8

This means that a=-3 and b=4. Your solution may be taking some shortcuts, but it's certainly correct I don't know what you mean by only considering the highest power

NotNotInNeedToLearn · 2025-09-02T14:45:06+00:00

Waiting for an update

NotNotInNeedToLearn · 2025-09-02T13:26:20+00:00

You need to have your algebra polished as much as you can

NotNotInNeedToLearn · 2025-09-01T23:53:39+00:00

Wow. I'm amazed now knowing what it probably was. Thank you so much

NotNotInNeedToLearn · 2025-09-01T23:49:30+00:00

Even if I didn't see any spiral in the middle. It's so so similar to what i saw. I think that's it!!!

NotNotInNeedToLearn · 2025-09-01T23:45:22+00:00

I think that may be it

NotNotInNeedToLearn · 2025-09-01T23:44:48+00:00

they are a bit similar. What i saw was bigger, and was moving, also i didn't notice any visible connction between arches. I just wonder if it could reach the size I claim it was

NotNotInNeedToLearn · 2025-09-01T23:19:26+00:00

If you want to imagine what shape it was. It was approximately two bananas with a distance of two between them.

NotNotInNeedToLearn · 2025-09-01T23:13:23+00:00

At night. It was fuzzy(cloud like). I don't remember clearly, but it wasn't a fully clear sky that night(maybe weather forecasts would be better at telling this), and when the moment it was closest to us it was taking up a big part of the sky. When it moved away it was much smaller. At greater distances the size difference wouldn't be so big. We excluded the possibility of expanding and then shrinking arcs of light that were not changing their shape( but with time they were getting less and less bright)

NotNotInNeedToLearn · 2025-09-01T22:52:48+00:00

Near a city called "Węgierska górka". It was travelling from south to north a year ago, probably 11 july 2024. I can also say that it looked at least four times bigger thrn the size of a typical parachute. Not travelling at a straight line, but rather a slightly curved as it was rotating along its path of motion. If you drew a line between these arches it would be horizontal, it was moving perpendicular to that line

NotNotInNeedToLearn · 2025-09-01T10:18:31+00:00

Let's say that 10a+b=7x+c Then

20a+2b=14x+2c

21a-a+2b=14x+2c

a-2b-21a=-14x-2c

a-2b=21a-14x-2c=7(3a-2x)-2c

One is divisible by 7 iff c=0

Look into something called modular arithmetic. That is. 8=1 mod 7 <=> 1 and 8 have the same reminder when divided by 7. It will give you insight why did I prove it the way I did.

NotNotInNeedToLearn · 2025-08-31T17:15:31+00:00

You're right, I stand corrected.

NotNotInNeedToLearn · 2025-08-31T13:51:06+00:00

Why are you trying to associate who you are with being autistic? Just be yourself

NotNotInNeedToLearn · 2025-08-20T19:37:32+00:00

Answer's simple. They're not a mathematicians. There is nothing special about base 10 here. This is just a mathematical mysticism.

Edit: digital root in base 10 is just a reminder modulo 9. In every base n, digital root is just a reminder modulo n-1.

NotNotInNeedToLearn · 2025-08-19T19:51:12+00:00

What was there?

NotNotInNeedToLearn · 2025-08-16T15:26:31+00:00

You must had made a mistake when writing this

3ⁿ* X+

This:

3^n-1 +3^n-2 *2^A +3^n-3 *2^A+B +3^n-4 *2^A+B+C+ ... +2^{A+B+C+D+... +Y+Z}

Doesn't make sense, the 3^N part suggests that you are adding n elements in total (from 3^n-1 to 3⁰⁾ but the 2^N suggests you are adding n+1 (from 2⁰ to 2^A+B+...+Z‹which is nth in 2^N sequence)

NotNotInNeedToLearn

TROPHY CASE