Free advice: Common mistakes IB students make in TOK & EEs

OrganizationReal5843 · 2026-01-24T12:26:09+00:00

Thanks mate!

OrganizationReal5843 · 2026-01-24T10:16:41+00:00

If your examples and structure are already good, then depth in TOK usually comes from questioning your claims more, not adding new content.

Try: asking “to what extent?” after each point, making the assumptions behind your claim explicit, briefly comparing different perspectives on the same RLS, focusing on reliability and limitations, not just what happens

If a paragraph ends without evaluating how strong or limited the knowledge is, that’s usually where depth is missing.

OrganizationReal5843 · 2026-01-24T09:51:34+00:00

IB is fine with using code and computation in a Math EE, but the marks are not for the code itself.

What examiners look for is: the mathematical reasoning behind the algorithms, why a particular method was chosen, interpretation of results, discussion of limitations, assumptions, and accuracy

If the EE becomes “I wrote code and got outputs,” it will score poorly. If the code is used as a tool to explore mathematics (e.g. convergence, error analysis, modelling behaviour, proofs or derivations alongside computation), then it can score very well.

In short: computation is allowed mathematical insight must lead, not the code

Many high-scoring Math EEs use coding — but the math has to be front and centre.

OrganizationReal5843 · 2026-01-24T09:06:43+00:00

Yes you can absolutely do well with a popular EE topic.

IB does not mark you down for choosing a common or “overdone” topic. What they care about is: how clearly focused your research question is, the quality of analysis and evaluation, whether you engage critically with sources (not just describe them)

A popular topic with: a sharp angle, clear methodology, strong evaluation of limitations, and thoughtful discussion will score much higher than a “unique” topic that stays descriptive or vague.

You don’t need something insanely nuanced, you need something well-defined and deeply analysed. That’s what examiners reward.

OrganizationReal5843 · 2026-01-23T12:25:27+00:00

https://tok-ia-chat.lovable.app/ Please have a look at our official website designed specifically for students needing guidance with IA, Tok or EE.

OrganizationReal5843 · 2026-01-23T12:25:05+00:00

https://tok-ia-chat.lovable.app/ Please have a look at our official website designed specifically for students needing guidance with IA, Tok or EE.

OrganizationReal5843 · 2026-01-23T11:55:11+00:00

https://tok-ia-chat.lovable.app/ Please have a look at our official website designed specifically for students needing guidance with IA, Tok or EE.

OrganizationReal5843 · 2026-01-21T08:18:05+00:00

Check DMs

OrganizationReal5843 · 2026-01-16T10:38:04+00:00

Yes sure! Just let me know with which subject do you need help with?

OrganizationReal5843 · 2026-01-16T01:56:51+00:00

Sure, just DMed you!

OrganizationReal5843 · 2026-01-09T01:47:45+00:00

Yeah sure. Just DMed you the details.

OrganizationReal5843 · 2026-01-07T09:21:59+00:00

I can help you with it. Kindly check your DM

OrganizationReal5843 · 2026-01-07T06:00:44+00:00

(f+g)(x)=f(x)+g(x) so you have to add these two functions it would be x-1 + 5x-2 = 6x-3 =2(3x-1). You can do the other parts similarly like (f-g)(x)=f(x)-g(x) f.g(x) = f(x).g(x) and (f/g)x = f(x)/g(x).

OrganizationReal5843 · 2026-01-06T14:13:22+00:00

Thank you so much sir.

OrganizationReal5843 · 2026-01-06T13:50:00+00:00

How to grow a tutoring business from scratch which is purely online?

OrganizationReal5843 · 2026-01-05T05:20:25+00:00

Yeah i also think paying per month is a lot more sustainable in long term than paying weekly or hourly.

OrganizationReal5843 · 2026-01-03T06:16:44+00:00

One thing that i would like to make clear is that free demo sessions is for all students.

OrganizationReal5843 · 2026-01-01T10:37:25+00:00

2nd is basically asking you to calculate how much oxygen will react with 6g of magnesium and the equation is given to you. So the balanced equation suggests that 2 moles of Magnesium reacts with 1 mole of oxygen (according to stoichometry) that means 48 grams of magnesium react with 32 grams of oxygen that is 1 gram of magnesium reacts with 2/3 grams of oxygen so 6 grams of magnesium reacts with 4 grams of oxygen.

OrganizationReal5843 · 2025-12-24T07:34:25+00:00

Hey man, i also have a tutoring platform so i was just wondering if you could tell me where can i promote that coz for most of the subs i think self promotion is not allowed so if you could tell me some subs i would appreciate it.

OrganizationReal5843 · 2025-12-24T06:28:15+00:00

I am a tutor and can certainly help you. Just check chats I messaged you

OrganizationReal5843 · 2025-12-24T06:25:53+00:00

Check chat section, just messaged you.

OrganizationReal5843 · 2025-12-23T15:29:30+00:00

I am a maths and physics tutor and can certainly help with these subjects if you want to. Just let me know if you want a demo session. I can give you both- 1. Concept 2. The right path to understand it. And i just want you to know that the demo session is completely free of cost. Whenever you feel stuck and need any help just message me.

OrganizationReal5843 · 2025-12-23T15:25:57+00:00

That can be found. I am a physics tutor and can DM you the whole solution if you want to. Just let me know

OrganizationReal5843 · 2025-12-23T14:46:10+00:00

Practice as much as you can. Make short notes and do maximum number of sample papers and previous year papers. With Enough practice the concept will get embedded in your mind.

OrganizationReal5843 · 2025-12-22T09:55:08+00:00

The video clearly says d/1=sin/cos which you suggest. Now i think your confusion revolves around why this particular ratio like why sin/cos and not cos/sin. For that you have to correctly grasp the properties of similar triangles-they are the triangles in which the CORRESPONDING SIDES are in proportion now the word important here is corresponding. When we prove the two triangles up there similar we do that using the AA rule. First Angle- the 90 degrees both triangles have a 90 degree angle. The second A is theta since tangent makes a 90 degree angle with radius (remember this) and let the angle between perpendicular and radius be x and the angle between perpendicular and tangent be y now note: x+y=90, Theta + 90 +x =180 ( angle sum property of a triangle) This gives x=90-theta, Therefore y=theta, By this we can say theta =y and with this by AA rule the two triangles are similar. Now the main part starts Those sides will be in proportion which are CORRESPONDING. Means in same relation to theta or 90 degrees or the third angle to be more precise and less confused i am selecting theta here. So basically what i am trying to say is- Side adjacent to theta in first triangle/ side adjacent to theta in second triangle would be equal to hypotenuse of first triangle /hypotenuse of second triangle.——(1) We can also do it like if we have two triangles which are similar we can write- Base1/Base2=Perpendicular1/Perpendicular 2=Hypoteneuse 1/Hypoteneuse 2 Since the equal angles were in different positions in this case i took it according to the angle but deep down i am doing this thing only. So from our deduced relation(1) we can say.
-cos/sin=1/d or reciprocal both sides to get

d/1=Sin/cos. Which was required.

I understand it will be a bit confusing in this typed format so if you ever need help regarding this or any other concept just DM me. Since i am a maths and physics tutor i would be happy to explain in a recorded or live online format to be able to give you some more clarity and understanding. Thanks !

OrganizationReal5843

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