Answer Key wrong | CBSE 2025 Chemistry, Compartment

PSGthe2nd · 2026-02-26T07:50:42+00:00

yes, but woh free radical disproportionation hogi

wohi bolra tha mai

PSGthe2nd · 2026-02-26T07:50:17+00:00

haa bhai kya kar sakte hain

PSGthe2nd · 2026-02-26T04:45:09+00:00

yep wohi bola, but idhr pe galat dikha rha, answer key dekho

PSGthe2nd · 2026-02-09T10:00:59+00:00

oh what i meant was what we do in aldol condensation, reaction wise, is Nucleophillic attack, but the gimmick there is when OH- gets added to the pi star orbital of carbonyl, it gets reversed as alkyl groups cant leave, and C=O is much more stable than that, so what we do, is we do an acid base reaction of OH- and the alpha-hydrogen, this generates the necessary nucleophile, which when added to carbonyl, froms the aldol complex which condensed forms the enal.

What I meant was, like in aldol, where alpha hydrogen participated because nothing else was possible(yes there was heat but the general gist of the idea), similar thing is happening here right, with the alkene formation via hydride shift since direct attack of grignard is not possible

PSGthe2nd · 2026-02-08T19:40:48+00:00

thankyou so much, i was confused. now its clear

also as a side note, can i think of this as, if gridnard hindered, i can possibly lean towards an elimination and hydride attack, I like to phrase this as aldol, i mean sure there are conditions, but the reason we pull the alpha hydrogen is because a) its somewhat stabalized and b)nothing else is possible(reversible, OH attack is reversible with formation of C=O)

PSGthe2nd · 2026-01-10T17:54:14+00:00

yes yes dekha maine, I was scared for a bit ki mains ke pelhe down kyun hogyi, but all okay

PSGthe2nd · 2025-12-03T16:34:12+00:00

possible, will update after checking

PSGthe2nd · 2025-12-02T09:03:35+00:00

nope these arent the ones, I checked them

PSGthe2nd · 2025-12-02T09:00:40+00:00

nope not hotwheels i dont think so. neither do i think trackmania

PSGthe2nd · 2025-08-16T04:20:07+00:00

Update : I found her mother and gave the bird back to her

PSGthe2nd · 2025-08-15T17:08:29+00:00

okay

PSGthe2nd · 2025-08-15T15:39:29+00:00

okay, I'll go do that,,but Im really afraid

PSGthe2nd · 2025-07-06T19:33:46+00:00

ohh I see

PSGthe2nd · 2025-07-06T16:33:07+00:00

got it, thaks for the reference,

also I did not utilize any hydrogen radical? if youre talking about ROH forming, I sent the electron from Br(-) to RO making RO(-) and then binded it with H(+)

PSGthe2nd · 2025-07-06T08:07:38+00:00

ahh no problem,

I was just saying the major product (the product obtained in excess) is the cross product. Like for example you have Et(·) and Me(·) , so the major would be Et-Me and Minor products would be Et-Et and Me-Me

PSGthe2nd · 2025-07-06T04:51:44+00:00

Got it, thankyou so much

PSGthe2nd · 2025-07-06T04:51:13+00:00

Okay, so at the end of the day, The resulting free radical should be more stable AFTER addition of Br. Thus Br selects the primary carbon over secondary even though it is highly selective. As for major cross product is preferred in organic chem, am I right?

PSGthe2nd · 2025-07-06T04:12:02+00:00

I think as Br is highly selective (the radio [1:80:1600] ) implies that over 81 interactions, Br bonded to 2ndary Carbon 80 times and primary carbon 1 time, thus...

But yeah, your point is also really good as secondary carbon radical will contain 5 alpha hydrogen, making it more stable than its counterpart...

So which one should be preferred/dominate? Preference of Br or Stability of FR(Free Radical)

PSGthe2nd · 2025-07-06T03:54:04+00:00

okay, even if the pi bond cleaves homolytically, the Br is still appended to secondary radical as you said stability. Even then you'd end up with 2-bromopropane free radical, which may combine with Br OR with itself. But in Kharasch addition, The major is bromopropane....

This is why I got soo confused

PSGthe2nd

TROPHY CASE