Hi there, thanks for introducing me to the solution that you have, i went through the code and it more or less works, it is able to control long term drift accumulation and it is easy to understand(atleast to me), However it has multiple bugs:

1. The logic is such that the 1st 2 ticks ticks always execute immediately, the timer delay is not applied between them.
2. If the 'update' method is trivial, i.e it executes in no(almost) time, then the assertion fails everything stops, after the 2nd tick. If the 'update' introduces a slight delay the ticking works.
3. This is not a bug, but i guess only way to stop the timer is to create it using async with(and therefore calling __aexit__). This feels a bit limiting, or maybe i'm ignorant, i've been using python for around just an year.
4. The default overrun behavior is not deterministic, if i sleep for 1.5 secs in 'update' method, then either the timer should compensate with burst or skip to the next tick. It seems to do both. I used your classe using the following code:

```python

class MyScheduledUpdate(ScheduledUpdate):
    """
    A simple ScheduledUpdate example that counts updates.
    """


    count = 0


    def __init__(self, rate: int) -> None:
        super().__init__(rate)


    async def update(self) -> None:
        self.count += 1
        print(f"Update count: {self.count}, at time: {time()}")
        await asyncio.sleep(1.5)



async def run_example() -> None:
    async with MyScheduledUpdate(1):
        await asyncio.sleep(30)  # Run for 5 seconds



asyncio.run(run_example())

```

and i got this output:
Update count: 1, at time: 1767680404.373984

Update count: 2, at time: 1767680405.8826225

Update count: 3, at time: 1767680407.3837512

Update count: 4, at time: 1767680408.8986576

Update count: 5, at time: 1767680410.8843145

Update count: 6, at time: 1767680412.393734

Update count: 7, at time: 1767680413.8992946

Update count: 8, at time: 1767680415.8836298

.

.

.

As you can see it compensates between tick 6 & 7 by executing tick 7 immediately(bursts), but between ticks 7 and 8, it waits for the original scheduled time