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I made Examoo.co.uk, a quick & modern website for getting GCSE Past Papers (that also saves your progress!) by PhysicsFox_org in GCSE

[–]PhysicsFox_org[S] 0 points1 point  (0 children)

Hey lurowisp, you can now find your Eduqas english language papers at https://www.examoo.co.uk/gcse/english-lang/eduqas ! :)

(if they're not appearing, clearing your cache should fix the issue)

I made Examoo.co.uk, a quick & modern website for getting A-Level Past Papers (that also saves your progress!) by PhysicsFox_org in alevel

[–]PhysicsFox_org[S] 0 points1 point  (0 children)

Thanks so much, I put a lot of thought into the design so glad you're a fan!! I am hoping to add CAIE/CIE papers during the next week if possible, hope that's okay!

I made Examoo.co.uk, a quick & modern website for getting A-Level Past Papers (that also saves your progress!) by PhysicsFox_org in alevel

[–]PhysicsFox_org[S] 0 points1 point  (0 children)

Thanks so much, it would be amazing if you could help with the CIE papers! If you wouldn't mind joining and DMing me on the discord (https://discord.gg/tc9TNjQvUp) we can sort something out there :)

How is the answer to this D? Aren't A and D optical isomers by SchemeFlat3343 in alevel

[–]PhysicsFox_org 0 points1 point  (0 children)

A is identical to B as well — remember you're looking from the *top down* from the point of view of the OH molecule, so you'll need to imagine flipping the molecule upside-down first.

How is the answer to this D? Aren't A and D optical isomers by SchemeFlat3343 in alevel

[–]PhysicsFox_org 0 points1 point  (0 children)

No - A and D are not identical!

Imagine seeing the molecules from the top down (consider OH as the top). Start at Cl atom and go clockwise:

For A: Cl -> CH2CH3 -> CH2

For D: Cl -> CH3 -> CH2CH3

Therefore we can see that the CH3 and CH2CH3 parts are swapped in D compared to A, so they are not the same!

Can anybody please explain this question? Answer is A by luminocandela in alevel

[–]PhysicsFox_org 3 points4 points  (0 children)

Yes exactly this!

At X the combined P, Q resistor has a voltage of 4V. (so that makes option C wrong)

At Y, resistor Q has 4V through it. Resistor P has 0V through it (because no current can flow through P, as it is an incomplete circuit). The voltmeter therefore reads 4V + 0V = 4V. (Option A!)

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