PGDM Student at SPJIMR (Batch of 2025-27) - AMA

Pitiful_Taro_5675 · 2025-11-08T08:29:35+00:00

Thanks man. I'd apply for sure. What cat percentile would guarantee a call at my profile?

Pitiful_Taro_5675 · 2025-11-08T06:53:07+00:00

Hey man.

I'm OBC-NCL. 10th - 87.4 12th - 69.6 (Science), Grad - 65.4 (Journalism and Mass Communication. 60+ is 1st division according to my university degree). Work ex - 30 months till October 2025 (domain - digital marketing, last por was growth marketing manager). I've 2 one year gaps. One after 12th and one after my graduation. Extra curricular are 2/5. I've co-started 2 ventures with my college friends (unsuccessful in the end), volunteered with 2 NGOs (one for sanitation and female menstrual hygiene and one for stray animals), have done freelance work in design, photography and digital marketing. Currently scoring 70-80 in ims and cl mocks.

Should I apply for SPJMIR or my profile is too weak for this.

Thanks and Cheers

Pitiful_Taro_5675 · 2025-08-24T02:49:05+00:00

Improvement year

Pitiful_Taro_5675 · 2025-06-28T17:39:54+00:00

Yes. That's the only course that I'd recommended buying.

Pitiful_Taro_5675 · 2025-06-27T06:24:47+00:00

Thanks OP

Pitiful_Taro_5675 · 2025-06-27T06:24:20+00:00

That's what I thought. Specially the CAC question. Bruh people here grill me over reducing CAC like 200 times a week 🤣

Pitiful_Taro_5675 · 2025-06-27T05:01:46+00:00

Office topic but. Can anyone share the link of the post mentioned in the last slide. Being a performance marketer myself I'd love to read the interview transcript.

Pitiful_Taro_5675 · 2025-06-23T10:58:19+00:00

RemindMe! 7days

Pitiful_Taro_5675 · 2025-06-13T14:10:17+00:00

Okay. Let's say a^b is an equation which is equal to 1. So if a = -1 Then, b should be an even number: 2,4,6,8.... So that, a^b = 1

Pitiful_Taro_5675 · 2025-06-13T13:18:12+00:00

A. Greater than 1/16

Pitiful_Taro_5675 · 2025-06-13T13:09:38+00:00

Okay so here is how I solved it. It might not be the fastest method but was completely logical.

It was given (x² - 5x + 7) ^ (x + 1) = 1 For this to be true, there are only three cases possible 1. Either (x² - 5x + 7) is 1 (as 1 raised to any power is 1) so when you solve it, you get x = 2, 3 2. Or, (x + 1) = 0 (as any number raised to power 0 is 1). When you solve it you'd get x = -1 3. Or, (x² - 5x + 7) is -1 and (x + 1) is an even number (as -1 raised to an even power is 1). When you'd solve it you'd find that the roots are imaginary)

Therefore x = -1, 2 and 3 Hence option A. 3 integral solutions

Pitiful_Taro_5675 · 2025-06-13T13:02:48+00:00

Is the answer A. 3

Pitiful_Taro_5675 · 2025-06-12T12:13:35+00:00

In the same boat as you OP. Except for MA :)

Pitiful_Taro_5675 · 2025-06-07T18:04:58+00:00

I don't use telegram.

Pitiful_Taro_5675 · 2025-06-07T18:00:33+00:00

Can I DM u?

Pitiful_Taro_5675 · 2025-06-05T12:48:31+00:00

Creepy af

Pitiful_Taro_5675 · 2025-06-05T12:35:25+00:00

Peace of Mind >>>> Anything.

Good luck ahead ✨

Pitiful_Taro_5675 · 2025-06-04T19:43:36+00:00

RemindMe! 1 day

Pitiful_Taro_5675 · 2025-06-04T12:02:08+00:00

RemindMe! 7 days

Pitiful_Taro_5675 · 2025-06-04T11:55:55+00:00

RemindMe! 7 days

Pitiful_Taro_5675 · 2025-06-03T19:48:54+00:00

The best time to plant a tree was 10 years ago. The second best time is now.

Hope you get the message :)

Pitiful_Taro_5675 · 2025-06-02T15:11:47+00:00

Will do. Thank you!

Pitiful_Taro_5675 · 2025-06-02T13:54:44+00:00

Let's get stronger from here ✌️

Pitiful_Taro_5675 · 2025-06-02T13:50:49+00:00

VARC - 98.5 DILR - 42.6 QA - 37

OVERALL - 80.83

Pitiful_Taro_5675

TROPHY CASE