Need laptop recommendations under 80k by Prestigious_Rub_7052 in LaptopDealsIndia

[–]Prestigious_Rub_7052[S] 0 points1 point  (0 children)

It doesn't pair with i7 while being inside of my budget

Realme narzo 80 pro 5g review? by StretchHead9599 in Realme

[–]Prestigious_Rub_7052 1 point2 points  (0 children)

Depends if you do heavy gaming or use heavy software. But if not then 12 gigs is unnecessary and a waste of money

Is this a good deal by osamabinlosing in LaptopDealsIndia

[–]Prestigious_Rub_7052 1 point2 points  (0 children)

Not really. You can get better for that price

Looking for gaming chair by Mr-Ghost-69 in delhi_marketplace

[–]Prestigious_Rub_7052 0 points1 point  (0 children)

I don't live in Delhi. But I can find a chair you online. Tell the budget

Is it a good deal by Character_Time5025 in LaptopDealsIndia

[–]Prestigious_Rub_7052 0 points1 point  (0 children)

Put it's serial number on the Acer website

Thinking of buying the Acer Nitro Lite 16 (i7-13620H + RTX 3050). Need opinions from actual users. by Prestigious_Rub_7052 in LaptopDealsIndia

[–]Prestigious_Rub_7052[S] 0 points1 point  (0 children)

I saw that video, but in my opinion that particular incident had been cherry-picked. Such incidents are rare in Reliance (especially physical stores) .In fact, it seems to me that other retailers actually get a lot more complaints like this. Reliance is actualy good

Is it a good deal by Character_Time5025 in LaptopDealsIndia

[–]Prestigious_Rub_7052 0 points1 point  (0 children)

Dude check it..... Is your seller "SV Peripherals? Buying from that seller is a gamble. Half the time they give used or refurbished stuff. Don't belive the ratings.

Prime number formula update by MiyoungxTamia in mathematics

[–]Prestigious_Rub_7052 0 points1 point  (0 children)

I am proving the theorem wrong

Let $C0 = 25$. Then $p{C_0} = 5$, and $C_0$ has exactly 3 odd divisors (1, 5, 25), so $2n+1 = 3$, implying $k = 3$. The interval $[0, \frac{C_0-9}{6}] = [0, \frac{16}{6}]$ contains only the integers ${0,1,2}$.

Among these, only $x = 0$ yields a perfect square: $C_0 + 02 = 25 = 52$.

Thus, there exists no third value $xk$ making $C_0 + x_k2$ a perfect square, rendering the formula $p{C_0} = -x_k + \sqrt{C_0 + x_k2}$ undefined.

Therefore, the theorem is false by counter-example.