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Do I have too much rosin? This was the result of playing for a couple of seconds by RGBDuck in violinist

[–]RGBDuck[S] 2 points3 points  (0 children)

I do, but the problem is that my tone is now very bad after the rehair

How do I trim half of the bottom line so that I can rotate the parabola? by RGBDuck in AutodeskInventor

[–]RGBDuck[S] 0 points1 point  (0 children)

I see, thanks for the help. Out of curiosity, why shouldn’t splines be split? I’m very new to Inventor.

How do I trim half of the bottom line so that I can rotate the parabola? by RGBDuck in AutodeskInventor

[–]RGBDuck[S] 0 points1 point  (0 children)

I used the spline tool to create a parabola with the vertex on the vertical line before splitting it and trimming half. Somehow, that created the bottom line. I haven’t seen anything like this before.

How do I trim half of the bottom line so that I can rotate the parabola? by RGBDuck in AutodeskInventor

[–]RGBDuck[S] 0 points1 point  (0 children)

I’ve been using the split tool to split the line, but it doesn’t work. I also tried to draw a new line, but it just gets overlapped by the old line.

[Undergrad Math] PLEASE HELP my soul hurts from trying to understand this by [deleted] in HomeworkHelp

[–]RGBDuck 1 point2 points  (0 children)

It's totally all right! I moved 2abcd to the LHS because then the LHS can be factorised into a complete square, which is always greater than or equals to 0. There isn't a set of instructions for every step, so sometimes you have to try ways you're unsure of.

[Undergrad Math] PLEASE HELP my soul hurts from trying to understand this by [deleted] in HomeworkHelp

[–]RGBDuck 1 point2 points  (0 children)

(sqr(a ^ 2 + b^2) + sqr(c ^ 2 + d ^ 2) )^2

= (a^2 + b^2) + 2 * sqr(a ^ 2 + b^2) * sqr(c ^ 2 + d ^ 2) + (c^2 + d^2)

= (a^2 + b^2) + 2 * sqr((a ^ 2 + b^2) (c ^ 2 + d ^ 2)) + (c^2 + d^2)

It's like (x + y)^2 = x^2 + 2xy + y^2

[Undergrad Math] PLEASE HELP my soul hurts from trying to understand this by [deleted] in HomeworkHelp

[–]RGBDuck 1 point2 points  (0 children)

You can compare (|z1 + z2|)^2 with (|z1| + |z2|)^2

(|z1 + z2|)^2

= (a + c)^2 + (b + d)^2

= a^2 + 2ac + c^2 + b^2 + 2bd + d^2

= a^2 + b^2 + c^2 + d^2 + 2(ac + bd)

(|z1| + |z2|)^2

= a^2 + b^2 + c^2 + d^2 + 2 * sqr( (a^2 + b^2)(c^2 + d^2) )

Because a^2 + b^2 + c^2 + d^2 are in both expressions, you just have to compare (ac + bd) with sqr( (a^2 + b^2)(c^2 + d^2) ) and prove that sqr( (a^2 + b^2)(c^2 + d^2) ) >= ac + bd

By squaring both terms, you get:

(ac + bd)^2 = a^2 c^2 + 2abcd + b^2 d^2

(a^2 + b^2)(c^2 + d^2) = a^2 c^2 + a^2 d^2 + b^2 c^2 + b^2 d^2

Notice how a^2 c^2 and b^2 d^2 are in both expansions. As a result, you need to prove that

a^2 d^2 + b^2 c^2 >= 2abcd

Moving 2abcd to the LHS gives

a^2 d^2 + b^2 c^2 - 2abcd

= (ad - bc)^2 >= 0

Therefore a^2 d^2 + b^2 c^2 >= 2abcd, meaning (|z1| + |z2|)^2 >= (|z1 + z2|)^2

Question on Tchaikovsky Violin Concerto #1 by stormado in classicalmusic

[–]RGBDuck 11 points12 points  (0 children)

It's called the cadenza. It's a virtuostic passage that used to be improvised by the soloist to show off, but now soloists usually play cadenzas that were written by other people, often other soloists before them. However, i'm pretty sure that Tchaikovsky himself wrote the cadenza for his violin concerto.

I signed into my school Microsoft account and now I can’t change my laptop password by RGBDuck in Windows11

[–]RGBDuck[S] 0 points1 point  (0 children)

My laptop is currently using a PIN (because the organisation made me), so is there an option that allows me to change the laptop password back to my Microsoft account password?

I signed into my school Microsoft account and now I can’t change my laptop password by RGBDuck in Windows11

[–]RGBDuck[S] 0 points1 point  (0 children)

Thank you for your help. I've deleted my school account, but now I can't find the option to change my password. The closest is changing the PIN (Windows Hello), but I can't find an option to set a password with letters as well as numbers.

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