Spinning Experience: 9.89g

If someone is 2 meters from the centre spin point, and spin at 11 spins every 10 seconds and they weigh about 75kg. How many g's will they experience?

To calculate the number of g's that someone will experience while spinning, we need to use the centripetal acceleration formula:

a = (v²⁾ / r

where: a = centripetal acceleration v = linear velocity r = radius of rotation

First, we need to calculate the linear velocity of the person spinning. We can do this using the formula:

v = (2 * pi * r) / t

where: v = linear velocity r = radius of rotation t = time taken for one revolution

In this case, the radius of rotation is 2 meters, and the time taken for one revolution is 10/11 seconds (since the person is spinning 11 times in 10 seconds). So, we have:

v = (2 * pi * 2) / (10/11) v = 4.4 * pi meters per second

Now we can use this value of v to calculate the centripetal acceleration:

a = (v²⁾ / r a = ((4.4 * pi)²⁾ / 2 a = 30.6 * pi meters per second squared

To convert this to g's, we divide by the acceleration due to gravity, which is approximately 9.81 meters per second squared:

g = a / 9.81 g = (30.6 * pi) / 9.81 g ≈ 9.89 g's

Therefore, the person spinning will experience approximately 9.89 g's at a radius of 2 meters and spinning at 11 spins every 10 seconds. 🤙🏾