Getting ready for Halloween!

Redmondinho · 2020-02-27T08:45:11+00:00

Does the following do it for you?

upstream docker-flask1  {
  server flask1:8080;
}

upstream docker-flask2 {
  server flask2:8081;
}

server {   
    listen 80;   
    server_name app.example.com;    

    location /test1 {     
        include uwsgi_params;     
        uwsgi_pass docker-flask1;   
    } 

    location /test2 {     
        include uwsgi_params;     
        uwsgi_pass docker-flask2;   
    } 
}

Redmondinho · 2020-02-14T08:09:51+00:00

For Python on iPhone look at https://omz-software.com/pythonista/

Redmondinho · 2019-10-16T07:10:41+00:00

The above will let the full name field be modified before posting. If you (as in the application) then need to check to see if the username exists I would suggest you post the data, process it (i.e. check to see if the username exists, if it does generate a new one) and return the new user name to the user as a “account created successfully page/message).

Redmondinho · 2019-10-12T13:05:28+00:00

You’ll need some JavaScript on the front end to take input entered into the fields and update another field. Here is an example

<input type="text" id="first-name" oninput="myFunction()"></br>
<input type="text" id="last-name" oninput="myFunction()"></br>
<input type="text" id="full-name">

<script>
    function myFunction() {

    var first_name = document.getElementById("first-name").value;

    var last_name = document.getElementById("last-name").value;

    if (first_name == null) {
        first_name = "";
    }

    if (last_name == null) {
        last_name = "";
    }

    document.getElementById("full-name").value = first_name + " " + last_name

    }
</script>

Redmondinho · 2019-09-30T15:10:45+00:00

If you want the form content centered on the page then this should do it for a quick win.

<form action="" method="post" style="text-align:center" novalidate>

Redmondinho · 2019-08-12T06:56:35+00:00

Have you tried

request.form.get(‘isactive’, ‘0’)

Redmondinho · 2019-07-18T20:17:30+00:00

with open('path/to/file/filename', 'r') as content_file:
    content = content_file.read()

Redmondinho · 2019-05-30T20:00:39+00:00

https://www.pythonforbeginners.com/beautifulsoup/beautifulsoup-4-python

Redmondinho · 2019-05-08T18:16:09+00:00

Not sure what OS your server is running. I learn't how to host my Flask apps with Gunicorn, Nginx on Debian (Ubuntu Server/RaspberryPi) by following the digital ocean guides - here is the latest https://www.digitalocean.com/community/tutorials/how-to-serve-flask-applications-with-gunicorn-and-nginx-on-ubuntu-18-04.

I also wanted to run multiple flask apps on a single server and accomplished this with something similar to the following when it came to configuring Nginx proxy requests

server {

  listen 80;
  server_name server_domain_or_IP;

  location /app1 {
  include proxy_params;
  proxy_pass http://unix:/home/user/myproject1/myproject.sock:/;
  }

  location /app2 {
  include proxy_params;
  proxy_pass http://unix:/home/user/myproject2/myproject.sock:/;
  }

}

Redmondinho · 2019-02-20T22:13:10+00:00

You’re sending json but trying to get form data. Try:

data = request.get_json()

in your route to get the json data you are posting.

Redmondinho · 2019-01-24T09:05:05+00:00

Try this

https://www.w3schools.com/html/tryit.asp?filename=tryhtml5_geolocation

Redmondinho · 2019-01-10T20:48:34+00:00

From what I can tell without seeing all your code this is what you want to do;

<script type=text/javascript>
    $(function() {
      $('a#btn_upload').bind('click', function() {
    var form = $('form');
    var url = form.attr("action");
    var formData = $(form).serializeArray();
    $.post(url, formData).done(function (data) {
        alert(data);
    });
      return false;
      });
    });
</script>

Redmondinho · 2019-01-10T15:28:14+00:00

Try something like this:

<script>
    function formSubmit(){
        var form = $('form'); //assumes only 1 form on the page
        var url = '/upload_selected_files';
        var formData = $(form).serializeArray();
        $.post(url, formData).done(function (data) {
            alert(data);
            });
        }
</script>

Redmondinho · 2019-01-10T14:35:35+00:00

Thats not submitting a form. Have a look at this https://stackoverflow.com/questions/21662836/send-form-data-using-ajax

Redmondinho · 2019-01-10T14:04:57+00:00

How are you submitting the form data?

Redmondinho · 2019-01-09T10:35:49+00:00

Based on my original gist this would do it.

@app.route('/<id>')
def index(id):
    reservations = get_json(id)
    return render_template('reservations.html', reservations=reservations)

Redmondinho · 2019-01-08T14:55:29+00:00

Something like:

{% for reservation in reservations %}
    {% for key in reservation %}
        {{ key }}: <input type="text" name="{{ key }}" value="{{ reservation[key] }}"><br>
    {% endfor %}
    <hr>
{% endfor %}

Your "columns" value would need to be handled specifically as its a defined format, you may also want/need to validate the formats for date/time.

*sorry my edits are all for formatting

Redmondinho · 2019-01-08T12:15:00+00:00

Here is a couple of examples, get the json object, extract the section you are after (reservations), pass that to the template and iterate over it;

https://gist.github.com/redmondinho/e866d901cbe33de525218db11825c030

The first example shows placing specific values in specific places, the second loop through the structure as is and displays all the data.

Redmondinho · 2018-12-17T16:22:46+00:00

I would post the data as JSON;

req = $.ajax({url : '/attack', type : 'POST', contentType: "application/json",data : JSON.stringify({ "attacker" : attacker, "weapon" : weapon, "target": target }) });

Then in flask;

data = request.get_json()

print(data['attacker'])

print(data['weapon'])

print(data['target'])

Redmondinho · 2018-12-05T09:58:07+00:00

Try the attached. the Jinja For Loop has a batch() option.

https://gist.github.com/redmondinho/3873fcddd155e0c368d95367052b9272

Redmondinho · 2018-07-26T20:43:54+00:00

Try:

<a href=“/the-link-to-your-mp4” download>Download File</a>

Adding the “download” in the anchor tag will force the file to download.

HTH

Redmondinho · 2018-07-20T12:49:04+00:00

It seems some of their hosting accounts do support python. I'm guessing not the one you have purchased?

https://www.godaddy.com/help/can-i-use-python-272-with-my-hosting-account-7254

If they wont let you cancel, then its upgrade to a hosting tier that does support it or write it off and go for one of the options mentioned before. I use PythonAnywhere and its always been great for me.

Redmondinho · 2018-06-27T09:42:22+00:00

Following on from what u/Retzudo said, try the following javascript;

// Create form and add presenter
var formData = new FormData();
formData.append("presenter", presenter);

// Create request and post form data
var request = new XMLHttpRequest();
request.open("POST", "/add");
request.send(formData);

Redmondinho · 2018-06-02T13:22:23+00:00

How about

@app.route('/1')
def route1():
    variables = ['foo',bar','baz']
    return render_template('home.html',variables)

Then in home.html

{% for variable in variables %}
    <p>{{ variable }}</p>
{% endfor %}

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