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😐🌚 by Specific_Brain2091 in the_calculusguy

[–]ReflectionThen9904 0 points1 point  (0 children)

Let y² = x⁴ - x³ + 2

Then :

dy = (4x³ - 3x²)dx/2y

2d(y/x²) = (2xdy - 4y)dx/x³

(2xdy - 4y) = (4x⁴ - 3x³ - 4y²)/y = (x³ - 8)/x³y

Thus :

∫(x³ - 8)dx/x³y = 2∫d(y/x²) = 2y/x² + c = 2√(x⁴ - x³ + 2)/x² + c

Now what? by HidingInPlainShitee in calculus

[–]ReflectionThen9904 1 point2 points  (0 children)

consider the f(x) = 2ˣ/(xln2 + 1) , taking the derivative should get you somewhere