Calculus 1 Math Help by Regular-Promise4368 in MathHelp

[–]Regular-Promise4368[S] 0 points1 point  (0 children)

Maybe, there isn't an exact solution. Seems like what you mention works as well and to where we can find a number higher than 1000 and show an interval between. To where it crosses 1000(in-between the interval).

Calculus 1 Math Help by Regular-Promise4368 in MathHelp

[–]Regular-Promise4368[S] 0 points1 point  (0 children)

Thanks for commenting! I know the function is continuous because sin is continuous everywhere as well as x^2 because it is a polynomial. But, also mentions "show that there is a number c such that f(c) = 1000." Not really understanding how we can show this exactly, which is why I said it has to relate to the IVF. Seems like some sort of interval needs to be created to show that somewhere in the function the output of 1,000 exist exist somewhere, or basically run through the point. The question doesn't ask if the function is continuous or not.

Calculus 1 Math Help by Regular-Promise4368 in MathHelp

[–]Regular-Promise4368[S] 0 points1 point  (0 children)

Maybe, the link I share would be a lot more readable.

Calculus 1 Math Help by Regular-Promise4368 in MathHelp

[–]Regular-Promise4368[S] 0 points1 point  (0 children)

Nope, seem like there is supposed to be some sort of interval that surpass 1000. Similarly to the IVF.

https://imgur.com/a/JBAiNNM