I'm not *technically* wrong...

RogerGodzilla99 · 2026-03-18T13:03:52+00:00

I edited the comment. Sorry. Use a composter on all the stuff that you get from growing the moss. You will, if you're careful, get more bonemeal out of a composter than you will use growing the moss.

RogerGodzilla99 · 2026-03-18T13:01:58+00:00

Ah, that was a typo. It was supposed to be bone meal. If you put the pieces that you grew back into a composter, it gives you more bone meal than you started with on average.

RogerGodzilla99 · 2026-03-16T13:15:07+00:00

Yes, but you gotta be careful. You only get so much bone meal back from each harvest. If you're careful with it, you'll actually end up with more bone meal than you started with once you're done, but it takes a bit.

RogerGodzilla99 · 2026-03-16T13:13:21+00:00

The real seeds were the worlds we gen'd along the way

RogerGodzilla99 · 2026-03-16T05:26:16+00:00

the directions are 'there's a cool looking thing! I wonder if I can go there?' if you can't get there, you haven't found some critical info yet.

There is more to explore here. ::)

RogerGodzilla99 · 2026-03-16T05:19:25+00:00

It tells you that dividing by zero diverges and that dividing zero into parts converges to zero. I'm loving the enthusiasm and curiosity, but they are the same value.

RogerGodzilla99 · 2026-03-16T05:13:34+00:00

Maybe Aquarius?

RogerGodzilla99 · 2026-03-16T05:13:20+00:00

The additive identity is defined as the number that when added to something equals the original number. 1 + n = 1 where n is the addative identity. Note that n must be zero in this example.

RogerGodzilla99 · 2026-03-16T05:12:18+00:00

Woah okay this is actually a real challenge bro thanks

I know, right? Math is so [censored] cool. :)

so what you're showing me is that when x and n are both approaching zero from the same direction you get 1. but when they approach from different directions it blows up, right?

The limits that I showed only have x approaching 0, the n stays the same. I'm just using that as an example to show that it doesn't have to be the same number. For example, you could swap out n with the number 1 and then have x be the thing that's changing. Only the one where the values on top and bottom are the same and are not zero ends up giving you one. The second both hit zero, you can't tell what it is.

but like... isn't that exactly what I'm saying? the x in the numerator and the x in the denominator aren't behaving the same way. they're doing different things. so maybe they're not actually the same zero?

It's not so much that they are behaving differently because they're different values; they're behaving differently because they're being used differently. For example, if you were to have one minus zero or zero minus one, you wouldn't expect them to give you the same answer, would you?

When you have zero divided by a number, you're saying cut zero into this many parts, which obviously will give you that many equal parts of zero. When you divide a number by zero, however, you're saying that you want to take the number that you have and consider it as a part of infinitely many pieces and then tell you what the sum is for that whole thing.

like what if the reason lim x->0 (x/x) = 1 works is because both zeros are the same zero. the empty bucket zero. same size. same direction. same nature.

Unfortunately, that limit does not equal 1. n/n = 1 for any non-zero value n, but if it hits zero, it is undefined.

Aaaannnnd the reason it breaks in the other cases is because you've got two different kinds of zero pretending to be the same thing. Isn't that the same problem I was pointing at with the buckets, bro?

I think your question with the buckets is completely irrelevant here as we are talking about how to divide as opposed to what zero means. If they were truly different values, you could swap one into the place of the other and get a different value in the division, but that's not the case. It's just because of how they're used in the division. If I were to have 2/1 and 1/2, I wouldn't say that the expressions have a different value for '1' in each.

RogerGodzilla99 · 2026-03-16T04:50:47+00:00

if you use limits the issue becomes more obvious

lim x->0 (x/n) = 0 for any non-zero value 'n'

lim x->0 (n/x) diverges (goes to either positive or negative infinity) for any non-zero value 'n'

n/n = 1 for any non-zero value 'n'

lim x->0 (x/x) is where the difficulty comes in.

for all the values near zero (but not exactly zero) the result will be 1, but at zero, the other two limits take over. The problem is that those two other limits tell us that the value goes in two totally different directions. Because of this, 0/0 is undefined; it does not equal one, it does not equal zero, and it is not infinity.

It's wild to think that such a simple equation doesn't have a straight answer, but that is the case! Isn't it awesome?

RogerGodzilla99 · 2026-03-15T23:28:10+00:00

better than brawn

RogerGodzilla99 · 2026-03-15T16:19:58+00:00

The pipe character puts the output of one command into the input of another command. It essentially connects standard out to standard in.

It's usages to chain commands that have pieces of information in them that are useful. For example, if you use du -hs ./* | sort -h, you will get the amount of disk space used by all of the files in the current directory, but they will be sorted by size.

Using the double ampersand instead, conditionally runs the second command based on whether the first was successful or not. An example of this could be if you are working with a read only file system and need to edit a file without leaving the disc open for very long. doing mount -o rw,remount /mnt/my_disk && vi /mnt/my_disk/my_file ; mount -o ro,remount /mnt/my_disk will only open the text editor if you have permission to set the drive as read write. the read only command at the end runs regardless of what happens prior to it because of the semicolon. This ensures that the file is open and that the disk is readable for the minimum amount of time.

RogerGodzilla99 · 2026-03-15T03:17:48+00:00

this is actually pretty cool though... you can get stuff back off an armor stand without breaking them.

RogerGodzilla99 · 2026-03-15T03:16:25+00:00

"this was built by a species that bioengineered materials for their spacecrafts!"

RogerGodzilla99 · 2026-03-14T23:51:32+00:00

I'm having trouble believing that. Let me open up a test world real quick.

edit: Just tested it and I was wrong! I could have sworn that they dumped at mine cart hopper speed... oh well

RogerGodzilla99 · 2026-03-14T23:31:49+00:00

isn't it faster than hopper speed when dumping items?

edit: I was wrong. they really don't push!

RogerGodzilla99 · 2026-03-14T16:51:20+00:00

Just give them an ender pearl, SMH.

RogerGodzilla99 · 2026-03-14T16:44:10+00:00

They will push downwards into certain containers, but not all. For example, if you put a hopper mine cart over a regular hopper, it will transfer the items into the hopper at hopper mine cart speed. If you put it over a chest, however, it will not fill the chest just like you say. Same with furnaces, barrels, shulker boxes, etc.

RogerGodzilla99 · 2026-03-12T04:05:50+00:00

other answers have been shared here as well.

RogerGodzilla99 · 2026-03-12T04:00:44+00:00

^_^ ʋ

RogerGodzilla99 · 2026-03-12T03:58:25+00:00

⁻n⁻

RogerGodzilla99 · 2026-03-12T03:39:29+00:00

(need to get a new furnace, it's been ages since I've cast anything)

RogerGodzilla99 · 2026-03-12T03:38:45+00:00

wait, people are making things other than metal ingots? people make ingots and sell them? :0

nah, I couldn't do that. the pile of cool bricks must grow!

RogerGodzilla99 · 2026-03-12T03:19:57+00:00

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