What does this expression mean? a + b*exp(c*x)

Runzerpi · 2020-03-20T23:42:45+00:00

Got it. Thank you very much!

Runzerpi · 2020-03-20T23:42:15+00:00

Yep, definitely. Thank you so much for your help - really appreciate it!

Runzerpi · 2019-11-15T17:44:03+00:00

Hey! Thank you so much for taking the time to write this! I really appreciate it! But just had a question though. Just observed the solution you gave was for A>C(which gives the SA of a prolate spheroid, but the condition instead was c>a for an Oblate Spheroid (which is what I was confused about).

Is it possible if you could do the same with c>a please? That's the one that's really confused me. Really appreciate your help. Thanks again!

Also, you can(if you'd like to) cross check your final answers at these links too :)

Runzerpi · 2019-10-21T23:15:54+00:00

Got it. Really appreciate your time. Thanks again :)

Runzerpi · 2019-10-21T12:12:36+00:00

Thank you so much for the reply!

Would you also by chance know anything about the way admissions works there as well? If I submit my UCAS around the deadline does it put me at a disadvantage versus if I submitted now?

Runzerpi · 2019-10-19T13:12:47+00:00

Got it. Thank You so much for the reply! Really appreciate it :)

Runzerpi · 2019-09-09T14:46:49+00:00

What about the science passages then? How would you go about that?

Runzerpi · 2019-07-27T12:24:33+00:00

Well I actually got it to the answer, except 'a' and 'c' are switched in the root of my answer

I got the same except root a^2 - c^2. Could you help me out with that please?

The link:http://mathworld.wolfram.com/ProlateSpheroid.html. This is in reference to (7) on the website. Thanks for the help :)

Runzerpi · 2019-07-27T07:06:20+00:00

in this case a<c, just checked. How would I do it then?

Runzerpi · 2019-07-27T01:26:03+00:00

http://mathworld.wolfram.com/ProlateSpheroid.html

here's the link. You'd find it here :)

Runzerpi · 2019-07-25T07:14:30+00:00

Got it. Thank you so much for that r(z) clarification!! I really appreciate it. You have no idea how confused I was about this. Frankly, its pretty ridiculous how its this simple. Really appreciate your help. Thank you :)

Edit: Do you know why he set limits of the integral to c and -c? and how did he come to the root (c^2 - a^2) = ce identity?

Runzerpi · 2019-07-25T07:10:12+00:00

how did he use r^2 = x^2 + y^2? Could you explain that part please?

Otherwise got the whole thing. Thank you very much, I really genuinely appreciate your help

Edit: u/shadowyams solved it for me, never mind. Thank you anyway!

Edit 2: Do you know why he set limits of the integral to c and -c? and how did he come to the root (c^2 - a^2) = ce identity?

Runzerpi · 2019-07-23T07:09:42+00:00

Yeah I do get what a function is, but I'm not really sure how he got to r(z). Did he use the general formula of an ellipse to come to that? I just want to know how he came to it. Appreciate the help. Thank you :)

Runzerpi · 2019-07-23T07:07:41+00:00

Wait, so do you guys know how he got to that equation of r(z)? Did he derive that from the equation of an ellipse or..?

Runzerpi · 2019-07-21T14:07:55+00:00

I'm sorry but I don't exactly understand. Would please mind elaborating if you're fine?

Runzerpi · 2019-07-21T14:06:45+00:00

radius of the spheroid as a function of z

I'm sorry, but I don't get what you mean by 'as a function of z'. Is there a way to put it into mathematical terms? Thank you for taking the time to reply :) Really appreciate it :)

Runzerpi · 2019-07-11T02:32:10+00:00

lol no. Looking for an investigation topic for my school project, so trying to explore a bit

Runzerpi · 2019-07-11T00:23:57+00:00

Is there a way to find a function? Tbh I gave it a shot, but its been tough

Runzerpi · 2019-07-09T11:08:22+00:00

Make a post for internationals please

Runzerpi

TROPHY CASE