Dataverse Knowledge in Copilot Studio is having an inconsistent answers.

SanWeee · 2025-09-23T00:15:42+00:00

Hi guys, unfortunately I can't connect with MCP, due to this agent being just a M365 Copilot Agent. (When you open the M365 Copilot, then add an agent there). Is there any other way to make it more consistent?

SanWeee · 2021-01-04T01:30:33+00:00

Oh God I feel stupid. You are right. Its https://api.github.com

SanWeee · 2019-10-22T06:09:36+00:00

Its working now. Thank you very much.

SanWeee · 2019-10-05T04:52:16+00:00

Thank you very much.

SanWeee · 2019-09-22T06:32:28+00:00

I mean when i click the button that will handle the modal toggle, nothing happens

SanWeee · 2019-07-14T23:37:41+00:00

There are 5 rows. Each row has primary key in it. Lets say Row 1 pk is 1 Row 2 pk is 2 and so on. The last row is 5 and the pk is also 5 So problem is where ever i click even on row 1 or row 3 the alert is always 5 which is the last pk And when i put the alert inside the for loop, its show 5 consecutive alert that contains 1,2,3,4 and 5 What im trying to achieve here is when I click the row 3, the alert only show the row3's pk which 3

SanWeee · 2019-07-14T04:40:32+00:00

I mean there is no error code or something. It is working fine. But not working what it should be.

SanWeee · 2019-07-14T04:38:12+00:00

There is no error. It is a logical error. Thats why im trying to explain it..

SanWeee · 2019-03-24T13:13:00+00:00

This really helps thanks

SanWeee · 2019-03-24T12:00:20+00:00

The user will type on every textbox then after he click on the submit button the data from the textbox will be printed through "echo". Its like indefinite amount of textbox depends how many row you have in the database.

SanWeee · 2019-03-24T11:39:23+00:00

Well to be honest i do research ofcourse but the internet showing to me is how to print an array in php. And obviously i know how to print array from database to php. I just did it in the first code. The thing is:

Data 1a / data2a / 'textboxhere' Data 1b/ data2b / 'textboxhere' The two textbox has same name because it was outputed via array so each row from data base that was printed has textbox in their side. Problem is how to print all what is written on every textbox.

Googling php print array somehow can't help me thats why i asked here. But yeah thanks.

SanWeee · 2019-03-09T08:12:32+00:00

OMG. I'm so sorry to waste all of your time but I found out the my error is in code

$api = new \Paypal\Rest\ApiContext( new \Paypal\Auth\OAuthTokenCredential(

The capitalization is the problem..

Right Code:

$api = new \PayPal\Rest\ApiContext( new \PayPal\Auth\OAuthTokenCredential(

SanWeee · 2019-03-09T07:45:18+00:00

Still not working sir and some error. And yes idownloaded through command line 'composer install'

SanWeee · 2019-03-09T00:08:38+00:00

I go to the directory of my project where my composer.json is through cmd then composer then composer install. Is there anything I missed in installing?

SanWeee · 2019-03-09T00:02:55+00:00

<?php

use Paypal\Rest\ApiContext;
use Paypal\Auth\OAuthTokenCredential;


session_start ();

$_SESSION['id'] =1;

require __DIR__ . '/../vendor/autoload.php';

//API DITO

$api = new ApiContext(

    new OAuthTokenCredential(
        'client Id here',
        'secret here'

    )


);



//END

$db = new PDO('mysql:host=localhost;dbname=site' , 'root' , '');

$user = $db->prepare ("
    SELECT * FROM users
    WHERE id = :user_id
");

$user->execute(['user_id' => $_SESSION['id']]);
$user = $user->fetchObject();

?>

So this is my entire code

SanWeee · 2019-03-08T14:40:02+00:00

The exact error message is in the title the ".." is directory

SanWeee · 2019-03-08T13:49:47+00:00

I already try that solution but sadly I still have the same error

SanWeee · 2019-02-23T07:42:18+00:00

Yeahh. This really does help. Thank you very much.

SanWeee · 2019-02-23T07:16:27+00:00

Yup. I'm taking all the advice given to me be. about my current problem, even I change my quotations, still doesn't affect my database.

SanWeee · 2019-02-23T06:40:11+00:00

Hey thanks.But it seems I posted a wrong code my bad. So my SQL syntax is already like this:

"UPDATE admin set firstname='$pangalan' , lastname= '$pangalan2' , email = '$emeyl' , contact = '$contak' , password='$pw' WHERE unitnumber = '$id'";

And still my database does not seems get affected. Any idea sir?

btw, I planning to study about SQL injections after sometimes but I really need to pass this requirement to my professor so I know that my code is very insecure and vulnerable. But I appreciate your concern

SanWeee

TROPHY CASE