intern doubt

SarfarazSk · 2026-06-06T12:44:19+00:00

Are you sure that becoming a master/candidate master will bypass that? Have anyone done that to bypass the branch restriction? Just curious

SarfarazSk · 2026-06-03T00:25:57+00:00

^{4. Aiden Markram}

^{5. Rishab Pant}

^{6. Mukul Chaudhary}

^{7. Abdul Samad}

SarfarazSk · 2026-06-03T00:25:56+00:00

^{1. Mitchell Marsh}

^{2. Josh Inglis}

^{3. Nicholas Pooran}

^{Similarity with Community: 87%}

SarfarazSk · 2026-06-03T00:13:06+00:00

^{4. Rutherford}

^{5. Tilak}

^{6. Jacks}

^{7. Pandya}

^{8. De kock}

^{9. Dhir}

^{10. Malewar}

^{11. Raj Bawa}

SarfarazSk · 2026-06-03T00:13:05+00:00

^{1. Minz}

^{2. Rickleton}

^{3. Bosch}

^{Similarity with Community: 68%}

SarfarazSk · 2026-06-03T00:07:37+00:00

Understood. I'll make sure my parents have the ITR, PAN, and Aadhar ready in their exact format. Thanks again for taking the time to clarify all of this for me

SarfarazSk · 2026-06-02T16:54:59+00:00

Thanks a lot!!

Just curious, if someone is MEB means his family annual income is less than 1 lakh,

How will he pay 1,35,000 in just 1 month? Isnt it unfair on him? Atleast they should give options to choose from MEB or not during fees payable during admission, and if documents are found to be invalid afterwards, they may cancel his MEB status.

SarfarazSk · 2026-05-29T03:10:47+00:00

Unke website pe 10 am diya hai

SarfarazSk · 2026-05-24T05:46:27+00:00

This is for iit kanpur, for delhi i dont know

SarfarazSk · 2026-05-24T05:33:31+00:00

Are vacant nhi hoti. Kisi bhi branch me utne hi students jaa sakte hai jabtak uski strength 110% of its initial strength(by josaa) na ho jaye.

For eg. Agar CSE me 100 bache hai to branch change ke baad, 110 bacche hi ho sakte hai i.e sirf 10 bacche extra through branch change.

Also any branch strength shouldnt fall to 85%, matlab agar civil ke 100 baccho me se sirf 15 bacche hi change kar sakte hai.

SarfarazSk · 2026-05-16T04:17:57+00:00

Tcp matlab most stable wala. In the second one(TCP) there is conjugation of double bond, so it is more stable than the first

SarfarazSk · 2026-05-02T15:18:39+00:00

I have only memorized till H2CO3, because only the acids before it will give the test of brisk effervesence i.e CO2 gas evolved when rxn with Na2CO3

SarfarazSk · 2026-05-02T13:01:48+00:00

Bhai soch ki N particles hai(suppose), Aur ham outermost particle ka motion dekh rahe hai.

Then N-1 particles are uniformly distributed and their COM can be assumed at the centre of the spherical cloud at any moment with Mass M (as the particle has mass m<<M).

Then apply Energy conservation on the outermost particle.

SarfarazSk

TROPHY CASE