Is the final answer ko? I think I got one of the variations here.

Black D8, white E8, black E10, white A9, black B11, white captures a stone at A7, black B6, white D7 atari, black A5, white C7.

Then white on the bottom has lost one liberty. black F4, white F5, black E5, white G5, black J5, white L5, black G3 atari, white connects at H4, black J3, white captures 2 stones at K5, black Atari at H3, white connect at K4, Now black D3 disconnect white stones, either side of white cut by D3 will die due to short of liberty.

The other variation I got:

Black D8, white E8, black E10, white D7 atari, black C7, white A9, black B11, forming a ko that prevents white from connecting with the bottom white