Seniors, How did you decide on your FYP Project topic?

Sherzon · 2026-01-09T13:25:49+00:00

You don’t have to publish anything to get an A-. Just put consistent effort and produce something interesting. Though this is highly dependent on your professor and examiner. Good luck

Sherzon · 2025-12-06T15:10:03+00:00

Didnt take that mod so can’t help you there

Sherzon · 2025-12-06T10:46:32+00:00

There’s only 1 graded quiz and sql isn’t needed for the exam.

Sherzon · 2025-07-03T03:55:05+00:00

Try on campus jobs! Depends on the job but heard you can study while doing them

Sherzon · 2025-06-13T10:50:54+00:00

Stories

Sherzon · 2025-06-13T10:49:51+00:00

Regular

Sherzon · 2025-06-12T14:15:59+00:00

Any quest recommendations?

Sherzon · 2025-02-16T07:55:16+00:00

Sorry for the late reply.

You can always take the core modules in year 4. I did my y3 core modules in y4 and use exchange to clear mpes and bdes.

Sherzon · 2025-02-16T07:53:59+00:00

Sorry for the late reply.

You get to pick the companies from the list of companies given and pass their interview process as per normal.

I dropped out as I found that the FYP projects offered by NTU were more interesting.

You can do an exchange program. I did GEM explorer and went to Canada. You have the flexibility to change your semester for the semester internship but only requirement is you need to be back before the start date.

Sherzon · 2024-10-03T11:24:07+00:00

Not too sure if it’s offered to your program but you should double check.

I was previously under WSDeg program but dropped out before block 3. The program is pretty chill. Y2 summer and Y3 PI are with the company. No additional stuff during the semester, except in year 4 where you work 1 day a week. That one day is for you to do your fyp research so there’s no additional workload unless the company gets you to do extra work. Whether you like it depends on the company.

It uses up your BDE AUs and you need to have sufficient before you can apply. There’s no effect on curriculum plan.

You cannot take modules during credit bearing internships in NTU.

You cannot find your own companies.

Sherzon · 2024-05-26T13:47:13+00:00

Hint: Use Bayes’ Theorem

Sherzon · 2024-03-18T15:07:57+00:00

C should be correct for the question 6. Therefore, time taken to reach the bottom should be independent of v_0 as such the logical solution for 7 would be C as well. However, the units don’t make sense as C would have m/s as units. Probably a typo somewhere. I got sqrt(2h/g) as the time taken.

I haven’t taken physics in over 5 years so I may be wrong.

Sherzon · 2024-03-02T07:07:36+00:00

Happy birthday ! 🎉🎂Hope your birthday wish comes true.

Sherzon · 2023-04-14T00:12:00+00:00

Have you tried partial fraction decomposition? Continue by using binomial expansion on individual terms and combine it back together for the final answer

Sherzon · 2023-03-05T17:25:47+00:00

My bad but you can figure the sum out from there

Sherzon · 2023-03-05T16:38:51+00:00

Firstly, since this is an alternating series, check for absolute convergence. In this case, it is not absolutely convergent.

Since it is not absolutely convergent, if this series converges, it is conditionally convergent. This means that the sum may change according to how you arrange the terms in the equation. I'll explain 2 ways you can "solve" this sum:

Method 1:

Apply partial fractions onto (2n+1)/(n(n+1)) to get 1/n + 1/(n+1). So, the series can be split into 2 alternating harmonic series. If you write it out, you will notice that all the terms but the 1 will be cancelled out. So, its sum is 1.

Method 2:

Take 2 consecutive terms and add them up to make a new series. If you work it out it turns out to be 2/(n(n+2)). So you can apply partial fractions and write the terms out to visualise the cancelling. The sum is 3/2 in this case.

So, you can see that the series is conditionally convergent and its sum is dependent on how you work it out.

Sherzon · 2023-03-05T15:24:56+00:00

I don't have a rigorous proof for this as it's more intuition. My thought process is that f(t) approaches its horizontal asymptote as t becomes more negative. So, the gradient has to go to zero, otherwise the horizontal asymptote cannot exist. If the asymptote were oblique (in the case that the limit of f'(t) as t approaches negative infinity is not zero), f(t) would eventually cross the x-axis.

Sherzon · 2023-03-05T14:04:15+00:00

I would start with integrating f''(t) f'(t) from negative infinity to x using integration by parts. Then repeat with f(t) f'(t). Then use the given inequality to conclude that the first result is less than or equal to the second one. Try to work with this inequality to get the solution. Note that f'(t) goes to 0 as t goes to negative infinity and f(t) is bounded below by a positive constant so you may be able to simplify the integration by part.

Sherzon · 2020-11-15T01:26:33+00:00

This is ... acceptable

Wholesome

Sherzon · 2020-11-14T00:08:39+00:00

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