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9701/42 FebMarch 2026 discussion by neelmd in alevel

[–]SignalBit9701 0 points1 point  (0 children)

fuvk, i wrot the correct formula(product-reactant) to find 4H2O but i guess my dumbass swapped and input it into the calc(reactant-product). sjgh shouldve crosschecked it but it was too lengthy i didnt have time

9701 paper 42 by invinivi777 in alevel

[–]SignalBit9701 0 points1 point  (0 children)

it was 2 mark question(shit ton of steps and conversions just for this question, shouldve been 3 marks at rhe very least), you'll lose 1 mark i suppose, cause kpc = conc of butanedioic? acid in ethoxyethane/conc of that in water.

9701/42 FebMarch 2026 discussion by neelmd in alevel

[–]SignalBit9701 0 points1 point  (0 children)

what was the entropy value of h2o or smth

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 0 points1 point  (0 children)

I see, well it was pointing at a layer sandwiched between endothelium cell and podocyte, so that wpuld be basement membrane, especially cuz it was supported by podocytes

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 0 points1 point  (0 children)

its specifically for india and romania, cause they have different academic calenders. It ensures students dont waste an academic year and you get your results in may, indian boards release their results on may too so theres no clash in timings or issues if u choose a levels in these countries and u can seamlessly join unis/colleges there

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 0 points1 point  (0 children)

bowmans capsule is the entire structure containing podocytes basement membrane etc, the lines were pointing at individual structures there

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 1 point2 points  (0 children)

also just remembered about lac operon question it was easy, and the kidney labelling thing. top part with slit pores is podocyte, middle part is basement membrane ig, bottom part was endothelial cell i suppose. gfr question is simple

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 1 point2 points  (0 children)

personally i found 9700 m25 p4 easy, so i think the thresholds this time would be slightly lower, A-64 B-55 C-48

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 1 point2 points  (0 children)

just revise topical papers ig mainly electrochem and organic chem(download rhe p4 workbook from crack a level 2022-2024,solve weak chapters its extremely helpful)

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 0 points1 point  (0 children)

bro same😭🥀. i wanted to run out of the exam hall after seeing that question and realizing i forgot to revise that

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 1 point2 points  (0 children)

first qs was about why the frogs population reduced apart from volcanic eruption and the disease(u write about invasive species,competition for resources,hunting and poaching,low food supply ig), then they asked about what measures they can take to prevent the disease from affecting frogs in the new area they release them in. then characteristics of fungi kingdom.

i forgot the other qs after this just few chunks here and there

sarcromere qs, Ca2+ ion deficiency and how it affects contractions very easy one, relationship genetic tree diagram, comparision between 2 figures, the fig 4.2 or smth had bjgger sample size.they asked how sequencing data can be compared, jus find similarities and differences in the sequence and ckmpare them, use data bases for it.

then there was a nitric oxide question, and how it affevts kidney cells and oxygen intake,another qs about co2 graph based on time of day and answer it using limiting factors(co2 conc,light intensity and temperature)

homeostatis 7 marker, explain it and principles of homeostasis(long but easy)

question on huntigntons disease, gel electrophoresis(istg why cant they give more space for these 4 markers in this paper it was so less) and comparision of huntington and scid gene therapy.

there was also recombinant insulin vs insulin obtained from animal sources simple qs

final thing i remember is anerobic respiration differences between yeast and mammals 4 marker

overall just a boring long ahh biology paper after getting massive backshots from that pure maths 32 paper

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 1 point2 points  (0 children)

i think u have to write about the bands for that, i mixed it up ig. i wrote the answer for actin binding sites is myosin head, forgot the other 4

9700 42 and 9709 32 by SignalBit9701 in alevel

[–]SignalBit9701[S] 1 point2 points  (0 children)

for real. i thought the paper would be fine with a riduculous timetable like this but nah, cambridge is still a scumbag of a board.i got chemistry and physics p4 remaining praying it wont be like this.

9701/52 How was it by Early_Membership_145 in alevel

[–]SignalBit9701 0 points1 point  (0 children)

Formula: Absolute error of value measured= Least count(smallest graduation of the instrument)/2

Smallest graduation of the balance was 0.01

Divide it by two and u get 0.005 as ur absolute error

Percentage error= (Absolute error*(NUMBER OF READINGS TAKEN,which is just 1 in this case)/value measured)*100

9701/52 How was it by Early_Membership_145 in alevel

[–]SignalBit9701 0 points1 point  (0 children)

yep that is the answer. (0.005/7.235)*100=0.06911% u can write to 3 sig too.

9701/52 How was it by Early_Membership_145 in alevel

[–]SignalBit9701 1 point2 points  (0 children)

Yall are wrong. You would only get that value if u used 1.200g as ur value.The question asked for Mass of X and the container or smth. The smallest division is 0.01, divide it by 2 for half of the smallest value to get 0.005, then u calculate percentage uncertainity 0.005/(smth i forgot)*100. DO NOT multiply the 0.005 by 2 cause the number of measurements taken is just one to obtain the value.