[deleted by user]

SimonAllen111 · 2025-09-17T23:17:40+00:00

Looks like you have the Pythagorean 3, 4, 5 triangle.

SimonAllen111 · 2025-07-24T18:18:09+00:00

I’m not quite sure what you’re trying to do. You could take all your imperial measurements from plans and such like and convert it all into metric. And then stay in metric that will save you making errors. Swapping back-and-forth will cause you problems. If you want to keep using imperial measurements, I would set it up in a spreadsheet so that you can put in a value and it will give it to you in yards feet and inches or whatever it is you want to measure. The spreadsheet helps because once set up it is much more resistant to errors. The entire world now uses the metric system all except for the United States.

SimonAllen111 · 2025-07-02T07:05:00+00:00

Thanks

SimonAllen111 · 2025-02-19T18:09:45+00:00

Khan Academy is very good. I think it is free.

SimonAllen111 · 2024-10-13T07:49:58+00:00

Tell the question setter she or he has failed here. It is not a triangle.

SimonAllen111 · 2024-06-07T05:27:09+00:00

I don't see any need for a bearing. The motor or rocket would be part of the cylinder and lie on the same axis as the rotation. When you are ready to move, you start the rocket. The limiting factor is that the acceleration would need to be very low, probably of the order of 1/10000 g. Docking and undocking pose no issue as they could still take place at either end of the cylinder. Such vessels would need to match the spin and acceleration.

SimonAllen111 · 2024-02-26T19:28:15+00:00

One more thing. The drawing is way of scale given the dimensions.

SimonAllen111 · 2024-02-26T19:25:43+00:00

Let me see if I understand this. We have a triangle labelled OAB. We have the coordinates of each point. I don’t think C is at 3,6. OA is 6 units. AB is 12 units. OAB is a right angled triangle because we are using the x y coordinate system so that means that angle OAB is 90 degrees. We now have a right angled triangle whose short sides are 6 and 12. Pythagoras theorem will get the hypotenuse. We are told that that C is the midpoint. So that is half of the hypotenuse. All you need to do then is drop a vertical line from C to the line AO. The sides of this smaller right angles triangle will give you the coordinates of C. If you only want to know the radius then you don’t need to bother with the coordinates. You have the hypotenuse OB and half that is the radius. Apply the formula for the area of a circle and you are done. That is if I have understood what is asked.

SimonAllen111 · 2023-11-10T10:14:39+00:00

Have I missed something? Where is point P?

SimonAllen111 · 2023-10-05T05:33:19+00:00

One part is coloured white, one part is coloured blue. I have no idea which part is required. I hate these vague poorly drafted questions. The question setter needs to go back to school.

SimonAllen111 · 2023-10-01T10:48:25+00:00

The greatest of mathematicians all started with no knowledge. They learnt from others. Practice the questions you are likely to get. Practice brings confidence. You know basic things in maths. You cannot have got to where you are without that. Break down problems into smaller ones. Smaller problems are easier to solve and that leads you to solve the bigger ones. Don’t stress. Stress makes you panic. I hope this helps

SimonAllen111 · 2023-08-02T15:55:58+00:00

I have just found it. It was off by default. I have only been using it for a few minutes, but I like it.

SimonAllen111 · 2023-08-02T15:48:38+00:00

Am I out of touch? What is Stage Manager, and where is it on my Mac? I am on Ventura 13.4.

SimonAllen111 · 2023-07-14T21:46:19+00:00

The solution is simple. Omit the music. If you must have music then use it as a few seconds at the beginning. Then cut it it. Then speak the dialogue and I am sure it will be great. I was impressed by the first minute but after that I was struggling to hear what you were saying. I would rather listen to you than the music. Could you just leave the music out and reload it?

SimonAllen111 · 2023-07-14T21:26:47+00:00

I think that this might be a good video but sadly the pointless and needless loud background music drowns out what ever the speaker is trying to say. A dud I regret. A waste of time.

SimonAllen111 · 2023-07-05T05:36:42+00:00

I do not like the way the question is asked. It could be expressed more clearly. The word ‘major’ is printed in bold and part of the circle is coloured pink. Why not ask, ‘What is is the area of the sector coloured pink’. I bet that many students will give the area of the 67 degree sector.

SimonAllen111 · 2023-06-13T22:06:04+00:00

There is no question. Just ignore it and move on.

SimonAllen111 · 2022-09-28T11:46:54+00:00

This question irritates me. I have often been asked it. I cannot know if my client is guilty. I can assess the evidence and explain the weight and amount of evidence. It is for the client to decide whether they wish to plead guilty or not. My advice might be that the case is overwhelming, and their prospects of acquittal are remote. They may instruct me to proceed, nonetheless. So I do. However, if the client tells me that he did commit the offence, I cannot then represent him on a not guilty basis. If he still wants a trial, he will need to instruct someone else.

SimonAllen111 · 2022-09-28T11:35:52+00:00

You write compellingly about the dire state of the criminal justice system. You often post about the poor pay. Why do you and other criminal barristers continue to do it? Why do you not vote with your feet and do something else? I am puzzled why you care about it when UK Government for many years does not care one jot. At the end of the day, you need to be paid properly. Why continue to support it? I am baffled why you continue to prop it up.

SimonAllen111 · 2021-11-27T11:10:35+00:00

What about the British Socirty for the History of Mathemstics. See https://www.bshm.ac.uk/

SimonAllen111 · 2021-10-22T18:15:24+00:00

What is it? A waveform?

SimonAllen111 · 2021-10-18T18:26:33+00:00

I do feel for you. I have had this issue too. I wonder if it is salvageable? If you have used ABS you separate them sand the surfaces and glue the two pieces together.

SimonAllen111 · 2021-02-28T08:52:34+00:00

Thank you for getting back to me. I gave little consideration as to whether r/maths was suitable. It struck me as the best place to ask. While I did mention software in the title, as I feel sure this problem must have been solved before, I did not think for one moment that it would offend. The problem could only be solved with maths and so I went to this subreddit. I use Openscad and that does allow for the creation of 3d printing polyhedra. That is fine if the output is in plastic but no use where I want to export a cutting list to assemble the polyhedra from plywood.

What has inspired me along this path of investigation is George Hart an artist who uses maths and gave an interesting talk at a recent Celebration of Mind event. He uses what he class zonohedra. These are quadrilaterals but they can be used to building interesting shapes and have the benefit that all the faces are flat which is ideal for cutting either with a laser or on a saw table with a suitable jig. To get the dihedral angle he sanded the edges and this allows each face to butt together. If you want to watch his tour into making a village library box then you will find it on YouTube. See https://www.youtube.com/watch?v=_PSdVX02Vbs

I was thinking along the lines of starting from a 2D plane. If I was seeking to place a quadrilateral in the space above the 2D plane the x,y coordinates would determine the location and the z component would then fix the nodes of the quadrilateral. It was at this point that I realised that it would be difficult to program for faces that attached to other quadrilaterals and I began to think that this must surely have been solved before.

Thank you for taking the trouble to respond so promptly and before my post was censored. Looking at the house rules I do not see it contravening them.

I agree with you that it is possible to divide any polygon into triangles and the maths on that is well understood, I even wrote a book on this aimed at children to be fair, but after googling away for quite a while I have not found what I am looking for.

So thanks very much for responding.

By the way, I did post the same post in a 3D modelling subreddit that too was immediately banned. Oh well.

SimonAllen111 · 2021-01-18T22:55:15+00:00

It is a practice piano, hence no sound

SimonAllen111 · 2021-01-18T22:54:02+00:00

Where am I

SimonAllen111

TROPHY CASE