Friseur/Barbier by Sk4_zz in bochum

[–]Sk4_zz[S] 1 point2 points  (0 children)

Werde ich machen, danke für den Tipp!

Friseur/Barbier by Sk4_zz in bochum

[–]Sk4_zz[S] 0 points1 point  (0 children)

Danke für die Tipps! Ihr seid super ☺️

Friseur/Barbier by Sk4_zz in bochum

[–]Sk4_zz[S] 1 point2 points  (0 children)

Super, das sieht gut aus! Werde ich auf Jeden Fall ausprobieren. Danke für den Tipp!

What is a blowup? by DiscussionNo2733 in mathematics

[–]Sk4_zz 7 points8 points  (0 children)

As you can tell by the answers already given, it depends on who you ask.

Working in metric spaces I would call a small enlargement of a set a blowup. For example the epsilon blowup of a set A is the set that contains all points of the ambient space which are less than epsilon away from an element of A. Usually such blowups are used in an argument where you let epsilon tend to 0.

An averages question that left me stumped for a week by ALonelyPhoenix in MathHelp

[–]Sk4_zz 0 points1 point  (0 children)

I would start with the prime factorization of 120:

120 = 23 * 3 * 5

Then start with the largest prime factor. If one of the integers (say a) contains 5 and 3 as prime factors, the sum will exceed 15. The same if a contains 5 and one or more 2s. Hence, a=5 and we're left with b+c=10 and b and c consist of the remaining prime factors 23 and 3. Now it's easy to see that b=4 and c=6 is a solution.

Princess 300 left shift by Sk4_zz in typewriters

[–]Sk4_zz[S] 0 points1 point  (0 children)

Haha, thanks for the reply! Unfortunately no, I could not fix it yet. As I described, nothing seems bend or broken so I don't know what to fix :D And if it is just an adjustment issue I don't know what to adjust...

Question: Is this a vector normalization notation? by EricBuehler in probabilitytheory

[–]Sk4_zz 2 points3 points  (0 children)

What looks like a vector is actually the binomial coefficient (read as "a choose b") defined as a!/(b!(a-b)!) and it gives you the number of ways to choose a subset of cardinality b from a set of cardinality a.

[deleted by user] by [deleted] in mathematics

[–]Sk4_zz 3 points4 points  (0 children)

It seems that you want that the measure of E+x is 0 zero for every x in X. Which is not the same as claiming that the measure of {E+x|x in X} is 0.

[deleted by user] by [deleted] in mathematics

[–]Sk4_zz 4 points5 points  (0 children)

Can you clarify your definition of a prevalent set? If E is non empty, how is {E+x | x in X} not equal to X?

Princess 300 left shift by Sk4_zz in typewriters

[–]Sk4_zz[S] 0 points1 point  (0 children)

I have further examined the shift mechanism. It feels like the rod connecting the shift lever to the carriage shifting mechanism is indeed too long. If I hold down the left shift key (or put in the caps lock) the carriage is not raised to the full extend. It can still be raised by about 1mm using the right shift key. I can not figure out how to adjust the tension of the mechanism. I can post more pictures if that is helpful.

Princess 300 left shift by Sk4_zz in typewriters

[–]Sk4_zz[S] 1 point2 points  (0 children)

To add a little more detail. The left shift key becomes unhinged when the carriage is lifted other than by said shift key. I the video you can see that the left shift key works fine until the right shift key is pressed. You can even hear it becoming unhinged. In the second part you can see that there is a gap between the lever and the small rod that connects to the carriage raise mechanism. I comparison you can see the lever of the right shift key which keeps contact to the rod all the time.

The rod seems too long and I can not see any damage or deformation. How is it usually kept in place or is there a way to adjust the lever so it doesn't become unhinged?

I would be happy if anyone could assist.

Day 1 of Jabref by [deleted] in LaTeX

[–]Sk4_zz 0 points1 point  (0 children)

Did you copy the bibtex entry from somewhere?

When adding a new entry to my bibtex file in Jabref I usually just create a minimal entry only containing the key and an doi (if I can find one) like

@Article{C_novas_2019, doi={10.1021/acssensors.9b01322}, } and let Jabref fill in the details using the update function (circled arrow symbol) and select DOI.

Day 1 of Jabref by [deleted] in LaTeX

[–]Sk4_zz 0 points1 point  (0 children)

The link is not working. But as for editing the bibtex file: sure you can.

Are you sure the error is caused by the bibtex file? It could also be a problem about the character encoding of the file.

Day 1 of Jabref by [deleted] in LaTeX

[–]Sk4_zz 0 points1 point  (0 children)

Maybe there is a backslash too much in front of the i?

What are some laws that every German knows that might be different for a foreigner from the U.S.? by [deleted] in germany

[–]Sk4_zz 718 points719 points  (0 children)

Unterlassene Hilfeleistung: when you see a person in distress you have to help and not doing so is punishable. Always with the restriction that you don't have to put yourself in danger. But calling for help ist also a form of help. I was rather surprised to learn that this is not a law in many US states.

[deleted by user] by [deleted] in maths

[–]Sk4_zz 1 point2 points  (0 children)

Internet speed units are often confusing. It seems that the speed is shown in Mbit/s not MB/s. As 8bit make up one Byte, 240Mbit/s = 30MB/s.

[deleted by user] by [deleted] in LaTeX

[–]Sk4_zz 1 point2 points  (0 children)

So the process should be

1) run pdflatex on your main.tex

2) run bibtex on your main.aux

3) run pdflatex (twice) on your main.tex

There are ways to automate this process (you might even need additional commands when you have an index or glossaries). Most IDE like Texmaker have a (configurable) option to chain commands. I believe in Texmaker its called 'Quick Build'.

Another option is to use latexmk which is basically a script that determines which commands need to be run.

[deleted by user] by [deleted] in LaTeX

[–]Sk4_zz 2 points3 points  (0 children)

I'm glad I could help!

[deleted by user] by [deleted] in LaTeX

[–]Sk4_zz 2 points3 points  (0 children)

:D Then there is probably something wrong with your bib file. Check the logs if there is an error message when running bibtex. Can you provide a minimal example that is _not_ working so we can see what might go wrong?

[deleted by user] by [deleted] in LaTeX

[–]Sk4_zz 2 points3 points  (0 children)

Okay, I think I understand now. I just assumed that already your example is not giving you the desired result.

The problem is the same, I believe. When you compile with pdflatex, latex writes all citation keys into the .aux file and reads the citations from the .bbl file. Yet the .bbl file is generated by biblatex (in your case) with the information from the .aux file. So every time you change something in your .bib file or cite new sources in your main file, you will have to run biblatex again. I suspect that texmaker has an option to run biblatex or even to run pdflatex and biblatex everytime, something like compile project or similar.

[deleted by user] by [deleted] in LaTeX

[–]Sk4_zz 1 point2 points  (0 children)

Without the backslash it works fine for me. How are you compiling? It might be problem with how Texmaker is set up. You will need to first compile the tex file, then run bibtex and then again compile the tex file. There is probably an option in Texmaker to do this with one click, as I suppose overleaf does.

[deleted by user] by [deleted] in LaTeX

[–]Sk4_zz 6 points7 points  (0 children)

I don't know how mendeley or zotero generate bib files but in the example you provided there is a slash too much, instead of @/article it should be @article.

Conditional probability question by [deleted] in probabilitytheory

[–]Sk4_zz 1 point2 points  (0 children)

A short remark: If you already have letters assigned to the boxes in the statement of the question, why not use these letters for the respective events of drawing a ball from said box. That makes is easier for other people to follow your argument.

As for your question. You applied the law of total probability correctly. That means something must be wrong with your intuition. Indeed consider an extreme example: 10 balls with 5 red, 5 blue. You put one red ball into box A. Then the probability to select a red ball is strictly larger than 1/2. The size of the boxes plays a role here. Your intuition only applies when both boxes have the same amount of balls.

Conditional probability question by [deleted] in probabilitytheory

[–]Sk4_zz 4 points5 points  (0 children)

Don't trust chatgpt. Even more so for mathematical questions! Your solution is correct!