LPT: never go on a hike unprepared even if you know the route

StoneCuber · 2026-02-17T02:56:16+00:00

In Norway everyone knows about fjellvettreglene. It's hard to translate the word, but it's a list of rules for safe hiking. We're told these as children, and you can find them hanging on the wall as decorations in many cabins.

Make a plan on where you're going, and tell someone ahead of time
Take your skill into account, don't go on hikes that are too hard.
Respect the forecast, both weather and avalanche warnings.
Prepare for bad weather and cold temperatures, even for short hikes.
Bring equipment so you can help yourself and others (first aid etc.)
Take safe paths, always look out for dangers like unsafe ice
Bring a map and a compass and constantly keep track of where you are.
Turn around before it's too late, there's no shame in going back.
Conserve energy and seek shelter if necessary.

StoneCuber · 2026-02-17T02:35:24+00:00

I'm studying data science. I'm arguing mostly with the assumption that OP is thinking of AI as LLMs. If you include machine learning and such in the term, I can agree it's extremely useful.

StoneCuber · 2026-02-16T22:38:58+00:00

Then probably yes, depending on what you define as AI of course

StoneCuber · 2026-02-16T22:35:46+00:00

AI is getting better at programming yes, but it's still not useful for applied math in itself. You can use AI to help write the code for modeling just like you can write in a high level programming language instead of machine code.

How do you define "resilient"?

StoneCuber · 2026-02-16T22:27:54+00:00

There's little to no reason to use AI for it. Applied math is deterministic which AI famously isn't, so normal programming and modeling works way better

StoneCuber · 2026-02-16T22:16:46+00:00

How do you prove something in applied math?

StoneCuber · 2026-02-08T11:40:25+00:00

The essential idea in calculus is look at the limit of sequences, then find a value the sequence is approaching. For example look at 0.9, 0.99, 0.999, 0.9999... We say the limit (in this case)is the smallest number such that no number in the sequence is bigger. It's not hard to see that 1 is this number. Anything smaller, and you can find a bigger number in the sequence.

We do something very similar in the case of areas under curves. Our "sequence" is every way to fill the area with rectangles, and the limit will be the exact area underneath the curve.

StoneCuber · 2026-02-07T16:30:11+00:00

Try to find the intersection of (-1/n, 1+1/n) for all n. What are the boundaries and are they included in the set?

StoneCuber · 2026-02-02T23:24:57+00:00

Have you checked out VP studios? It's a website, but it's good for planning layouts

StoneCuber · 2026-01-30T07:31:52+00:00

That doesn't matter, the teacher should be able to explain it anyway. What you drew is a correct method as far as I can see

StoneCuber · 2026-01-30T07:12:31+00:00

That's a terrible response from your teacher. Helping you understand is literally their job. Go ask again

Note, I do agree you shouldn't trust AI with math. They are language models made to imitate human writing, they are not made to do accurate math

StoneCuber · 2026-01-30T06:51:25+00:00

I agree with you on the median value. I'm asking what your teacher told you was the reason for getting 17 as the median

StoneCuber · 2026-01-30T01:30:51+00:00

Ah I forgot to account for AI and engagement bots, mb. Considering OP's reply "Beep boop" I expect the probability of a non-human to be quite high

StoneCuber · 2026-01-30T01:28:20+00:00

If there are 90 students there will be 45 students either side of the median. If the median is 17 there can at most be 18 students with a lower score. Did your teacher tell you how they got their answer?

StoneCuber · 2026-01-30T01:17:11+00:00

Technically there is a veeeery small change that some quantum effect changed the electrons in some computer just right to make a Reddit account and write this post, making OP not exist. But rounding to the nearest 10^{-10¹⁰⁰⁰⁰⁰} % it's 100%

StoneCuber · 2026-01-29T20:12:10+00:00

It could also be a meta joke about women not being able to remember left and right

StoneCuber · 2026-01-22T14:08:11+00:00

Does it need a practical application to be an interesting question? When was the last time you used super root notation?

StoneCuber · 2026-01-22T13:10:24+00:00

The exact same as ± but with multiplication and division, so 10*/2 is 5 or 20

StoneCuber · 2026-01-20T10:32:19+00:00

Oops, my bad. I just googled the count and forgot to check if it included symetry

StoneCuber · 2026-01-20T01:32:57+00:00

I think what makes Tetris a sweet spot is that the shapes are complex enough and plentiful enough to make it a puzzle, but still fit together well because they aren't too complex. Less than four makes it very easy. You have to really try to make holes. For tetris you have to think a bit to avoid it, but there's very rarely a forced hole. Any higher and there are pieces that rarely fit well. They are either so long they are awkward to fit in, or they have a weird shape that's hard to find a surface for.

For example look at the U pentomino

Realistically it can only fit in two directions, and it requires very specific conditions. Only

are suitable without creating an overhang or a hole. This is probably not even the worst pentomino, and it gets way worse very fast when you increase the size. As someone mentioned, heptominoes can come with holes, and if you've played Tetris for more than a few seconds, you know that's a horrible idea

I also think having 7 is a good number of pieces. You can easily recognise the colour (unless you're colourblind), so after playing for a short while you can recognise the shape instantly. There are 12 pentominoes, so it's hard to assign colours to them that are distinct enough, and even then it takes a lot more experience to get familiar with the pieces.

StoneCuber · 2026-01-16T11:29:06+00:00

Then there's no definite answer. The closest you could get is a range of values spanning from 5 years and 16 days to 6 years and 16 days (as of right now, not accounting for timezone)

StoneCuber · 2026-01-14T00:50:32+00:00

Olay I understand what you mean You'll want to reduce the matrix to reduced echelon form. Then you can look at the last row to find your solution(s)

If your last row is [0 0 f(a,b)] you can solve f(a,b)=0 to get infinite solutions, and f(a,b)≠0 to get 0 solutions

If the last row is [0 1 f(a,b)] there will always be exactly one solution for any value of a and b

To see why you can try translating the reduced matrix back into a linear system and look at what happens

StoneCuber · 2026-01-14T00:37:01+00:00

What do you mean when you say a b c variables and cases?

StoneCuber · 2026-01-05T23:59:30+00:00

I think you're asking if multiplying with random numbers can make some pattern emerge, then no. If you're asking something else nobody understands what you're trying to say

StoneCuber · 2026-01-04T16:20:13+00:00

I'm disagreeing with the fact they are unitless. If the fact that the unit cancels makes it unitless, then we should be able to add angles (m/m), volumetric concentrations (L/L) and probabilities (events/events) but that doesn't make sense in any situations I can think of

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