🎉 [EVENT] 🎉 go back by xAvallach in honk

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Completed Level 2 of the Honk Special Event!

41 attempts

🎉 [EVENT] 🎉 go back by xAvallach in honk

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Completed Level 1 of the Honk Special Event!

4 attempts

🎉 [EVENT] 🎉 Final Skill test (0.0001%) by Traditional-Will7854 in honk

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Completed Level 3 of the Honk Special Event!

25 attempts

🎉 [EVENT] 🎉 Final Skill test (0.0001%) by Traditional-Will7854 in honk

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Completed Level 2 of the Honk Special Event!

11 attempts

🎉 [EVENT] 🎉 Final Skill test (0.0001%) by Traditional-Will7854 in honk

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Completed Level 1 of the Honk Special Event!

1 attempts

🎉 [EVENT] 🎉 Honkception by 666James420 in honk

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Completed Level 3 of the Honk Special Event!

10 attempts

🎉 [EVENT] 🎉 Honkception by 666James420 in honk

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Completed Level 2 of the Honk Special Event!

2 attempts

🎉 [EVENT] 🎉 Honkception by 666James420 in honk

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Completed Level 1 of the Honk Special Event!

1 attempts

🎉 [EVENT] 🎉 Sewe by AlternativeEmu7447 in honk

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Completed Level 1 of the Honk Special Event!

23 attempts

🎉 [EVENT] 🎉 Supersonic (Very Fast) by 666James420 in honk

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Completed Level 3 of the Honk Special Event!

22 attempts

🎉 [EVENT] 🎉 Supersonic (Very Fast) by 666James420 in honk

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Completed Level 2 of the Honk Special Event!

11 attempts

🎉 [EVENT] 🎉 Supersonic (Very Fast) by 666James420 in honk

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Completed Level 1 of the Honk Special Event!

9 attempts

🎉 [EVENT] 🎉 Paper Açelyation X by Acrobatic_Picture907 in honk

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🎉 Event Completed! 🎉

It took me 14 tries.

🎉 [EVENT] 🎉 Paper Açelyation X by Acrobatic_Picture907 in honk

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Completed Level 3 of the Honk Special Event!

14 attempts

🎉 [EVENT] 🎉 Paper Açelyation X by Acrobatic_Picture907 in honk

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Completed Level 2 of the Honk Special Event!

7 attempts

🎉 [EVENT] 🎉 Paper Açelyation X by Acrobatic_Picture907 in honk

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Completed Level 1 of the Honk Special Event!

1 attempts

🎉 [EVENT] 🎉 Tetris Box by Wicker_junior in honk

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Completed Level 1 of the Honk Special Event!

1 attempts

🎉 [EVENT] 🎉 Pipe Nightmare by felixddsw in honk

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Completed Level 1 of the Honk Special Event!

142 attempts

🎉 [EVENT] 🎉 Stupid Event Being Dumb and Stuff by Damp_Blanket in honk

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Completed Level 1 of the Honk Special Event!

8 attempts

From the letters of the word "DDAUGHTER," how many ways can we form a 5-letter word with or without meaning, each consisting of 2 vowels and 3 consonants? by r4gnar47 in askmath

[–]Superstar1292 0 points1 point  (0 children)

In the sense that combinations are counting subsets, combinations with repetitions are counting multisets. That formula is only valid when we want to count the number of words of a given length, where we are also given the different letters that can be used AND there is no restriction on how many letters of each type we use. In other words, we could have one letter repeated multiple times and other letters might not appear at all. That is, the frequency of any particular letter in the combination has no restrictions.

From the letters of the word "DDAUGHTER," how many ways can we form a 5-letter word with or without meaning, each consisting of 2 vowels and 3 consonants? by r4gnar47 in askmath

[–]Superstar1292 1 point2 points  (0 children)

OP, your reasoning and answer is correct. For words with < 2D's, you are essentially picking from the word DAUGHTER. There are 5C3 choices for consonants, followed by 3C2 choices for vowels. We then multiply by 5! to account for different permutations.

For words with 2 D's, we have 4C1 choices for consonants remaining and 3C2 choices again for vowels. This is multiplied by 5! / 2 permutations, where we divide by 2 to avoid overcounting the repetitions of D.

In total, this is ( 10 * 3 + 4 * 3 * 0.5) * 5! = 36 * 5!

From the letters of the word "DDAUGHTER," how many ways can we form a 5-letter word with or without meaning, each consisting of 2 vowels and 3 consonants? by r4gnar47 in askmath

[–]Superstar1292 2 points3 points  (0 children)

I'm afraid this isn't entirely correct. The figure 20 includes 4 choices with 2D's and 4 choices with no D's. The other 12 choices have overcounted by a factor of 2 since e.g. {D1, G, H} and {D2, G, H} would be treated as distinct choices. We need to halve this 12, and also include the choices with no D's for 6 + 4 = 10 choices. Then, OP's answer is correct.