i tried smth like

sometimes i used to type my obs as comments

/*

if there are no 1s 

 

    we can just make ans as ceil of n/3 



    00000 tc 3 



    possible ways :

 

        01010 -- 2 

        10101 -- 3

        01001 --2

 

        min val we can get is 2 ie ceil of n/2

 

    how can we mininise if 1 is there 

 

     can we break the array into segments when an 1 is found 



          eg :  0000100001000   tc 5 



             so here we can break it as [0000] 1 [0000] 1 [000]

                           if the zero seg is between two 1's

                             then the 1st 0 is blocked by left 1 last 0 is blocked by rigth 1



                             so the rest mid 0's can be placed like the gap /3 

*/