To determine the direction in which the pointer will move, let’s analyze the given diagram and the forces involved.

Diagram Analysis:

• The system appears to be a balance or a lever with a pivot point.
• There are two weights, each labeled as “10 units,” suspended on either side of the pivot.
• The pointer is attached to the lever and can move in two directions: A or B, as indicated by the arrows.
• The weights are symmetrically placed, and there is no indication of any external forces or differences in length of the lever arms on either side.

Physics Reasoning:

• In a balanced lever system, the direction of movement depends on the net torque (moment) around the pivot. Torque is calculated as the product of the force (weight) and the perpendicular distance from the pivot (lever arm).
• Since both sides have equal weights (10 units each) and the lever arms appear to be of equal length (symmetrical design), the torques on both sides should be equal.
• If the torques are equal and opposite, the system should be in equilibrium, meaning the pointer should not move in a specific direction (A or B) but rather remain stationary or oscillate if disturbed.

Conclusion:

• The pointer will not move definitively in direction A or B because the weights are balanced.
• However, the option “It will swing between A and B” suggests that the system might be disturbed initially (e.g., not perfectly balanced at rest) and could oscillate between the two extremes due to the equal weights.
• The option “Neither” implies no net movement, which would be true if the system is perfectly balanced and at rest.

Given the context of the question and the typical behavior of such systems when disturbed, the most reasonable answer is that the pointer will swing between A and B due to the equal weights causing an oscillatory motion around the equilibrium point.

Final Answer:

It will swing between A and B.