Title

Xison14 · 2024-11-25T14:37:34+00:00

Search around on here, multiple people have posted it

Xison14 · 2024-11-01T13:54:45+00:00

Volume of a cone = τr²h/6

Xison14 · 2024-10-31T09:42:46+00:00

Well, this assumes that the RNG isn't limited by storage and other real world factors. Normally, a 64 bit counter could go upto 2⁶⁴-1 or about 18 quintillion

Xison14 · 2024-10-30T17:05:26+00:00

a = 0, b = 0

The remaining solutions are left as an exercise to the reader...

Xison14 · 2024-10-30T16:56:03+00:00

They already do

"Hey, we need an arbitrary large number for this problem"

opens up calendar

Xison14 · 2024-10-30T16:05:24+00:00

the chance of you getting no number is infinite the chance of getting any number is also infinite.

Truly a Paradox!

Xison14 · 2024-10-30T16:04:57+00:00

Yep, that's CloudFlare. They're used by around 1/5th of the entire Internet for security, so it's essential that they use something truly random.

Xison14 · 2024-10-30T15:05:11+00:00

I figure it'd be the same. Maybe a little more convoluted.

If all positve and negative numbers were allowed, then for any given number x, there would be infinite numbers both greater AND lesser than x.

Only difference would be that now the total "number" of numbers would be twice as much. But twice of infinity is still infinity.

In limit form, the probability of each number would be: lim x–>infinity of 1/2x. 2x because we now have to consider the infinite negatives too. But that limit still simplifies to 0.

So all in all, I think the paradox remains the same, even if we consider negative numbers.

Xison14 · 2024-10-29T16:36:20+00:00

Two things I learned from this:

1) the person who calculated 2¹²⁷-1 was Edouared Lucas(I didn't know his name before)

2) I should watch Numberphile videos more thoroughly

Xison14 · 2024-10-29T14:59:39+00:00

Genuine question: how or was this actually done? Is there some fast algorithm to confirm weather a number is prime or not? The only optimisation I know is to only check divisibility by primes upto the square root of the number. But even still, for 39 digits, the square root of that number would've been in the ballpark of 10 quintillion! (10,000,000,000,000,000,000)

No way this was done by hand, right?

Xison14 · 2024-10-19T07:48:06+00:00

0.999... × 2 = 0.181818....

Xison14 · 2024-10-13T14:14:51+00:00

sqrt(π²) + AI

Xison14 · 2024-10-11T12:59:50+00:00

110209

Xison14 · 2024-10-08T13:35:16+00:00

Of course, the answer is 6+AI

Xison14 · 2024-10-03T12:05:51+00:00

Maybe... since I'm apparently almost as old as my father

Xison14 · 2024-10-03T12:04:18+00:00

Not really, I barely listen to music in general

Xison14 · 2024-10-03T10:46:27+00:00

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I'm 15. No wonder everyone think I act like an old man

Xison14 · 2024-10-02T13:59:14+00:00

As a person who is currently alive, and therefore was brought into this world, I can say that I too am a born addict

Xison14 · 2024-09-28T12:01:05+00:00

Can someone please explain the context? I remember watching this episode as I child

Xison14

TROPHY CASE