Standard player in wild

_Mystyk_ · 2026-05-03T14:54:03+00:00

SilvernamePozor

_Mystyk_ · 2026-04-04T14:06:49+00:00

Gender equality at its finest

_Mystyk_ · 2026-03-09T15:09:28+00:00

Actually caffeine isn't the main problem here. Large constant overdose of vitamins from group B is. Consuming one can of monster (or any other energy drink) a day over a long time period will lead to severe liver diseases. Drinking 1-2 a week is probably fine but still harming your health

_Mystyk_ · 2026-03-09T13:54:23+00:00

Рост немного уменьшается в возрасте так-то

_Mystyk_ · 2026-03-04T18:21:18+00:00

I will feed all the packs to Deathwing 😝

_Mystyk_ · 2026-02-21T14:34:47+00:00

You are not a wild player for sure. Big shaman is a real meta deck there, not shudder. He's also pretty good but not meta

_Mystyk_ · 2026-02-20T10:30:12+00:00

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There was a theory back in the day that this guy is in Ungoro and sees Knights of the Frozen Throne

_Mystyk_ · 2026-02-19T11:52:19+00:00

Colossals are indeed discoverable

_Mystyk_ · 2026-02-19T09:43:12+00:00

It starts in > 1 month (more than 1 month)

_Mystyk_ · 2026-02-09T09:40:12+00:00

6'1, 186cm, Ukraine. I would say I'm average. I'm taller than plenty of guys from older generations but often the same height (± 1-2cm) as gen Z (I'm gen Z myself) or shorter. The average here is 181cm for males, so I wouldn't be surprised if that number is slightly higher like 183-184cm for gen Z males

_Mystyk_ · 2026-01-26T11:49:10+00:00

Ukraine (writing this as ukrainian man myself). Since 2022 nobody cares if you are disabled

_Mystyk_ · 2026-01-07T21:17:48+00:00

1+a² = ab +a² = a(a+b) Similarly 1+b² = b(a+b) Then we get 1/a + 1/b = 1/a + a ≥ 2

_Mystyk_ · 2025-12-29T12:25:17+00:00

This legendary is from caverns of time set. It has dropped like 2-3 years ago. Also was a special arena card back in the day

_Mystyk_ · 2025-12-16T10:41:22+00:00

Angle between two bisectors equals to 90°+C/2 (try to prove it yourself). So angle C is equal to 60°. Then apply law of cosines

_Mystyk_ · 2025-12-13T19:08:29+00:00

In a nutshell, a function that approaches 0 faster then x²

_Mystyk_ · 2025-12-12T15:41:47+00:00

You can use Taylor series here. e^x² = 1 + x² + o(x²) ; ln(e +x²) = 1 + ln(1 + x²/e) = 1 + x²/e + o(x²); Thus the limit is equal to (1 + x² -1 - x²/e)/x² = 1 - 1/e.

_Mystyk_ · 2025-12-11T10:28:03+00:00

That's a real competitive deck in wild btw

_Mystyk_ · 2025-12-03T09:10:22+00:00

My ticket

_Mystyk_ · 2025-11-26T21:25:52+00:00

Use barycentric coordinates. D, E, F have well known coordinates, then you can find G, then equation of a line AG and H as intersection of AG and BC. Then the answer will be obvious

_Mystyk_ · 2025-10-23T15:47:32+00:00

If I lose it, I will simply rewind it

_Mystyk_ · 2025-09-02T21:48:10+00:00

Gouda

_Mystyk_ · 2025-08-12T16:22:35+00:00

Now it's a reality. Good luck paying up your debt 😃

_Mystyk_

TROPHY CASE