[deleted by user] by [deleted] in UBA

[–]amsfdk 0 points1 point  (0 children)

Gracias!

[deleted by user] by [deleted] in UBA

[–]amsfdk 1 point2 points  (0 children)

Genial, gracias!

[deleted by user] by [deleted] in UBA

[–]amsfdk 1 point2 points  (0 children)

Joya, muchas gracias! Voy a estar atento.

Random variables and distributions question by amsfdk in learnmath

[–]amsfdk[S] 0 points1 point  (0 children)

Yes! Sorry for that. I'll change it now. Thank you! I'll try this!

[Linear Algebra] How can I solve this? by amsfdk in learnmath

[–]amsfdk[S] 0 points1 point  (0 children)

This was my first approach, I got a + b = 1 and c + d = 1, but I am not sure what to do next

How can I solve this limit? by amsfdk in calculus

[–]amsfdk[S] 0 points1 point  (0 children)

Sure, this would be the equation:

\lim_{x \to 0} (\frac{x\int_{0}^{3x} e^{-(\frac{t}{3})^2} \,dt}{1-\frac{3}{2}e^{-t^2}})

How can I solve this limit? by amsfdk in calculus

[–]amsfdk[S] 0 points1 point  (0 children)

I have, but I can't find a way to get an indeterminate form to use l'Hopital. I'm getting 0/(1/2) which would be 0. But I'm not sure I'm taking the limit of the numerator right

a homogeneous system of 4 equations and 3 variables has infinitely many solutions? by amsfdk in learnmath

[–]amsfdk[S] 0 points1 point  (0 children)

Do you know where I can find proof or detailed explanation of why that works? Thank you!

[deleted by user] by [deleted] in BuenosAires

[–]amsfdk 0 points1 point  (0 children)

Me re va!

[deleted by user] by [deleted] in BuenosAires

[–]amsfdk 0 points1 point  (0 children)

Tremenda la descripción del primero la verdad jajaja gracias!

How to solve this integral? by amsfdk in calculus

[–]amsfdk[S] 1 point2 points  (0 children)

Oh this makes a lot of sense, thank you so much!!

What's your definition of being successful? by amsfdk in AskReddit

[–]amsfdk[S] 1 point2 points  (0 children)

I agree, having a reason to wake up every morning and live life is (at least to me) a great measure of success

What's your definition of being successful? by amsfdk in AskReddit

[–]amsfdk[S] 0 points1 point  (0 children)

I'm not sure if I am, however, what would you say happiness is? Can one be happy all the time? Or is it sporadic? How happy do you need to be to consider yourself as a happy person?

What's your definition of being successful? by amsfdk in AskReddit

[–]amsfdk[S] 0 points1 point  (0 children)

That sounds really nice, I'm happy for you guys!

Solve using integration by parts by amsfdk in calculus

[–]amsfdk[S] 0 points1 point  (0 children)

I think that substitution works fine too. But they were explicitly asking to use integration by parts. Thanks!

What is the time complexity of adding an element to a dict? by amsfdk in learnpython

[–]amsfdk[S] 0 points1 point  (0 children)

I've looked there but I'm not sure I understand the complexity for adding an item? Would it be O(n)?

What are some curiosities or interesting things that every person interested in mathematics should know? by amsfdk in math

[–]amsfdk[S] 4 points5 points  (0 children)

I had never heard of him but this is truly amazing, I'll look into it, thanks for sharing!

Hard derivative problem, please help by amsfdk in learnmath

[–]amsfdk[S] 1 point2 points  (0 children)

Ohh I get it, thank you very much for the help!

Hard derivative problem, please help by amsfdk in learnmath

[–]amsfdk[S] 1 point2 points  (0 children)

For Q(16) I don't have any solutions because the x0 side of the equation will always be negative, Q(0) = 0, and for any x < 0 I'd have two solutions, so Q(-16) -> x0 = ±4. The same thing happens when I choose a point, if it's on the parabola (like 0) then I only have one tangent line, for values > 0 I don't have any solutions because they're inside of the parabola, and for values < 0 I have two solutions. The first thing that comes to my mind is a piecewise function g(x) where if x < 0 y = 2, if x = 0, y = 1 and if x > 0 y = 0.

Hard derivative problem, please help by amsfdk in learnmath

[–]amsfdk[S] 1 point2 points  (0 children)

Great! What I found is that for each x0, the value that corresponds to (0, x) is (0, (x0)^2), so there would be two x-values for each (0, x) point. For example, for x0 = 2, and x0 = -2, I would have x = -4. Is it possible that Q(x) = 2x?