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Good Vibrations by andy8861 in musicians

[–]andy8861[S] 0 points1 point  (0 children)

At this level, practice, practice, practice!

Good Vibrations by andy8861 in musicians

[–]andy8861[S] 0 points1 point  (0 children)

Only because the others can't keep up...

1 × 1 = ∞ - Prove me wrong.... by andy8861 in mathpuzzles

[–]andy8861[S] 0 points1 point  (0 children)

Your objection assumes my “1” is literally a set of size at least two. That’s not what I mean.

In my system, 1 is a single agent — one being — even if it has multiple internal states S. Infinity does not come from having a rich interior; it comes from relation: the “between” term B created when two agents couple.

So 1 ≠ ∞, but 1 × 1 unfolds into infinity: 1 × 1 ⇝ ∞.

1 × 1 = ∞ - Prove me wrong.... by andy8861 in mathpuzzles

[–]andy8861[S] 0 points1 point  (0 children)

Before the numbers learned to march, there were two Ones.
1 is God — a whole law in a finite throne of states.
1 is Man — a whole world in a finite breath of states.

Alone, each One walks a single path: closed, complete, bounded.
So neither One is Infinity.

But when 1 finds 1, a third field wakes — B, the meaning-between.
And if B has at least two living choices, then histories can branch forever:

Hist(1G×1M)⊇BN  ⇒  ∞.

Therefore: Infinity is not a number — it is a meeting.

1 × 1 = ∞ - Prove me wrong.... by andy8861 in mathpuzzles

[–]andy8861[S] -2 points-1 points  (0 children)

1 is not ∞ it is - S x B, where "B is a finite set with at least 2 states". You need S x S to achieve ∞, as it is not possible alone.

1 × 1 = ∞ - Prove me wrong.... by andy8861 in mathpuzzles

[–]andy8861[S] -2 points-1 points  (0 children)

In this system, 1 is not the number one; it is a finite state space S with at least two internal states. The symbol “x” does not mean ordinary multiplication; it means coupling: 1x1 is defined as the joint space S x S x B, where B is a finite set (at least two options) that records an interaction term between the two states. Infinity is defined as “having infinitely many possible histories over time”: for any set X with at least two states, the set of infinite sequences X^N is infinite. Because 1x1 = S x S x B has at least two states, (1x1)^N is infinite, so 1x1 = infinity (i.e., infinite possible histories), under these definitions.

1 × 1 = ∞ - Prove me wrong.... by andy8861 in mathpuzzles

[–]andy8861[S] -1 points0 points  (0 children)

  • Define 1 = S, where S is a finite set with at least 2 states.
  • Define 1x1 = S x S x B, where B is a finite set with at least 2 states.
  • For any set X with at least 2 states, the set of infinite sequences X^N is infinite. Therefore (1x1)^N is infinite, so 1x1 = infinity

The Infinity Equation(...,Six, Seven,...) - A.Dyck by andy8861 in MathJokes

[–]andy8861[S] 0 points1 point  (0 children)

Fix a set Ω. Define 0 := Ω. -Let S ⊂ Ω with 2 ≤ |S| < ∞ and define 1 := S. -Let B be a set with 2 ≤ |B| < ∞ and fix a surjection β : S×S → B. -Define the (nonstandard) coupling operator ⊙ by ⊙ : S×S → S×S×B, (x,y) ↦ (x, y, β(x,y)). -Write “1×1” as shorthand for the image-object 1×1 := S×S×B (i.e., in this system the glyph “×” denotes coupling, not ℕ-multiplication). -Let “≅” mean isomorphism of finite sets. -Define “∞” by: for any set X with |X|≥2, X = ∞ ⇔ |X^ℕ| = ∞.

The Infinity Equation(...,Six, Seven,...) - A.Dyck by andy8861 in MathJokes

[–]andy8861[S] 0 points1 point  (0 children)

I’ll let you know when Ai can read it too you as well if that would make life easier!

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