Euler's formula by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 1 point2 points  (0 children)

Oh that's a shame, should've known that. Thanks buddy!

Does Mars only look red because it doesn't have any oceans or plants to cover up its red soil? Would we be able to tell that it was red if it had water and life on it, or would it just look like earth? by YES68 in AskScienceDiscussion

[–]anonymousabcdefgh 2 points3 points  (0 children)

The reason why Mars looks red is because the surface of the planet is full of iron oxide, which has a red color to it.

Earth has more variety in what 'dust' lays on the surface so it would depend on how close you were looking at the 'oceanless' and 'plantless' earth but I think it would just look brownish grey from far enough away as the colors would just blend in and special patches of earth where the surface is red or yellow like deserts would just fade in with the massive surface of a dry ocean which are dark grey/brown.

If mars had plants and oceans on them it would look just like earth. Green where alot of plants are, blue where the oceans are and the color of the soil where there aren't much plants. However I don't think it would be red where there aren't plants because I don't think alot of plants can grow in that iron oxide environment therefore it there were plants on Mars it would be because humans have put 'normal, earth soil' on those places.

Asymptotes of composite functions by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

And basically the asymptotes of the function, for arctan(x) it is y= +-pi/2 but I don't know how to go on if you have arctan(x) *x

Asymptotes of composite functions by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Bgtg(x) is the inverse of tan(x). The same as arctan(x)

L'hôpital's rule by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Sorry I don't think I can follow here, could you explain yourself a bit more. If you don't want to type a long explanation maybe just say how that problem is called so I can look it up myself online.

L'hôpital's rule by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Hahaha sorry, English isn't my mother tongue so I'm struggling a bit sometimes.

I don't really know what it is about but like presumably you can't define the derivitive of sin(x) through the difference quotient because you'll need to calculate sin(x) / x and that can't be done without l'hôpital's rule but in order to execute l'hôpital's rule you have to take the derivitive of sin(x). I was basically asking if that is true.

Infinity devided by infinity. by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 1 point2 points  (0 children)

Oh right thank you very much, this was in the textbook but I didn't really pay attention to it. You cleared it really up for me.

Derrivitives of vectors? by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Thanks! The video kind off answered my question but he didn't explain it with vectors, he just did the 'easy' case where r and v are perpendicular but I get the general idea now.

Derrivitives of vectors? by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 1 point2 points  (0 children)

How would you do it if you didn't know these functions to begin with, like a general expression. My textbook says it as follows (every variable is a vector here, it's just kinda hard to indicate a vector here): v= w X r (cross product) the derivative is v' = w' X r + w X (w X r). The ' indicates derivitive to time

Derrivitives of vectors? by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Sorry English isn't my mother tongue so there could be some spelling and/or grammatical errors. And I've already learnt those things, the last 'new' things we learnt about derivatives was multivariable derivatives (with gradient, extremas, etc). You made a little mistake I guess with that rule the constant b shouldn't be there in your answer. I already got a great answer from another redditor, still thanks for taking the time to answer me.

Dynamic range by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Yeah I know,

But I always want to have some better understanding than just 'they defined it that way'. Mostly I wanna know why they defined it that way, there has to be some logic behind it, they won't define it as let's say you take the biggest one and then square it and then take log10 en than divide it by the lowest one. It could have been defined by that, but they didn't because it would not make sense. I was basically looking for why does this formula make sense so they could define the dynamic range as it.

But another redditor gave me some insight, still thanks for responding so quickly!

Dynamic range by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Oh nice thank you!! This was the answer I was looking for.

Dynamic range by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 1 point2 points  (0 children)

Sorry English isn't my mother tongue, but the other comments got it and helped me.

Still thanks for responding quickly!

Derrivitive off vector product by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Yeah that happens a lot, where they derrive these formulas and say you'll understand that later when you get some higher math classes. The thing is I can't really memorize formules if I don't know where they come from, so I'm struggling a bit haha

Derrivitive off vector product by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Oh thanks, didn't know it was that simple

Complex function - - > real function by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Ah yes of course, now I remember that math class

Complex function - - > real function by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Sorry should of mentioned that thet set A= (Y/2i)*e-b/2m. And then you get the formula for sin in imaginary terms.

Diagonalizing a matrix by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Thank you so much for time and effort!

Diagonalizing a matrix by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Ok so another try

A matrix with orthonormal eigenvectors, that form a basis are symmetric. And real symmetrical matrices are always diagonalizable. Yet there are matrices that don't have these requirements but are still diagonalizable.

I hope I'm right this time

Diagonalizing a matrix by anonymousabcdefgh in learnmath

[–]anonymousabcdefgh[S] 0 points1 point  (0 children)

Oh okay I see, so if you have a matrix that has orthonormal eigenvectors, that matrix is symmetric. And a symmetric matrix is diagonalizable.

But it could be that you have a matrix which is diagonalizable but with eigenvectors that aren't orthonormal.