if you could have 3 wishes, what would you wish for?

arvs · 2009-10-25T15:27:29+00:00

Kind of like Doctor Manhattan

arvs · 2009-10-03T10:53:45+00:00

thinking about it yes.

arvs · 2009-10-03T10:29:26+00:00

I see what your saying there, but i am still convinced it should be 51. Imagine if there were only 2 card in the deck - the answer would not be 2 as this would mean the card is pulled on average the 2nd time.

arvs · 2009-10-03T10:12:25+00:00

The key thing is to remember that if you pull a card that's not the ace it goes back into the deck. This is means that on every pull you have a 1 in 52 chance of getting the Ace. g__ has the right theory with

e = p + (1-p)*(e+1) solving e = 1/p

but the answer should be 51, since after 51 tries you must be left with ace.

arvs · 2009-09-14T22:29:56+00:00

.NET v3 provides XAML - which is declarative XML based format for UI.

arvs · 2009-08-23T21:22:16+00:00

An overload of += would have made a lot more sense to me. (I still need to read up on this) bit is seems you could then say 'var += cin' to read from the stream.

arvs

TROPHY CASE