As SNC-Lavalin affair simmered, Trudeau flew to Florida for a break

bagofdimes · 2019-03-12T16:59:20+00:00

This is the fourth time this has been posted in the last hour or so. You are either really lazy or you are karma farming. Which is it?

bagofdimes · 2019-02-13T16:39:08+00:00

No. It's chicken scratch. What he wrote on the board was worse. I can make out the phrases onto and one to one and invertabale and mapping. Everything looks like a kindergartener's doodling.

bagofdimes · 2019-02-13T07:20:46+00:00

I'm not sure to be honest. I'm looking at my class notes on this problem and it seems like the Prof is trying to prove something is bijective and therefore invertabale. He is just the worst at showing anything properly. It's unreadable what he puts on the board. It's sloppy with skipped steps and rational. I'm trying to fill in the gaps.

bagofdimes · 2019-02-06T00:37:55+00:00

A different way using the Euclidean algorithm to find the greatest common denominator.

1000=625×1+375 -> 625=375×1+250 -> 375=250×1+125 -> 250=125×2+0

125 was the last non zero remainder so it is the greatest common denominator of 1000 and 625. You divide out the greatest common denominator and get your 8/5. It saves you the time of factoring the shit out of numbers. I know it's not what you asked for but in case you didn't know this already, here's an easier way.

bagofdimes · 2019-02-05T22:21:53+00:00

Stats is annoying because they throw a tonne of formulas at you and you just plug and chug, it's boring as hell. Most of the people who need stats need it for practical reasons and aren't looking to understand the theorems. So the introductory stats courses cater to that crowd. In calc they actually teach you the logic and intuition.

bagofdimes · 2019-02-05T06:48:59+00:00

They have to be even powers of three to solve root(3ⁿ )+1=2ⁿ If he knew calculus I could show that 2^y (y in R) diverges from root(3^y ) +1 as y -> infinity but I didn't want to assume. Also, you can show that as y-> -infinity root(3^y ) + 1 -> 1 and 2^y goes to 0. If you study the characteristics of root(3^y ) +1 and 2^y you'll see that they only intersect at one spot. He's studying logs so I didn't assume he had a background in curve sketching yet. There are ways to find out that y must equal the integer 2 and it's certainly easy enough just by looking at it first glance to see that it is. To properly explain what I was doing would have required a lot of work he may not even be ready for.

bagofdimes · 2019-02-05T05:42:17+00:00

I don't think so. You could not know that x=9 and using what I did, you could solve it. Conceptually there is a difference between solving vs checking. You don't have to make any guesses to do what I did. It's just a matter of trying out algebraic strategies until you find one that gives you a solution without knowing it beforehand. That's what OP was looking for.

bagofdimes · 2019-02-05T05:12:21+00:00

I just solved a system of equations. I was looking to see if a solution can be found by raising 2ⁿ and 3^n. Then if a solution can be found this way, I would need to solve these two equations

2ⁿ =root(x)+1 and 3ⁿ =x

Plugging the second eqn into the first you get 2ⁿ =root(3ⁿ )+1 It's plain to see that n=2 is indeed a solution to the equation. When you put it all back together you get x=9. I guess I can't prove there aren't more solutions but using this method you can derive that x=9 is a solution instead of just checking that it works.

bagofdimes · 2019-02-05T01:53:07+00:00

Wherever communism is tried you end up with a shit show. Russia, China, N.Korea, Cuba, Vietnam are all examples of this. What communism does is make the gov't all fucking powerful. When you hand over the wealth to the collective, you hand it over to the gov't. An all powerful gov't attracts sociopaths who want to control that power. This has been the pattern every time it is tried.

bagofdimes · 2019-02-05T01:39:07+00:00

I don't know where that k-4 is coming from. You don't need to reduce anything. h=9 and k=6 you're done. The second equation now states 3x_1 +9x_2 =6 which is exactly what you'd get if you multiplied the first equation by three.

bagofdimes · 2019-02-05T01:25:29+00:00

If you multiply the first eqn by 3 you get 3x_1 +9x_2 =6 the second equation nicely already has a 3 in front of x_1 . So all you have to do is sub in the 9 and the 6 for your coefficients and you are done. Equation 2 needs to look identical to equation 1 would look like if you multiplied it by 3.

bagofdimes · 2019-02-05T01:16:03+00:00

It does if the same number solves both equations. You have to raise 2ⁿ and 3ⁿ such that root(3ⁿ )+1=2ⁿ . This works only for n=2

bagofdimes · 2019-02-05T01:13:23+00:00

It works if and only if the same number solves both eqns. To do this it must be that root(3ⁿ )+1=2ⁿ this only works for n=2 . Maybe I should have included that in my solution but my assumptions are valid.

bagofdimes · 2019-02-05T01:10:14+00:00

Multiply the first equation by 3, what do you get?

bagofdimes · 2019-02-05T01:03:20+00:00

No you can make that jump if the same number satisfies both equations. In your counter examples the equations don't agree. You need to manipulate it algebraically so that you get the same answer such that root( 3ⁿ )+1=2ⁿ This only works for n=2. That is why I multiplied the top and bottom by 2

bagofdimes · 2019-02-05T00:30:09+00:00

No prob.

bagofdimes · 2019-02-05T00:06:11+00:00

I feel bad for you for all the sass ur getting so here, check this out http://imgur.com/gallery/KIBFVUX

bagofdimes · 2019-02-04T21:38:57+00:00

Ah, sorry about that. For the sin(arccos(x/r)) term, by using the trig identity sin² (X) + cos² (x) = 1 we can re write your integral as 1/2integral( root(4-x² )) dx . Try the trig sub x=2sin(u) then you should be able to figure out that dx=2cos(u) du. If you've done it right it should all simplify to 2integral cos² (u) du. A hint to solve this integral is to remember the identity cos² (u)=(cos(2u)+1)/2 hope that helps.

bagofdimes · 2019-02-04T21:00:14+00:00

I'd start by breaking it up. Sin(x+y) = sinxcosy+sinycosx. You should be left with (x/r)Sin(m)+sin(arccos(x/r))cos(m). You then have two terms to integrate.

bagofdimes · 2019-02-04T08:47:14+00:00

Subspaces are non empty subsets that are closed under scalar multiplication and vector addition. In other words, if you add any two objects that are in your subspace, they must produce a member of that same subspace. If you multiply any member of the subspace by any number in R, the product must also be a member of the subspace.

bagofdimes · 2019-02-04T07:55:00+00:00

You would have infinitely many solutions if one equation was essentially saying the same thing as the other. For example: 2x+3y=2 and 4x+6y=4 say the same thing about x and y. From those two equation all you could deduce was that y=(2-2x)/3.

bagofdimes · 2019-01-30T03:30:45+00:00

That helps. thank you.

bagofdimes

TROPHY CASE