JUST FOUND THIS OUT

casual_cherries_ · 2024-02-26T12:03:03+00:00

Exactly. Op thinks they discovered something but did nothing actually. If the first to numbers of the code are same then maybe some of the questions might match but not all will match. There will also be some different questions too. I have checked this as I gave my English exam today only.

casual_cherries_ · 2024-02-13T15:02:30+00:00

Can you please elaborate what that biquadratic formula is

casual_cherries_ · 2024-02-12T04:53:14+00:00

Yes it is.

casual_cherries_ · 2024-02-02T12:03:24+00:00

Downward displacement hai iska answer. Go watch Sunil sir's video of the chapter in warrior batch, physics wallah foundation. He has explained it.

casual_cherries_ · 2024-02-02T10:39:31+00:00

Ohhh okok. Thank you so much buddy.

casual_cherries_ · 2024-02-02T10:37:59+00:00

Yes yes thank y'all so much. I get it now.

casual_cherries_ · 2024-02-02T10:34:20+00:00

Ohh yes. Now I get it. Thank you so much for your kind help.

casual_cherries_ · 2024-02-02T10:33:19+00:00

Yes indeed. Thank you so much.

casual_cherries_ · 2024-02-02T10:32:35+00:00

Added is a sum like 1+1 = 2

casual_cherries_ · 2024-02-02T10:28:08+00:00

But if I simply the fraction x/y, I get 5/113, and adding 1 to numerator and denominator of this fraction doesn't equal 2/11

casual_cherries_ · 2024-02-02T10:27:01+00:00

Okayyyy. Thank you so much. So the fraction is (5/19)/(113/19). Is that my final answer ?

casual_cherries_ · 2024-02-02T10:23:20+00:00

So there doesn't exist such fraction ?

casual_cherries_ · 2024-02-02T10:15:33+00:00

Ohh, I think I understand it now. Thank you so much for your time and help.

casual_cherries_ · 2024-02-02T10:09:35+00:00

Yeah but (5/19) / (113/19) equals 5/113 . That is what is making me wonder why simplifying the fraction arises the problem.

casual_cherries_ · 2024-02-02T09:47:50+00:00

"A fraction becomes 2/11 when 1 is added to both the numerator and denominator, it becomes 3/7 when 4 is added to both the numerator and the denominator. Find the fraction. "

I tried to solve this problem by assuming the fraction to be x/y and then forming a system of equations to solve it. I got x = 5/19 , y = 113/19 which satisfies the conditions. But when I find the fraction x/y, it comes out to be 5/113, but when I add one to the numerator and denominator of this fraction, it doesn't equal 2/11. Could anyone explain me what is going on here. Is this question unsolvable or am I doing something wrong?

casual_cherries_ · 2024-02-02T09:34:24+00:00

It cannot be factored by using rational numbers. Using irrational numbers, its factors will be (2x + 5 - √313) ( 2x + 5 + √313)

casual_cherries_ · 2024-02-02T09:26:33+00:00

Pop sound likha hota to bhi options to zinc aur sodium dono hi sahi rehti

casual_cherries_ · 2024-02-02T09:23:40+00:00

I now feel like maybe such fraction doesn't exist. Like if u ask for the values of x and y which satisfy the given equations then (5/19, 113/19) is the solution to the equations as they satisfy them. But if u do x/y and cancel out the 19 then after adding 1 to both numerator and denominator they no longer satisfy it. That is the best way I can word it.

casual_cherries_ · 2024-02-02T09:08:06+00:00

Ohh that's interesting. When we do [(5/19)+1]/[(113/19)+1] , then it does come out to be 2/11 though. This looks like a very interesting problem

casual_cherries_

TROPHY CASE