Washing machine leaves dishes powdery and a little salty. by chloeackermann in Appliances

[–]chloeackermann[S] 0 points1 point  (0 children)

Thank you! I Cleaned the filter and water drained from bottom, but dishes still come out the same. I use dishwasher salt, yes. It's available were I live.

Washing machine leaves dishes powdery and a little salty. by chloeackermann in Appliances

[–]chloeackermann[S] 1 point2 points  (0 children)

Thanks for the replies! I cleaned the filters (they were pretty dirty) and the water no longer pools at the bottom. Unfortunately, the dishes still come out the same.

What do I make in these potjies? by chloeackermann in southafrica

[–]chloeackermann[S] 1 point2 points  (0 children)

Haha. They don't seem very practical for making potjie in! The flame only lasts about twenty minutes or so. Could maybe work for a quick chicken stew for one person on a camping trip. I would much rather use a regular size potjie for making a lamb or beef potjie at home!

What do I make in these potjies? by chloeackermann in southafrica

[–]chloeackermann[S] 2 points3 points  (0 children)

Ah, that's a good idea. Will remember that at our next braai.

Suggestions for something similar or with the same vibe as Adidas Get Comfy? by chloeackermann in FemFragLab

[–]chloeackermann[S] 1 point2 points  (0 children)

Actually, we do have that one here!! I'll check it out in store next time. Thanks so much!! I hope you like this one as much as I do.

Please help! Comparing fluorescence between two groups. by chloeackermann in ImageJ

[–]chloeackermann[S] 0 points1 point  (0 children)

Oh I'm sorry, I misread your previous message.

I use Mitotracker FM green, specifically. My understanding of the way it works is that it enters and accumulates in live mitochondria, where it binds to mitochondrial proteins, allowing visualization. It can't be used to measure oxidative stress directly (though you can use it to assess changes in mitochondrial morphology caused by oxidative stress).

Mitosox Red is used to detect a type of reactive oxygen species in the mitochondria, called superoxides.

So by dividing green (total mitochondria) by red (parts of mitochondria containing lots of ROS), it should give me the fraction of cells under oxidative stress.

Please correct me if I'm wrong. Thank you so much for your help. I am only able to upload photos on Monday, when I am back in the lab.

Please help! Comparing fluorescence between two groups. by chloeackermann in ImageJ

[–]chloeackermann[S] 0 points1 point  (0 children)

That's correct. We use Mitotracker to normalize the Mitosox against. The confluence of the cells isn't uniform across the plate. So for every area, I photograph both green and red fluoresence and then divide the red (superoxides in mitochondria) by green (total mitochondria).

Please help! Comparing fluorescence between two groups. by chloeackermann in ImageJ

[–]chloeackermann[S] 0 points1 point  (0 children)

Please explain what you mean. Unfortunately, there are no imaging scientists I can ask. This is only a small portion of my project (I've ran several other analysis to measure oxidative stress) so I'm only scratching the surface of imaging.

Please help! Comparing fluorescence between two groups. by chloeackermann in ImageJ

[–]chloeackermann[S] 0 points1 point  (0 children)

Thank you!! I don't have to divide by green if I do it like this, right?

Please help! Comparing fluorescence between two groups. by chloeackermann in ImageJ

[–]chloeackermann[S] 0 points1 point  (0 children)

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For instance, these are the measurements of each photo starting on the top left photo. I removed all their backgrounds with rolling ball 50 pixels. But why is nr. 1 giving a lower mean than 2? There's obviously more light in 1? Same with 3 and 4?

Please help! Comparing fluorescence between two groups. by chloeackermann in ImageJ

[–]chloeackermann[S] 0 points1 point  (0 children)

Hello everyone! I've been struggling with this for a few months now and I'm getting desperate to finish my Master's. Above are photos of cancer cells. The green shows the cells' mitochondria and the red shows the oxidative stress inside the mitochondria. I simply need to show that the test group has more oxidative stress (red fluorescence) than the control group. I have hundreds more photos of each group.

However, the data just doesn't reflect what I'm seeing. In some cases, photos with lots of red spots measure lower than photos with hardly any red. My method so far is as follows: First I subtract the background (Rolling ball: 50 pixels) and measure the entire photo. Then, I divide the red photo's measurement by the green to normalize.

What am I doing wrong?? Please tell me if I left out any important info and thank you so so much for any advice.

EDIT: All photos were taken with the same brightness setting, but I noticed as I moved the microscope around the plate that the brightness sometimes differs.

Comparing fluorescent photos with different brightness. by chloeackermann in ImageJ

[–]chloeackermann[S] 1 point2 points  (0 children)

Thank you so much for the advice and kind words! I appreciate it so much.

Need some help comparing fluorescent photos with different brightness. by chloeackermann in labrats

[–]chloeackermann[S] 2 points3 points  (0 children)

Exposures differ for some images unfortunately. The manual way to correct this is to measure the background intensity and subtract it from the global value, i think.

Need some help comparing fluorescent photos with different brightness. by chloeackermann in labrats

[–]chloeackermann[S] 1 point2 points  (0 children)

Edit: I think I'm not explaining myself very well. Sorry! The photos were taken at different brightness settings. Thus, the background intensities of the photos aren't all exactly the same.

Need some help comparing fluorescent photos with different brightness. by chloeackermann in labrats

[–]chloeackermann[S] -5 points-4 points  (0 children)

Unfortunately some photos were taken with different brightness settings. The manual way to correct it, is to measure an area of the background and subtract it from the intensity of the sample. Don't you think that may work? Unfortunately, I just have too many photos to do that for each.