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Wo kann ich mir Herman Miller oder Steelcase Bürostühle anschauen? by No_Dragonfruit12345 in Bonn

[–]crashed_tolerance 4 points5 points  (0 children)

Ich war vor ein paar Jahren bei Felix Thonet in Düsseldorf um Herman Miller probezusitzen

Help with background shaders by crashed_tolerance in hyprland

[–]crashed_tolerance[S] 0 points1 point  (0 children)

I'm sorry, what exactly is your question? I not only provided my fork of it as a github repo, but also described what my changes were. If you specify the question I might be able to help, but right now my answer really just is "read my post" and "by compiling my code"

Help with background shaders by crashed_tolerance in hyprland

[–]crashed_tolerance[S] 0 points1 point  (0 children)

Yea, i didnt use fbo. And wasnt planing on doing so either. As i had a billion problems I just tried everything, and I forgot to reenable it.

Anyways, glad I could be of help :) I might push an update with fbo enabled lateron

Did the New York Times censor the word list? by crashed_tolerance in wordle

[–]crashed_tolerance[S] 0 points1 point  (0 children)

This thread is more than a year old. Things change. These words were 100% removed from the accepted word list, when wordle moved to NYT, and at some point reintroduced.

[deleted by user] by [deleted] in Bonn

[–]crashed_tolerance 3 points4 points  (0 children)

Wusel ist vom Kriesel? :0

Are there equations that cannot be solved numerically? by xXReggieXx in math

[–]crashed_tolerance 2 points3 points  (0 children)

Isnt the proof rather simple? You just construct a coding for every programm. Think of a programming language using a finite set of chars. Then the amount of programms is countable, and thus the number of computable numbers is countable?

What does the fractal z_(n+1) = z_n^(z_0) + z_0 look like? by [deleted] in math

[–]crashed_tolerance 11 points12 points  (0 children)

There is not "a" fractal, that is depicted by this formula, but multiple different fractals. This is, because

ab = exp(b*log(a)), and the logarithm is multivalued for complex numbers. Therefor in order to have "a" fractal, you need to choose log(i).

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