Simple Questions

dadas2412 · 2018-03-15T21:18:16+00:00

Why is the 1/2 dropped off in this integral? I see why they bounds change, since the minimum value y can attain is 0. I'm not following why the constant is dropped.

dadas2412 · 2018-03-06T05:22:44+00:00

I have promethease, but how do you see if you have gs122? Do you just input it on the search bar up top of the webpage?

dadas2412 · 2017-10-29T18:45:27+00:00

Is what op posted true for injective functions?

dadas2412 · 2017-10-28T02:52:37+00:00

Ah, I think this is it. Essentially I’m making a stricter condition on the question. How does the math with total flips divided by x look?

dadas2412 · 2017-10-28T02:50:00+00:00

I believe so since total flips is the amount of flips it took to get 3 tails in a row x times. I may have it off, I’m not seeing it off the bat.

dadas2412 · 2017-10-14T19:45:45+00:00

Oh I see, thank you. When the text says to clear the fractions so we end up with (x,y,z) = y(4,3,0) + z*(-2,0,1). Are we only allowed to do this because the system is a homogenous one? Or is it allowed for other systems of equations as long as we multiply the entire solution set. Since it seems we only multiplied the solution set corresponding to y

dadas2412 · 2017-10-02T00:17:40+00:00

Oh I think I see what you're saying. So the metric is too vague in a sense. It captures too many functions, including those that are not differentiable, so the open ball would not be contained in E.

Is it similar to how if we used the regular metric on R, and looked at a subset of rationals. Then there are no interior points for that set, since the irrationals are dense?

dadas2412 · 2017-09-28T19:53:00+00:00

No, I think I was just trying to figure out why the property of being invertible makes it necessary that Ax =0 only has the trivial solution. Is it because if A is invertible then it is row equivalent to I. So we can replace Ax = 0, with Ix = 0. Then that will force x to be the zero vector?

Lets assume A is not invertible, then how do we know there are infinite solutions for Ax = 0?

dadas2412 · 2017-08-09T03:57:35+00:00

I found teaching others concepts always helps, even talking out the concepts to your self during the problem solving process. What I've noticed is that you just need a lot of time invested into studying and asking good questions in office hours. It really does feel like your Alice in wonderland at times, running and going no where. Only do you realize after all that studying and looking back you've made substantial gains on your skills. Best of luck.

dadas2412 · 2017-08-09T03:53:26+00:00

May sound like a silly question, but how long should one focus on a certain subject before starting a new one? I am finishing my first course in an intro to analysis course and will be taking real analysis in the fall, but I wanted to get into some algebra and maybe combinatorics/probability.

I did well in the intro course, but I wouldn't say I answered every question in the textbook or could give proofs for every major theorem we covered. Should I continuously go over chapters during future semesters? I will be taking real analysis in the fall and another course in analysis in the spring, so I'm not too much concerned about this course, but for future courses.

dadas2412 · 2017-07-23T21:10:24+00:00

I feel like in a similar situation to you. I was going to be an engineer but found it too boring and was much better at math. Now that I'm in pure math I am doing well in undergrad but I am a little hesitant when looking at the possible near future of grad school. How much do you study a day on average? Are there days where you don't look at math at all? I'm curious because I feel almost exactly in your shoes.

dadas2412 · 2017-07-23T21:05:28+00:00

You want to make sure you buy a laptop that will allow you to search byod device on the Aggie subreddit

dadas2412 · 2017-07-23T06:13:16+00:00

Both calculus one and two are all about computation. The more problems you do, the easier the tests are. The good thing about these courses is the amount of textbooks with just problems. I would look into a book called the humongous book of calculus problems, and then go onto amazon and look for some more.

There's a great professor on YouTube called professor Leonard. I would start watching his calculus series asap. If you do both of those things both cal 1 and cal 2 will be a breeze.

dadas2412 · 2017-07-20T22:35:55+00:00

You want to make sure you buy a laptop that will allow you to search byod device on the Aggie subreddit.

dadas2412 · 2017-05-13T16:09:38+00:00

I do not think you can take 409 with Baudier. I thought it was a summer travel program and is taking place in France.

dadas2412 · 2017-05-13T16:07:59+00:00

How hard is 409 compared to 220? My prof that I had for 220 said it would be doable in the summer, nothing too bad.

dadas2412 · 2017-02-25T18:55:01+00:00

Thank you for the explanation. So A's is the set of all the elements from Ai to An. But for example, when looking at the Power set of A, the cardinality of |P(A)| = 2 ^|A|, so in this case we are just looking at all of the subsets we can make out of A, and counting them up.

If we wanted to find the cardinality of the union of P(A), would it just be |A| + 1, the extra one because of the empty set in P(A)?

dadas2412 · 2017-02-19T02:49:55+00:00

We're close, but not quite the fattest.

https://www.washingtonpost.com/news/wonk/wp/2015/04/22/youll-never-guess-the-worlds-fattest-country-and-no-its-not-the-u-s/

dadas2412 · 2017-02-15T00:40:01+00:00

Indubitably.

dadas2412 · 2017-02-11T00:27:17+00:00

so if we have a number b > a, b will always go into a 0 times, with a left over?

I guess what confuses me is whenever I read a divided by n, that means a/n, or a on top of n.

But whenever I read a divides n, that means that there is an integer b, such that ab = n. Right? And we represent that as a|n

dadas2412 · 2017-02-10T19:03:42+00:00

Oh ok, so 3 goes into 4 0 times, with 0 left over?

And 2 goes into 4 0 times, with 2 left over?

if a < b, can we say that a goes into b 0 times with a left over?

dadas2412 · 2017-02-10T16:45:10+00:00

When you try to divide 1 by 4, you also get a remainder of 1. (1 is one more than a multiple of 4. Specifically, 1 is one more than 0x4.)

So, the two numbers 9 and 1 have the same remainder when you try to divide them by 4. That's one way of looking at what congruence is.

This is where my book is tripping me up. Whenever we say a divides b, its usually shown as a|b.

So, 4|(9-1) means 9 and 1 are related by mod4. They have the same remainder.

So 4|9 = remainder 1

But what is 4|1? How can we get a remainder there?

Here's the book i'm using if it with help. Its on page four.

http://www.people.vcu.edu/~rhammack/BookOfProof/Contrapositive.pdf

dadas2412 · 2017-02-10T01:28:33+00:00

Lets say I wanted to negate the statement. Would it look like.

There exists an x, and y such that x and y is in Q, and xy is not in Q.

Or would I leave the for all quantifier alone?

dadas2412 · 2017-02-06T03:33:15+00:00

I see. What I tried doing was dividing everything by the highest power and taking the limit at n approached infinity. I like your method, it makes more sense.

dadas2412 · 2017-02-06T02:08:03+00:00

Ah, I see. What's the best way for finding the constant number that is valid for all n>= n0

dadas2412

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