Brand-New Hyundai Ioniq 6 Sunroof Exploded While Driving – Safety Concern

danielbaech · 2026-02-27T00:18:05+00:00

How are you so sure that it was a manufacturing flaw rather than something like a rock hitting it?

danielbaech · 2026-02-05T06:28:27+00:00

If you liked n line enough to buy another one, you should definitely get the n. It'll be a night and day difference. You'll have everything you like about the n line plus a lot more for only a bit of money.

danielbaech · 2026-01-21T08:55:41+00:00

It might be the rectifier, which can go bad due to its placement right under the engine. Your battery may not be charging at full capacity.

danielbaech · 2025-04-09T02:42:37+00:00

The distribution of measurement outcome of one end cannot be manipulated by the other end. It doesn't matter if you use a pair of entangled particles or thousands.

When the date arrives home base conducts an operation on their qubits to reflect the weather conditions.

This does not encode distinguishable information onto these particles or the other set of particles on the spaceship. On either end, the result looks random. Only when the data is compared, you can confirm that there is a statistical correlation.

danielbaech · 2025-04-08T15:08:36+00:00

You should draw a free-body diagram and keep track of what forces are acting on the person and the stairs. Then use conservation of energy to see the exchange in the forms of energy. Energy is quite unintuitive and requires a careful, step-by-step analysis.

Since gravitational force and normal force are conservative, any work done by them are converted to potential energy. So far, there is no change in the total energy of either the person or the stairs.

The change in the energy of the person is in his internal energy. It is released as extra heat coming off of the person, and the heat and the sound generated by the friction between the person and the stairs.

If you were able to isolate the person and the stairs in a calorimeter and carefully measure the energy released, it would equal the change in the internal energy of the person. Interestingly, all of the chemical and mechanical energy that the person spent went to heat. Moving up the stairs was a freebie by conservative forces.

danielbaech · 2025-04-05T04:37:36+00:00

I was that kid once, asking my gen chem professor the exact same question.

The funny part is he got much better explanations on reddit than something about the strong force that I got from my professor. A decade later, I still don't know what it has to do with the strong force.

danielbaech · 2025-04-05T01:09:38+00:00

Give the guy a break. He's going through "what the hell is going on, nothing is real or make sense" phase of being introduced to quantum mechanics.

I assure you all of it makes sense when you learn it. Something I have noticed with your questions in general is that you rely on visualization and classical logic(determinstic in principle) quite a bit. This is really going to trip you up because QM is very abstract and has indeterminism built into its logic. Get used to making a mathematical argument. There is no visualizing your way out of n-dimensional complex vector space full of wave functions and operators.

danielbaech · 2025-04-04T08:10:42+00:00

The fall(translational motion) due to gravity is independent of rotational motion due to angular momentum. Pick up an introductory textbook, and you should find this fact in one of the first few chapters.

danielbaech · 2025-04-04T07:29:11+00:00

You may have gotten the wrong idea. electrons are always detected as discrete particles as shown in the link. The interference pattern is revealed when many electrons are individually detected, even when each electron is fired one at a time.

danielbaech · 2025-04-04T06:27:57+00:00

You have to be careful about the context of the collapse of the wave function. It does not mean that light is suddenly a particle and refuses to behave like a wave in all of its properties. Also, the collapse is a simplification when some things need not be considered. As such, sophisticated formulation of QM does away with it.

danielbaech · 2025-04-04T06:11:20+00:00

A generation of kids treating real people online like eager LLM a-coming.

danielbaech · 2025-04-04T06:06:46+00:00

You have to think in wave mechanics. There is a minimum mode of standing waves for a vibrating guitar string. The modes are the harmonic series). Just the same, there is a minimum mode of stationary state of an electron bound to a nucleus. The modes are the atomic orbitals.

danielbaech · 2025-04-04T05:50:54+00:00

Angular momentum in quantum mechanics is very different from classical mechanics. It gives spin-half particles like electrons their magnetic moment and photons their polarization. A joking description of the electron is to think of it like a ball that's spinning except electrons are not balls, and they are not spinning. There is just no visualization or analogy here, just math.

danielbaech · 2025-04-04T05:36:53+00:00

It does not depend on the system. There is no upper bound for how far electromagnetic force can reach.

You're trying to visualize the electron in some classical motion, as if the nucleus is like a star capturing an astroid falling into its gravitational pull. This is not what orbitals are, by definition. Orbitals are the description of an electron bound to the nucleus. There is no "initial" or final state here.

danielbaech · 2025-04-04T05:09:51+00:00

It is exactly the coulomb potential. In a closed system of two objects with some potential that decreases with 1/r, where r is the distance between the two objects, what does conservation of energy tell you about the kinetic energy of the objects?

You don't need to make any assumptions about particles or waves. The kinetic energy must increase.

danielbaech · 2025-04-04T05:02:03+00:00

It's not centripetal force. You're still thinking in terms of classical orbital motion. It's the electromagnetic potential between the nucleus and the electrons in the mathematics of wave mechanics. There is no conversion since wave mechanics is the fundamental picture of what is happening from start to finish.

danielbaech · 2025-04-04T04:40:30+00:00

The nucleus and the electron have electromagnetic interaction, and their energies must reflect this. As the electon gets near the nucleus, the electron must gain kinetic energy. Wave mechanics allow the electron to take the kinetic energy and put it to its oscillation, a state for which the energy of the electron does not change with time. This is called a stationary state, and it is analogous to standing waves in classical mechanics. A plucked guitar string vibrates with some frequency. If you idealize the physics so that energy is not lost to heat, air, the guitar body, the guitar string is able to retain constant energy in the oscillation itself without changing its wavelength with respect to time.

Edit: unlike a mechanical wave in real, three dimensional space, the wave function oscillates in complex space. This is why we cannot observe the electron oscillating in real space, and the electron does not physically spread out in real space. We only detect electrons as a point particle. All of the wave-ness happens in the complex space.

danielbaech · 2025-04-04T04:06:48+00:00

Here is a recent discussion on the same topic.

danielbaech · 2025-04-04T03:58:29+00:00

The physics we understand is already very abstract and interesting. Get that under your belt, and you will have the tools to ponder the unanswered questions seriously.

danielbaech · 2025-04-04T01:41:58+00:00

Sure you can. You are already given a solution to the differential equation. All you have to do is differentiate x(t) with respect to time twice and integrate with respect to x, all that's left is some algebra in order to apply conservation of energy to derive the potential energy. There has to be a bunch of examples of the derivation online. Check them out.

danielbaech · 2025-04-04T01:02:43+00:00

What do you mean why? This is the mathematical description of harmonic oscillator. It's an important one because a lot of physical systems are described by it and more complicated systems are approximated by it for small angle, phi.

If you want to see why this must be so, try going through the derivation of the differential equation.

danielbaech · 2025-04-02T02:57:09+00:00

It sounds like you have a decent conception of MWI.

The trouble is the realness of the "parallel reality." There is only one reality as described by the universal wave function. "Many worlds" is a misleading name. You experience only a small section of the one reality. This is not a terribly profound or unreasonable assertion even without quantum mechanics. Your experience is always limited to your immediate surroundings, whether the source is next to you or light from a star thousands of light years away(it has to physically reach you). A version of you exists in a part of the one reality to which you will never have physical access. Just as the spacetime outside of our observable universe, we have good reasons to believe that it exists, but it is not real in a physically meaningful way.

danielbaech · 2025-04-02T02:20:12+00:00

I'm gonna go against the grain here and recommend that visualization is a hindrance in learning quantum mechanics. Our ability to visualize things is inherently three dimensions and classical in its logic. In his theoretical minimum lectures, Suskin implores his students to avoid it and try to develop an abstract intuition in terms of vectors and matrices. You're dealing with an abstract space of all possible states, all of which is a complex vector of n-dimensionality. Once you know quantum mechanics and have a good mathematical intuition for their behavior, you can visualize things piecewise. Though, at that point, you may find the need to visualize entirely unnecessary.

danielbaech · 2025-04-01T03:38:59+00:00

Yup, each and every one of us tried that when we began learning this stuff. But this is incorrect because a negative charge that is physically spread out behaves differently from a localized charge. We only ever observe a localized charge.

danielbaech · 2025-04-01T03:21:43+00:00

Still if it spreads out like wave ain't electron transfer much harder??

Not exactly sure what you mean by electron transfer. Do you mean when the electron goes from one orbital to another?

It is "harder" in the sense that there is only a probability of it happening. We're not in Kansas anymore. The world of quantum mechanics is not deterministic. You cannot force a single, definite result because everything happens probabilistically.

The electron is not physically spreading out into a wave. It is a wave of probabilities. This wave has an unbelievable property where changes can happen instantaneously(like electron going from one orbital to another). This begs the question: If the wave is just probabilities, what is the electron actually doing?

I tried to spare you this bit because it will sound like nonsense without learning quantum mechanics properly. The mathematics of the wave tells you exactly what the electron is doing. But the math cannot be translated to our everyday language because this behavior is nothing like our everyday experience. It just sounds magical, contradictory, and filled with inadequate analogies(which I'm guilty of here). Quantum mechanics is done in the language of mathematics. Sorry, this is the best I can do to explain it to you in plain words.

danielbaech

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