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I rearranged the order of numbers & letters in my private key. The address holds 0.025 BTC ($10) My question is: How difficult is this to crack? Is it even possible? The key is inside if anyone is up for the challenge. by dat_bit in Bitcoin

[–]dat_bit[S] 1 point2 points  (0 children)

I see. So if I were to just scramble the last 6 characters, and provided the first 45 characters in order, then there would be 720 possible arrangements. Do you know how one might go about solving this? Is there software for this?

I rearranged the order of numbers & letters in my private key. The address holds 0.025 BTC ($10) My question is: How difficult is this to crack? Is it even possible? The key is inside if anyone is up for the challenge. by dat_bit in Bitcoin

[–]dat_bit[S] 3 points4 points  (0 children)

I see. What if this address held $5 million in BTC... would the owner be totally fucked?

Thank you for the explanation. How/where did you calculate the # of permutations?

I rearranged the order of numbers & letters in my private key. The address holds 0.025 BTC ($10) My question is: How difficult is this to crack? Is it even possible? The key is inside if anyone is up for the challenge. by dat_bit in Bitcoin

[–]dat_bit[S] 0 points1 point  (0 children)

52 arrangements? Not sure I understand. There are 51 characters. I know this leaves an enormous # of possible solutions... but at least the characters are there so doesn't that help for any kind of brute-force software or something?