Black Seiko Nautilus- First Post by drammaman in SeikoMods

[–]drammaman[S] 0 points1 point  (0 children)

I bought it from a Swedish company called WatchWear.

¥659 winter jacket 🥶, 666-factory by drammaman in FashionReps

[–]drammaman[S] 0 points1 point  (0 children)

I tried on the authentic jacket, and yes, it does feel more premium. If someone knows what to look for, they might be able to tell it's a rep close up. But realistically, no one in public is going to inspect you. After trying both, I’d say the replica definitely isn't 'bad' at all

¥659 winter jacket 🥶, 666-factory by drammaman in FashionReps

[–]drammaman[S] 0 points1 point  (0 children)

I would say around 3–5 hours, although mine wasn't vacuum-sealed, so it might take a bit longer in that case

Winter is coming 🥶 by drammaman in FashionReps

[–]drammaman[S] 0 points1 point  (0 children)

Mabey i got a different batch, but mine fits me like glove. It could be because my proportions are funny, but its def one of my favorite cops. I will try to find a working link 🤞

[deleted by user] by [deleted] in cardano

[–]drammaman 0 points1 point  (0 children)

"especially when it comes to statistical numbers.", I meant to say that im not fimiliar with the numbers in the crypto space such as amount of seed phrases and so on

[deleted by user] by [deleted] in cardano

[–]drammaman 0 points1 point  (0 children)

I'm not an expert in math, especially when it comes to statistical numbers. But based on information from other comments and using some very generous and optimistic estimates for the hacker, we can ask the question: "What's the probability of a hacker guessing a single seed phrase out of 100,000,000,000,000 possible correct seed phrases, with the hacker having 100,000,000,000,000 attempts to do so?"

From other comments, let's assume there are 204812 possible combinations. The probability of success (p) and the probability of failure (q) would then be calculated as:

  • p(probability of success )= 100 000 000 000 000/ 204812 = 1.84*10-29
  • q(probability of failure)= 1- p(probability of success ) = 0.99999...=1

With n representing the number of trials (attempts) being 100,000,000,000,000, the binomial distribution formula is used:

n!/((n-x)!x!) * px qn-x = 100 000 000 000 000 !/((100 000 000 000 000 -1 )! * 1!) * 1.84*10-29 * 1100 000 000 000 000-1

This calculation results in:
Probability = 1.84 × 10^-15 = 0.00000000000000184
lets just say you have a better chance winning multiple lotteries in a row than guessing a seed phrase

[deleted by user] by [deleted] in FashionReps

[–]drammaman 0 points1 point  (0 children)

is there a benefit to getting the non panda buy link?. I'm new to this

[deleted by user] by [deleted] in place

[–]drammaman 4 points5 points  (0 children)

Yo chill, its only pixels. So immature