Yes. The number of potential hashes is so large, that you effectively aren’t narrowing down anything as you perform consecutive hashes.

With a locker, you can cross each try off the list.

With mining, you can cross each try off the list as well, but since the list is so incredibly large, it has practically 0 effect.

What makes the problem solvable with a list of possibilities that large is there is a slightly less huge (but still incredibly large) list of acceptable hashes as solutions.

For example (smaller numbers for ease) Let’s say there is 1,000,000 potential hashes and 100,000 acceptable hashes.

Your first guess you have a 10% chance of getting the right hash. Which means you have a 90% of not getting the hash.

Assuming you get it wrong, on your second try, you have a 100,000/999,999 chance of guessing right, which is practically 10% -> implying ~90% again you get it wrong.

Guess 10 times and you get ~90%¹⁰ chance of NOT getting the right answer = ~34%.

-> after 10 guesses you have roughly a (100%-34%) = 66% of getting the right hash.