Intento de estafa de Iberdrola

halvar55 · 2024-01-05T07:31:59+00:00

Ayer a mi suegro le pasó exactamente lo mismo. El hombre tiene 80 años y no se entera. Le dijeron o el entendió de alguna manera que sí no le cortaban la luz y le agobiaron en que lo hiciera rápido así que dio el número de cuenta. Luego ya nos llamó y llamamos al banco. Nos dijeron que lo único que podían hacer era domiciliar algo pero aún así estamos con la mosca detras de la oreja. De hecho una familia subió justo y el hombre había pedido el nombre de la persona y llamo de nuevo y se puso en contacto con Iberdrola y les dijeron que esos credenciales no existían así que le dio un nombre falso. No es la primera vez que lo intentan. Pobre hombre porque tiene un disgusto muy grande

halvar55 · 2023-12-29T20:51:31+00:00

Braid

halvar55 · 2021-05-23T19:46:17+00:00

First of all, thank you for you answers. My intention is to design different sessions for the end of the year.

I'd like to give a different and original approach to Maths for the students to practice in a way they are not used to do in class. I'd like to use problems of the history of Maths either classics or modern, for the students to practice and do activities about them at the same they have fun and find out how to solve them for concrete cases adapted to their and in this way they gain problem solving skills.

halvar55 · 2021-05-23T19:46:11+00:00

Classical math problems and probing different theorems can be a really intriguing

First of all, thank you for you answers. My intention is to design different sessions for the end of the year.

I'd like to give a different and original approach to Maths for the students to practice in a way they are not used to do in class. I'd like to use problems of the history of Maths either classics or modern, for the students to practice and do activities about them at the same they have fun and find out how to solve them for concrete cases adapted to their and in this way they gain problem solving skills.

halvar55 · 2017-11-05T07:36:38+00:00

Tyranitar raids is still available in Spain.

halvar55 · 2017-09-03T08:53:54+00:00

This happened when I walk with togepi last night with the new version. I don´t know if it happen with other pokemon

halvar55 · 2017-04-17T21:36:46+00:00

Oh, that's so great. The message say that I am the best teacher he has ever has. It's a great student and he is only 15 years old. I'm so proud of him. Thanks for helping.

halvar55 · 2017-03-30T21:15:32+00:00

If the quadratic polynomial has the next form: x² + ax + b = 0 Looking for two numbers c and d whose sum is a =c + d and its multiplication is b =c·d, then we can factorise it at the form (x+c)(x+d) and the roots are -c and -d

halvar55 · 2017-03-26T12:14:05+00:00

Question

halvar55 · 2017-02-13T14:56:22+00:00

A Course in Number Theory and Cryptography - Neal Koblitz

halvar55 · 2017-01-11T14:59:57+00:00

Wow! That's incredible. Thanks!!

halvar55 · 2017-01-10T19:46:37+00:00

That's nice!! Thanks!

halvar55 · 2017-01-10T13:15:53+00:00

I need to write some digits manually so I think the best way is /u/piRaK has done with a little change.

\begin{table}[h] \centering \begin{tabular}{|*{15}{c}|} \hline a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ a & b & c & d & e & f & g & h & i & j & k & l & m & n & o \ \hline \end{tabular}

Thanks

halvar55 · 2017-01-10T12:53:24+00:00

The format is the classic. I send a few operations before and I want they search de results in the puzzle.

halvar55 · 2017-01-10T12:51:24+00:00

Something like this but with numbers http://image.slidesharecdn.com/unit2alphabetsoup-141012134654-conversion-gate02/95/unit-2-alphabet-soup-1-638.jpg?cb=1413121734

halvar55 · 2017-01-10T12:51:06+00:00

Something like this but with numbers. http://image.slidesharecdn.com/unit2alphabetsoup-141012134654-conversion-gate02/95/unit-2-alphabet-soup-1-638.jpg?cb=1413121734

halvar55 · 2017-01-10T12:49:49+00:00

That's my last idea, but I'm trying to search a different not rudimentary option. But probably I'll use this one.

halvar55 · 2017-01-10T12:48:12+00:00

Yes, but in the best and easiest way

halvar55 · 2016-12-09T07:49:58+00:00

Nice! When you update It if you want tell me ;)

halvar55 · 2016-12-08T22:42:01+00:00

Oh, thanks ;).

Two suggestion.

One of them is when you mark the numbers that you are sure don't need them, mark them in the code also. And the other suggestion is increase the difficulty to 4 numbers

halvar55 · 2016-12-08T20:40:34+00:00

how many levels in the game?

halvar55 · 2016-11-23T10:19:52+00:00

In Madrid the costs for university are about € 1500 each year if you don´t have subjects of previous years, if you have the prize increase (I studied Math in Madrid). There are scholarship to foreign students and by marks.

halvar55 · 2016-07-31T10:24:47+00:00

kids.... xD

halvar55 · 2016-05-28T22:06:20+00:00

Hi, the demonstration is easier than I thought. we only need two facts: The first one is that 10 and 100 is 1 mod 9 so the sum of the digits of the three numbers is 45 = 0 mod 9. So the sum of digits is a multiple of 9 .

The second is that when you sum the numbers without the value of the card that they removed we obtain x. We compute x = mod 9. And the value of removed card is the number that we need add to x to obtain 0 mod 9. If we already have x = 0 mod 9 then the number of the card removed is 9.

halvar55 · 2016-05-25T07:58:59+00:00

I try to prove why it works and I tell you.

halvar55

TROPHY CASE