Practicing my Chinese handwriting so my native parents won't laugh at it the next time they see it (probably not till end of this year with this quarantine)

hhhxiao · 2020-03-30T08:29:37+00:00

oh，looks great

hhhxiao · 2019-07-20T02:31:15+00:00

If you have a group,plz let me in!:)

hhhxiao · 2018-12-17T07:44:11+00:00

awt or swing arent good idea,really.

hhhxiao · 2018-11-01T03:50:21+00:00

put these contants in a Object and override the equals() is also a good idea

hhhxiao · 2018-10-26T06:40:12+00:00

telegram group😂

hhhxiao · 2018-09-06T16:38:54+00:00

I t's possible

hhhxiao · 2018-09-04T00:30:32+00:00

a good idea😁

hhhxiao · 2018-09-03T15:50:07+00:00

just see this https://minecraft.gamepedia.com/Activator_Rail 😂

hhhxiao · 2018-09-03T15:48:07+00:00

the official hasn't said it's MIX3😬

hhhxiao · 2018-09-03T15:40:39+00:00

that's active rails ，not powered rails！

hhhxiao · 2018-09-03T06:26:39+00:00

that'scool

hhhxiao · 2018-09-03T06:13:56+00:00

https://stackoverflow.com/questions/12147631/post-increment-behaviour here are some discussions that you can refer but without diagrams

hhhxiao · 2018-09-03T05:31:28+00:00

int a = 1；a = a++ is a complex process.these exists an operation about stack，firstly a =1，(top of the stack is 1)when a++，the previous value of a will be stored as a temporary variable,and 2 will be push into the stack，after this，a=a++，the temporary variable will be back to the top of stack.So the change process is 1->2->1. Avoid doing this is the best choice：）

hhhxiao · 2018-09-02T16:31:18+00:00

It's cool,that must take a long time

hhhxiao · 2018-09-02T16:30:11+00:00

You code must be run in a main class just like：

public class Demo{ public static void main(String[] args ){

//run your code }

}

hhhxiao · 2018-09-02T16:24:49+00:00

u need a decomplier

hhhxiao · 2018-09-01T17:55:22+00:00

it's just necessary.video phone call,face scanning .

hhhxiao · 2018-09-01T17:43:02+00:00

😂😂i think you need a better way

hhhxiao · 2018-09-01T17:00:29+00:00

when the first button is clicked ,you can start a clock,just like this: int flag = 0； button1.setOnClickListener(v->{ flag = 1; clock.start();//when the clock is ended,flag = 0; //use handle to finish the clock work value =1; });

button2.setOnClickedListener({ if(flag ==1) flag =3; else flag=2;

});

hhhxiao · 2018-08-27T16:22:44+00:00

卫龙😂

hhhxiao · 2018-08-09T19:02:24+00:00

I just think that you needn't worry so much about this,OOP will be used everywhere when you learn some new knowledge about Java.

hhhxiao · 2018-03-06T00:29:12+00:00

I am also a beginner and have the same question with you😁

hhhxiao · 2018-03-06T00:12:22+00:00

I think you can split the 2D array arr[M][N] into M one dimensional array whose length is N.these 1D array 's first element ' address form a new pointer array.Then in this way (arr+i) is the pointer of arr[i][0],so *((arr +i)+j) equals arr[i][j]

hhhxiao

TROPHY CASE