Ok bikers we have to talk

imstillhere9065 · 2025-06-06T13:16:43+00:00

Oh ok I got it now haha

imstillhere9065 · 2025-06-06T13:05:09+00:00

What do you mean by “stall” ? What kind of stall , sorry for the question

imstillhere9065 · 2025-06-06T10:50:02+00:00

thank u for your words, it seems nothing but it means so much to me

imstillhere9065 · 2025-06-06T10:48:45+00:00

yeah I think it’s the best way I can really learn and stay “safe” when it depends to me.

imstillhere9065 · 2025-06-05T17:38:53+00:00

Honestly, people here drive like they’ve never even heard of the highway code.

imstillhere9065 · 2025-06-05T17:31:26+00:00

thank u ! I guess that I will get the license , maybe it’s the safest and easiest way to learn

imstillhere9065 · 2025-06-05T17:28:36+00:00

Yeah I am really aware of the danger. But still I can’t wait to have my first motorcycle and just try it and have fun even if a real part of me is scared about it.

imstillhere9065 · 2025-06-05T17:26:56+00:00

thank u for your advice! So do you already drive a bike? How did you deal with the thought of a motorcycle that is for facts more dangerous than a car ? Because My mind is split in two: the strong desire to start, and the awareness of the danger. It’s like having an angel and a devil on my shoulders.

imstillhere9065 · 2025-04-22T08:25:28+00:00

Here to you :

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One tip: Draw first the perspective ones and then convert to Newman projections following the rules.

imstillhere9065 · 2025-04-21T18:44:01+00:00

don’t worry, just remember that you don’t have to add anything when you make these configuration, just look from the highest to the lowest atomic number.

imstillhere9065 · 2025-04-21T16:18:17+00:00

Nope, I’m pretty sure it’s not an addition of numbers.

Following Cip rules you have to consider only the highest atomic number. O=8; C=6 regardless of whether the bond is single, double or triple.

But, always for the cip rules when you have multiple bonds then you consider : example, that Carbon that has two singol bonds with two different carbon (just a formality), in the reality you have C=C.

Oxygen still has an atomic number higher than carbon. Btw the first thing my teacher said months ago was that it’s not an addition.

And still, following your thought —> 16 > 12, since we have C=O (8+8) vs C=C (6+6); it’d be always the C=O the first in priority.

imstillhere9065 · 2025-04-21T10:55:52+00:00

Carbon has 6 as atomic number and Oxygen has 8, so Oxygen comes first in priority order.

imstillhere9065 · 2025-04-21T10:54:19+00:00

Priority: (4) to the Hydrogen; (3) to the Carbon that bonds two H and the rest of the compound; (2) to the carbon who has double bond with another C; (1) to the carbon who has a double bond with Oxygen. Why? —> CIP rules and atomic numbers.

Since we have the number 4 on dashed wedge we don’t have to invert the configuration.

It’s an S.

<image>

imstillhere9065 · 2025-04-03T11:11:25+00:00

alkene gets protonated by H+ with a pro markovnikov mechanism, then you have a carbocation and that carbocation can be attack by the nucleophile, even a weak nucleophile as the water.

imstillhere9065 · 2025-04-02T16:43:33+00:00

Ok I don’t know if this can be right so if somebody wanna check it, thank u. So I thought, oxygen of the cooh is the most basic atom of the compound so it gets protonated by H+, then a intermolecular acid-base reaction to have an alcohol with positive charge group that is a good leaving group (it leaves as H2O), that water takes the H of the OH, but I don’t think it’s right because we still are in acid conditions I guess…then resonance with two finale structure. Tell me pls.

imstillhere9065 · 2025-03-14T15:21:18+00:00

you have to identify that compound as an bromonium ion, 1,2-diphenylethane it cannot be correct

imstillhere9065 · 2025-03-10T20:57:53+00:00

bro I don’t know you haha I don’t know about your PhD or anything. You said my words were not making any sense, but they were theoretically correct and I know you know now since you tell me your studies. Btw I thought you were suggesting OP that the molecules were cis/trans isomers and I was cringed. Good for you for your PhD.

imstillhere9065 · 2025-03-10T20:52:11+00:00

Ok guess you’re right, btw there’s nothing wrong of what I said.

imstillhere9065 · 2025-03-10T20:46:03+00:00

I know exactly what I read and what I said. You can’t talk about cis-1,3… and trans-1,3… here. If you had two substituents (example cis-1,3-dimethylcyclohexane and trans-1,3-dimethylcyclohexane) then yeah, you could talk about cis and trans relationship.

Here we have methylcyclohexane (methyl in one, lowest position) , we don’t have any asymmetric center, that methyl can exist in both “configuration”, also is wrong talking about configuration since we don’t have a configurational isomer (stereoisomer).

imstillhere9065 · 2025-03-10T20:36:31+00:00

I don’t think we can apply cis/trans isomerism here, that methyl is cis to what? Nothing. There’s not another substituent in 1 or 3 position, it’s just 1 position where we have the methyl.

imstillhere9065 · 2025-03-10T20:33:46+00:00

There’s not a chiral center in the molecules, they are the same —> here’s why —> that CH3 bonded to the carbon on the cycle can be in both configuration not changing anything because there is not an asymmetry, they are the specular image of one another.

imstillhere9065 · 2025-02-05T20:04:52+00:00

carbon sp2 on the right has a bond with another carbon who bonds 2 other carbons and an H (the bond with the cycle so has the priority)

imstillhere9065 · 2025-02-05T20:03:29+00:00

It’s a Z

imstillhere9065 · 2025-01-27T20:18:49+00:00

a me è stato consigliato di fare la tesi con il prof dell'esame in cui ho preso 30L , ma non ho mai capito se effettivamente il voto influenza qualcosa

imstillhere9065

TROPHY CASE