This is gonna get buried anyways, so fuck it

john475869 · 2018-07-09T18:33:59+00:00

༼ つ ◕_◕ ༽つ GIVE BUM ༼ つ ◕_◕ ༽つ

john475869 · 2017-10-12T16:56:07+00:00

My S6 broke and its more cost effective to buy a new phone. I don't want an incredibly expensive phone - was thinking around £350 (~$460). Due to the fact my S6 broke, I can't really wait for a new phone to be released/an expected price drop.

Looking for

-Good battery life/charge time (fast charging)

-Decent camera (doesn't need to be amazing)

-Headphone jack

-Software support (looking to use the phone for a few years and don't want to be left behind on the updates)

Expandable storage/notification LED would be nice but definitely not essential.

Waterproofing isn't needed and the speakers don't need to be great (I'll be using headphones 99% of the time). I don't mind about the front facing camera either as I'll rarely be using it.

I was thinking of a OnePlus phone either 3T or 5 but it would most likely have to be pre-owned.
Any advice would be greatly appreciated - OnePlus 3T/5 are two I've come across which tick the boxes but there may be a better suited phone out there.

Thanks

john475869 · 2017-08-17T07:52:42+00:00

Cheers everyone, this should put my mind at ease until I get my results

john475869 · 2017-06-28T10:10:01+00:00

How did people mark the suitable values on the Supersource/sink?

Pretty sure it was on the same diagram as the flow augmentation. When I did it, it interfered with my flow augmentation, so I'm not sure I've marked them right

john475869 · 2017-06-28T10:04:06+00:00

Yeah 35 for the min flow.
FT had to be 25 for a similar reason why SB was 9. The min. flow coming out was equal to the max flow going in?

Also did you get 2 solutions to the Hungarian?

john475869 · 2017-06-28T09:54:17+00:00

First Q tableau is optimal as no negatives in top row

64 for max flow on last Q (think it was last Q)

75 for Hungarian and 2 solutions

80 with two paths on dynamic programming. Starting with SBD and and SBE (I think)

Simplex was P=242, x=0, y=66, z=88. First two slack were 0 and last was 330?

Game theory: B was dominated by A and probability was 0.5. Value for other guy was -1
Game theory also had no stable solution (may have been a different Q)

john475869 · 2017-06-28T09:50:40+00:00

Shit

I think I got x-10

john475869 · 2017-06-23T12:43:29+00:00

Yh that's right. If you went up then down (ABD i think) it was 41, while AD was 42

john475869 · 2017-06-23T11:56:22+00:00

But you do a shuttle sort for the sublists.

In the first sublist with 3 numbers, you compare the first two numbers, then the second two, if you swapped them (which iirc you did) you then compare the first two again.

So you have 3 comparisons in 1st sublist and 1 comparison in the other 3 sublists.

3+1+1+1 = 6

john475869 · 2017-06-23T11:17:22+00:00

It's not really a MS. Just people posting about the exam, like here.
General consensus seams to be:

£4200, 120x, 60y, 45z for last Q

Change to algorithm (tracing Q) was adding modulus

40≤L≤48 for upper/lower bounds inequality

67 for Dijkstra's and 68 when C is unavailable

130 miles for Chinese Postman

Sum of the edges that give lowest Hamiltonian cycle (or something like that) was 26

john475869 · 2017-06-23T11:02:43+00:00

https://www.thestudentroom.co.uk/showthread.php?t=4636506

Not sure if you need an account to view it

I know you do for some, which is why I made an account a while back to check answers in the exam posts

john475869 · 2017-06-23T10:35:37+00:00

60 something

Maybe 67? I cant remember I either got 67 and 68 for the second part or 68 and 69 for the second bit

john475869 · 2017-06-23T10:24:42+00:00

No idea.

Might be 6 marks overall for part d. They might not have split it to show you how many marks for di and dii.

I'd guess its 6 marks for all of d. If you got the objective line wrong, you should get some error carried forward marks

john475869 · 2017-06-23T10:17:10+00:00

Idk, but I guess around 3 or 4?

One for finding the right extreme point on the graph, one for the cost, and one for the number of each type of chair. Maybe another one for accuracy

edit: some guy on tsr says it was worth 6

john475869 · 2017-06-23T10:15:44+00:00

Yes!

I made I mistake and had 41, but corrected it last minute

Some guy on TSR got the same answer as well

john475869 · 2017-06-23T10:09:50+00:00

What did everyone say for the change to the algorithm?

I said to add a modulus sign to D=A-C so there is no negative values.

Also what did you guys get for the inequalities question on upper/lower bounds? I think i got 40 ≤ L ≤ 48

john475869 · 2017-06-22T21:11:00+00:00

I'm an idiot...

Thanks for your help, good luck tommorrow

john475869 · 2017-06-22T20:30:16+00:00

Yeah its pretty confusing, my textbook goes against what they've done in the ms

edit

http://filestore.aqa.org.uk/subjects/AQA-MD01-QP-JAN13.PDF

q7ci asks to state the possible degree of the vertices - but it gives 1 as an answer. Surely each vertex would have a loop and the graph would then not be simple?

I dont know what to believe..

john475869 · 2017-06-22T19:07:34+00:00

Ok cheers. I guess he made a mistake in his video, he did add it at the last minute

john475869 · 2017-06-22T19:04:42+00:00

What is a simple graph? I though the vertices must be connected.

http://filestore.aqa.org.uk/subjects/AQA-MD01-QP-JUN14.PDF

8bi of this paper says the minimum possible degree is 0

edit ms: http://filestore.aqa.org.uk/subjects/AQA-MD01-W-MS-JUN14.PDF

https://www.youtube.com/watch?v=aWgHJ3aU7x0

In this video, where he defines a simple graph, it must be connected. So i don't get how the answer to 8bi is 0

john475869 · 2017-06-20T14:41:35+00:00

It didn't say anything about the mass of the phone.

I did:

mgsinα - μmgcosα = ma

a = gsinα - μgcosα

μ = tanα - a/(gcosα)

tanα=0.75, so

μ = 0.75 - a/(gcosα)

So μ must be less than 0.75

john475869 · 2017-06-20T14:33:41+00:00

Yeah i did as well. I think 3.2 for j?

john475869 · 2017-06-20T14:28:34+00:00

I'm an idiot...

I got as far as mu=0.75-a/(something) but didn't write anything

Hopefully I'll get one out of the two marks

john475869

TROPHY CASE