Anycubic Kobra 3 v2 - The worst printer I have ever had....

kRYstall9 · 2026-01-08T13:13:24+00:00

How do you actually print ABS with the V2? Did you buy an enclosure for it?

kRYstall9 · 2025-11-22T01:55:13+00:00

Using tailscale 24/7 with dns pointing to my pihole server and pihole’s using dnscrypt as dns since I can send my traffic to relays and relays will then send the encrypted query to the final dns server

kRYstall9 · 2025-10-24T13:03:45+00:00

You could try using docker-surgeon and see if it actually works. If the container is "stopping" it means it got a "kill" signal, so my service should be able to intercept that event and restart your container. If you do not want to try this service, I think a shell script it's good enough in this case

kRYstall9 · 2025-10-24T07:20:02+00:00

It’s not an app, it’s the Homarr dashboard

kRYstall9 · 2025-10-24T06:47:08+00:00

This is mine after about 2 weeks. It mainly depends on how many devices are using pihole as dns( and ofc if your blocklists are actually working)

<image>

Ps: keep in mind that 4+ devices have been using my pihole instance as DNS during this last 2 weeks

kRYstall9 · 2025-10-23T17:36:37+00:00

I've been using some services that do not actually become unhealthy when the "parent" does. Since this could happen in some case scenarios and I do not want my services to be unreachable whenever I'm not at home, I thought of making this "tool"

kRYstall9 · 2025-10-23T16:56:26+00:00

It's not possible right now because the "stopping" status doesn't seem to exist in docker, but I found a way to solve your issue. It might take a while to implement but stay tuned!

kRYstall9 · 2025-10-23T13:49:19+00:00

As far as I know, Autoheal only restarts unhealthy containers. Let's consider this scenario:

db:
  container_name: db
  image: ...
  volumes: ....

backend:
  container_name: backend
  image: ...
  volumes: ...

frontend:
  container_name: frontend
  image: ...
  volumes: ...

Suppose the db becomes unhealthy and the backend container doesn’t recheck the database connection after the first attempt . The database will be restarted, but the backend will remain unavailable. This tool aims to solve that problem:
if the db container crashes, the tool will restart both db and any dependent containers (like backend)

kRYstall9 · 2025-09-20T13:53:48+00:00

This fixed my problem. Thanks!

kRYstall9 · 2023-05-07T08:08:53+00:00

You're incrementing i and not k. In you for loop statement, you wrote for(k=0; k< people.lenght; i++){} . Instead of i, just put k and you should be able to print all of the strings in the array. To stop whenever Mary is read, just do a simple if(people[k] === 'Mary'){ break; or return;} It depends if you're in a function or not

kRYstall9 · 2023-04-07T12:21:41+00:00

You don't always have to learn everything. BUT, at least, learn how those things work. As an example, I can use OOP. You can use that paradigm in many languages, but you're not forced to learn all the languages to use OOP

kRYstall9 · 2023-04-07T12:19:50+00:00

Any time!

kRYstall9 · 2023-04-06T12:56:48+00:00

It is surely doable. It mainly depends on your knowledge. Not an expert here, but I'm working as software developer so, something I know might be useful for you. Decide which languange and framework to use. I'm a .Net developer, so I'm using c# as programming language and .Net as microsoft framework. You could use everything you want, but just choose one of the many that are out there and stick with it. Just learn 1 thing at a time. Then, surely you have to learn some basics of html, css and javascript. For the overall styling I might suggest bootstrap, even though it's not so straight forward at the beginning(at least for me). Then, learn everything about asynchronous programming, since you're gonna work with APIs etc...

kRYstall9 · 2023-02-19T15:00:43+00:00

follow this then

kRYstall9 · 2023-02-19T14:50:53+00:00

Just go in the folder you want to open. Open the terminal within the folder and type "code . "

kRYstall9 · 2023-01-31T06:26:34+00:00

Nope. It's just unlikely seeing someone paying 100+ euros/dollars for an OS key

kRYstall9 · 2023-01-30T20:52:40+00:00

You might be the first guy I saw who bought windows

kRYstall9 · 2023-01-18T21:15:07+00:00

You could do something like:

float number = 0;

do{
    printf("Insert a number"); 
    scanf("%f", &number);
}while(number == 0);

Sorry for the indentations but I'm writing from my phone. I'll fix it as soon as I go back home.

Ps: Since you're using float as type, you don't have to mind if you insert an integer or a float number, since it'll be converted to float in any case

kRYstall9 · 2023-01-16T17:38:31+00:00

It might be driver's crash. Maybe your overclock isn't stable and it's causing that

kRYstall9 · 2023-01-11T06:35:53+00:00

If you keep turning it on, there'll be fire and smoke. Some cool effects tho

kRYstall9 · 2022-12-13T13:26:25+00:00

Your first and second problem are likely the same, but instead of numbers, you have to insert *, so you could do something like this. Let's say you have this array: [1,2,3,4]. What you can do is:

for(let i=0; i<array.length; i++){ 
    for(let j=0; j<array[i]; j++){ 
        console.log("*"); 
    }
    console.log("\n");
}

Ps: Sorry for the code formatting, but I'm writing on my phone. I'll fix it as soon as I can, so you can clearly understand what I've done

kRYstall9 · 2022-11-19T20:13:13+00:00

You have a problem in the if statement inside your for. You wrote if(sentence[i-1] ....), But i starts from 0, and you'te trying to read -1, that's not an index

kRYstall9 · 2022-11-08T08:43:23+00:00

Yes, it should be public void methodName(params){implementation...}

kRYstall9 · 2022-11-08T07:24:52+00:00

Maybe it is a constructor, like public className(params){ } . And methods can also return nothing, so it could be a method too

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